Swift 2.0(单行):

String(nameOfString.characters.prefix(1)).uppercaseString + String(nameOfString.characters.dropFirst())

如果你想大写字符串的每个字，你可以使用这个扩展

Swift 4 Xcode 9.2

extension String {
    var wordUppercased: String {
        var aryOfWord = self.split(separator: " ")
        aryOfWord =  aryOfWord.map({String($0.first!).uppercased() + $0.dropFirst()})
        return aryOfWord.joined(separator: " ")
    }
}

Used

print("simple text example".wordUppercased) //output:: "Simple Text Example"

extension String {
    var lowercased:String {
        var result = Array<Character>(self.characters);
        if let first = result.first { result[0] = Character(String(first).uppercaseString) }
        return String(result)
    }
}

如果你的字符串都是大写，那么下面的方法将工作

labelTitle.text = remarks?.lowercased().firstUppercased

这个扩展将帮助你

extension StringProtocol {
    var firstUppercased: String {
        guard let first = first else { return "" }
        return String(first).uppercased() + dropFirst()
    }
}

Leonardo Savio Dabus:

我想大多数用例是获得适当的套管:

import Foundation

extension String {

    var toProper:String {
        var result = lowercaseString
        result.replaceRange(startIndex...startIndex, with: String(self[startIndex]).capitalizedString)
        return result
    }
}

下面是我一小步一小步完成的方法，类似于@Kirsteins。

func capitalizedPhrase(phrase:String) -> String {
    let firstCharIndex = advance(phrase.startIndex, 1)
    let firstChar = phrase.substringToIndex(firstCharIndex).uppercaseString
    let firstCharRange = phrase.startIndex..<firstCharIndex
    return phrase.stringByReplacingCharactersInRange(firstCharRange, withString: firstChar)
}