在Oracle中，你可以使用NULLS FIRST或NULLS LAST:指定NULL值应该在非NULL值之前或之后返回:

ORDER BY { column-Name | [ ASC | DESC ] | [ NULLS FIRST | NULLS LAST ] }

例如:

ORDER BY date DESC NULLS LAST

裁判:http://docs.oracle.com/javadb/10.8.3.0/ref/rrefsqlj13658.html

使用NVL函数

  select * from MyTable order by NVL(MyDate, to_date('1-1-1','DD-MM-YYYY'))

以下是最著名的DBMS中NVL的替代方案

我也偶然发现了这一点，以下似乎为我做的伎俩，在MySQL和PostgreSQL:

ORDER BY date IS NULL, date DESC

详见https://stackoverflow.com/a/7055259/496209

如果您正在使用MariaDB，它们会在NULL值中提到以下内容 文档。

Ordering When you order by a field that may contain NULL values, any NULLs are considered to have the lowest value. So ordering in DESC order will see the NULLs appearing last. To force NULLs to be regarded as highest values, one can add another column which has a higher value when the main field is NULL. Example: SELECT col1 FROM tab ORDER BY ISNULL(col1), col1; Descending order, with NULLs first: SELECT col1 FROM tab ORDER BY IF(col1 IS NULL, 0, 1), col1 DESC; All NULL values are also regarded as equivalent for the purposes of the DISTINCT and GROUP BY clauses.

上面显示了两种按NULL值排序的方法，您可以将它们与 ASC和DESC关键字。例如，另一种获取NULL值的方法 首先是:

SELECT col1 FROM tab ORDER BY ISNULL(col1) DESC, col1;
--                                         ^^^^

(“有点”晚了，但这一点根本没有被提及)

您没有指定您的DBMS。

在标准SQL(以及大多数现代DBMS，如Oracle, PostgreSQL, DB2, Firebird, Apache Derby, HSQLDB和H2)中，您可以指定NULLS LAST或NULLS FIRST:

使用NULLS LAST将它们排序到最后:

select *
from some_table
order by some_column DESC NULLS LAST

您可以使用内置函数检查null或非null，如下所示。我测试了它，它的工作良好。

select MyDate from MyTable order by ISNULL(MyDate,1)