在Python中,我可以使用re.compile将正则表达式编译为不区分大小写:

>>> s = 'TeSt'
>>> casesensitive = re.compile('test')
>>> ignorecase = re.compile('test', re.IGNORECASE)
>>> 
>>> print casesensitive.match(s)
None
>>> print ignorecase.match(s)
<_sre.SRE_Match object at 0x02F0B608>

是否有一种方法可以做同样的事情,但不使用re.compile。我在文档中找不到任何类似Perl的I后缀(例如m/test/ I)的东西。


当前回答

#'re.IGNORECASE' for case insensitive results short form re.I
#'re.match' returns the first match located from the start of the string. 
#'re.search' returns location of the where the match is found 
#'re.compile' creates a regex object that can be used for multiple matches

 >>> s = r'TeSt'   
 >>> print (re.match(s, r'test123', re.I))
 <_sre.SRE_Match object; span=(0, 4), match='test'>
 # OR
 >>> pattern = re.compile(s, re.I)
 >>> print(pattern.match(r'test123'))
 <_sre.SRE_Match object; span=(0, 4), match='test'>

其他回答

#'re.IGNORECASE' for case insensitive results short form re.I
#'re.match' returns the first match located from the start of the string. 
#'re.search' returns location of the where the match is found 
#'re.compile' creates a regex object that can be used for multiple matches

 >>> s = r'TeSt'   
 >>> print (re.match(s, r'test123', re.I))
 <_sre.SRE_Match object; span=(0, 4), match='test'>
 # OR
 >>> pattern = re.compile(s, re.I)
 >>> print(pattern.match(r'test123'))
 <_sre.SRE_Match object; span=(0, 4), match='test'>

你也可以在模式编译时定义不区分大小写:

pattern = re.compile('FIle:/+(.*)', re.IGNORECASE)

(?i)用以下有效标志匹配模式的剩余部分:不区分大小写匹配(忽略[a-zA-Z]的大小写)

>>> import pandas as pd
>>> s = pd.DataFrame({ 'a': ["TeSt"] })
>>> r = s.replace(to_replace=r'(?i)test', value=r'TEST', regex=True)
>>> print(r)
      a
0  TEST

对于不区分大小写的正则表达式: 在代码中添加有两种方法:

旗帜=再保险。IGNORECASE Regx3GList = re.search(“(WCDMA) ((\ d *)(,?))*", txt re.IGNORECASE) 不区分大小写的标记(?i) Regx3GList = re.search(“* *(?我)* * (WCDMA:) ((\ d *)(,?))*", txt)

进口

import re

在运行时处理中:

RE_TEST = r'test'
if re.match(RE_TEST, 'TeSt', re.IGNORECASE):

应该提到的是,不使用re.compile是一种浪费。每次调用上述匹配方法时,正则表达式都将被编译。这在其他编程语言中也是错误的做法。下面是更好的实践。

在应用程序初始化中:

self.RE_TEST = re.compile('test', re.IGNORECASE)

在运行时处理中:

if self.RE_TEST.match('TeSt'):