我得到了一个AsyncTask,应该检查对主机名的网络访问。但是doInBackground()永远不会超时。有人知道吗?

public class HostAvailabilityTask extends AsyncTask<String, Void, Boolean> {

    private Main main;

    public HostAvailabilityTask(Main main) {
        this.main = main;
    }

    protected Boolean doInBackground(String... params) {
        Main.Log("doInBackground() isHostAvailable():"+params[0]);

        try {
            return InetAddress.getByName(params[0]).isReachable(30); 
        } catch (UnknownHostException e) {
            e.printStackTrace();
        } catch (IOException e) {
            e.printStackTrace();
        }
        return false;       
    }

    protected void onPostExecute(Boolean... result) {
        Main.Log("onPostExecute()");

        if(result[0] == false) {
            main.setContentView(R.layout.splash);
            return;
        }

        main.continueAfterHostCheck();
    }   
}

当前回答

有不止一种编码方式真是太棒了。 下面是我的例子。

ConnectivityManager icheck = getSystemService(Context.CONNECTIVITY_SERVICE);

TextView tv = findViewById(R.id.textView1);

boolean wifi = icheck.getActiveNetworkInfo() != null;
        if(wifi) {
        tv.setText("Internet is on.");  
        } else {
             tv.setText("Internet is off.");    
        }

祝你好运。

其他回答

我使用这段代码而不是InetAddress:

    try {

        URL url = new URL("http://"+params[0]);

        HttpURLConnection urlc = (HttpURLConnection) url.openConnection();
        urlc.setRequestProperty("User-Agent", "Android Application:"+Z.APP_VERSION);
        urlc.setRequestProperty("Connection", "close");
        urlc.setConnectTimeout(1000 * 30); // mTimeout is in seconds
        urlc.connect();
        if (urlc.getResponseCode() == 200) {
            Main.Log("getResponseCode == 200");
            return new Boolean(true);
        }
    } catch (MalformedURLException e1) {
        // TODO Auto-generated catch block
        e1.printStackTrace();
    } catch (IOException e) {
        // TODO Auto-generated catch block
        e.printStackTrace();
    }

非常重要的是检查我们是否与isAvailable()有连接,以及是否可能与isConnected()建立连接

private static ConnectivityManager manager;

public static boolean isOnline(Context context) {
    ConnectivityManager connectivityManager = (ConnectivityManager) context.getSystemService(Context.CONNECTIVITY_SERVICE);
    NetworkInfo networkInfo = connectivityManager.getActiveNetworkInfo();
    return networkInfo != null && networkInfo.isAvailable() && networkInfo.isConnected();
}

你可以取消网络活动WiFi的类型:

public static boolean isConnectedWifi(Context context) {
    ConnectivityManager connectivityManager = (ConnectivityManager) context.getSystemService(Context.CONNECTIVITY_SERVICE);
    NetworkInfo networkInfo = connectivityManager.getActiveNetworkInfo();
    return networkInfo != null && networkInfo.getType() == ConnectivityManager.TYPE_WIFI;
}

或手机Móvil:

public static boolean isConnectedMobile(Context context) {
    ConnectivityManager connectivityManager = (ConnectivityManager) context.getSystemService(Context.CONNECTIVITY_SERVICE);
    NetworkInfo networkInfo = connectivityManager.getActiveNetworkInfo();
    return networkInfo != null && networkInfo.getType() == ConnectivityManager.TYPE_MOBILE;
}

不要忘记权限:

    <uses-permission android:name="android.permission.ACCESS_NETWORK_STATE" />
   <uses-permission android:name="android.permission.INTERNET" />

