下面是我一小步一小步完成的方法，类似于@Kirsteins。

func capitalizedPhrase(phrase:String) -> String {
    let firstCharIndex = advance(phrase.startIndex, 1)
    let firstChar = phrase.substringToIndex(firstCharIndex).uppercaseString
    let firstCharRange = phrase.startIndex..<firstCharIndex
    return phrase.stringByReplacingCharactersInRange(firstCharRange, withString: firstChar)
}

在Swift 3.0中(这比公认的答案更快更安全):

extension String {
    func firstCharacterUpperCase() -> String {
        if let firstCharacter = characters.first {
            return replacingCharacters(in: startIndex..<index(after: startIndex), with: String(firstCharacter).uppercased())
        }
        return ""
    }
}

nameOfString。大写是不行的，句子里的每个单词都要大写

如果你想大写字符串的每个字，你可以使用这个扩展

Swift 4 Xcode 9.2

extension String {
    var wordUppercased: String {
        var aryOfWord = self.split(separator: " ")
        aryOfWord =  aryOfWord.map({String($0.first!).uppercased() + $0.dropFirst()})
        return aryOfWord.joined(separator: " ")
    }
}

Used

print("simple text example".wordUppercased) //output:: "Simple Text Example"

Swift 3更新

replaceRange函数现在是replaceSubrange

nameOfString.replaceSubrange(nameOfString.startIndex...nameOfString.startIndex, with: String(nameOfString[nameOfString.startIndex]).capitalized)

下面是Swift 5的一个版本，如果第一个字母已经是大写，或者没有大小写的概念，使用Unicode标量属性API来保释:

extension String {
  func firstLetterUppercased() -> String {
    guard let first = first, first.isLowercase else { return self }
    return String(first).uppercased() + dropFirst()
  }
}

下面是我一小步一小步完成的方法，类似于@Kirsteins。

func capitalizedPhrase(phrase:String) -> String {
    let firstCharIndex = advance(phrase.startIndex, 1)
    let firstChar = phrase.substringToIndex(firstCharIndex).uppercaseString
    let firstCharRange = phrase.startIndex..<firstCharIndex
    return phrase.stringByReplacingCharactersInRange(firstCharRange, withString: firstChar)
}