目前我有一个Angular.js页面，允许搜索和显示结果。用户单击搜索结果，然后单击返回按钮。我想再次显示搜索结果，但我不知道如何触发搜索执行。细节如下:
My Angular.js page is a search page, with a search field and a search
button. The user can manually type in a query and press a button and
and ajax query is fired and the results are displayed. I update the URL with the search term. That all works fine.
User clicks on a result of the search and is taken to a different page - that works fine too.
User clicks back button, and goes back to my angular search page, and the correct URL is displayed, including the search term. All works fine.
I have bound the search field value to the search term in the URL, so it contains the expected search term. All works fine.
我如何让搜索功能再次执行，而不需要用户按下“搜索按钮”?如果是jquery，那么我会在documentready函数中执行一个函数。我找不到Angular.js的等价物。
当使用$routeProvider时，你可以解析.state并引导你的服务。也就是说，你要加载控制器和视图，只有在解析你的服务之后:
ui-routes
.state('nn', {
url: "/nn",
templateUrl: "views/home/n.html",
controller: 'nnCtrl',
resolve: {
initialised: function (ourBootstrapService, $q) {
var deferred = $q.defer();
ourBootstrapService.init().then(function(initialised) {
deferred.resolve(initialised);
});
return deferred.promise;
}
}
})
服务
function ourBootstrapService() {
function init(){
// this is what we need
}
}
一方面，正如@Mark-Rajcok所说，你可以使用私有内部函数:
// at the bottom of your controller
var init = function () {
// check if there is query in url
// and fire search in case its value is not empty
};
// and fire it after definition
init();
你也可以看看ng-init指令。实现将很像:
// register controller in html
<div data-ng-controller="myCtrl" data-ng-init="init()"></div>
// in controller
$scope.init = function () {
// check if there is query in url
// and fire search in case its value is not empty
};
但是要注意，因为angular文档暗示(从v1.2开始)不要使用ng-init。然而，在我看来，这取决于你的应用程序的架构。
当我想从后端传递一个值到angular app时，我使用了ng-init:
<div data-ng-controller="myCtrl" data-ng-init="init('%some_backend_value%')"></div>