我已经应用了@Levit提供的解决方案,并创建了不会调用额外Http请求的函数。

它将解决无法解析主机的错误

public static boolean isInternetAvailable(Context context) {
    ConnectivityManager cm = (ConnectivityManager) context.getSystemService(Context.CONNECTIVITY_SERVICE);
    NetworkInfo activeNetwork = cm.getActiveNetworkInfo();
    if (activeNetwork == null) return false;

    switch (activeNetwork.getType()) {
        case ConnectivityManager.TYPE_WIFI:
            if ((activeNetwork.getState() == NetworkInfo.State.CONNECTED ||
                    activeNetwork.getState() == NetworkInfo.State.CONNECTING) &&
                    isInternet())
                return true;
            break;
        case ConnectivityManager.TYPE_MOBILE:
            if ((activeNetwork.getState() == NetworkInfo.State.CONNECTED ||
                    activeNetwork.getState() == NetworkInfo.State.CONNECTING) &&
                    isInternet())
                return true;
            break;
        default:
            return false;
    }
    return false;
}

private static boolean isInternet() {

    Runtime runtime = Runtime.getRuntime();
    try {
        Process ipProcess = runtime.exec("/system/bin/ping -c 1 8.8.8.8");
        int exitValue = ipProcess.waitFor();
        Debug.i(exitValue + "");
        return (exitValue == 0);
    } catch (IOException | InterruptedException e) {
        e.printStackTrace();
    }

    return false;
}

现在叫它,

if (!isInternetAvailable(getActivity())) {
     //Show message
} else {
     //Perfoem the api request
}

这对我很有用。试试吧。

public void onCreate(Bundle savedInstanceState) {
    super.onCreate(savedInstanceState);
    setContentView(R.layout.main);
    try {
        URL url = new URL("http://stackoverflow.com/posts/11642475/edit" );
        //URL url = new URL("http://www.nofoundwebsite.com/" );
        executeReq(url);
        Toast.makeText(getApplicationContext(), "Webpage is available!", Toast.LENGTH_SHORT).show();
    }
    catch(Exception e) {
        Toast.makeText(getApplicationContext(), "oops! webpage is not available!", Toast.LENGTH_SHORT).show();
    }
}

private void executeReq(URL urlObject) throws IOException
{
    HttpURLConnection conn = null;
    conn = (HttpURLConnection) urlObject.openConnection();
    conn.setReadTimeout(30000);//milliseconds
    conn.setConnectTimeout(3500);//milliseconds
    conn.setRequestMethod("GET");
    conn.setDoInput(true);

    // Start connect
    conn.connect();
    InputStream response =conn.getInputStream();
    Log.d("Response:", response.toString());
}}

更新29/06/2015 如果你正在使用Xamarin。Android和想要检查连接,你可以使用Nuget包,这将给你在多个平台上的功能。好的候选人在这里和这里。 [更新结束]

The Answers above are quite good, but they are all in Java, and almost all of them check for a connectivity. In my case, I needed to have connectivity with a specific type of connection and I am developing on Xamarin.Android. Moreover, I do not pass a reference to my activities Context in the Hardware layer, I use the Application Context. So here is my solution, in case somebody comes here with similar requirements. I have not done full testing though, will update the answer once I am done with my testing

using Android.App;
using Android.Content;
using Android.Net;

namespace Leopard.Mobile.Hal.Android
{
    public class AndroidNetworkHelper
    {
        public static AndroidNetworkStatus GetWifiConnectivityStatus()
        {
            return GetConnectivityStatus(ConnectivityType.Wifi);
        }

        public static AndroidNetworkStatus GetMobileConnectivityStatus()
        {
            return GetConnectivityStatus(ConnectivityType.Mobile);
        }

        #region Implementation

        private static AndroidNetworkStatus GetConnectivityStatus(ConnectivityType connectivityType)
        {
            var connectivityManager = (ConnectivityManager)Application.Context.GetSystemService(Context.ConnectivityService);
            var wifiNetworkInfo = connectivityManager.GetNetworkInfo(connectivityType);
            var result = GetNetworkStatus(wifiNetworkInfo);
            return result;
        }

        private static AndroidNetworkStatus GetNetworkStatus(NetworkInfo wifiNetworkInfo)
        {
            var result = AndroidNetworkStatus.Unknown;
            if (wifiNetworkInfo != null)
            {
                if (wifiNetworkInfo.IsAvailable && wifiNetworkInfo.IsConnected)
                {
                    result = AndroidNetworkStatus.Connected;
                }
                else
                {
                    result = AndroidNetworkStatus.Disconnected;
                }
            }
            return result;
        } 

        #endregion
    }

    public enum AndroidNetworkStatus
    {
        Connected,
        Disconnected,
        Unknown
    }