我有一个getter从cookie中获取值。

现在我有了两个cookie,名字分别是shares=和obligation =。

我想让这个getter只从义务cookie中获取值。

我怎么做呢?因此for语句将数据拆分为单独的值,并将其放入数组中。

 function getCookie1() {
    // What do I have to add here to look only in the "obligations=" cookie? 
    // Because now it searches all the cookies.

    var elements = document.cookie.split('=');
    var obligations= elements[1].split('%');
    for (var i = 0; i < obligations.length - 1; i++) {
        var tmp = obligations[i].split('$');
        addProduct1(tmp[0], tmp[1], tmp[2], tmp[3]);
    }
 }

当前回答

如果你使用jQuery,我建议你使用这个插件:

https://github.com/carhartl/jquery-cookie https://github.com/carhartl/jquery-cookie/blob/master/jquery.cookie.js

<script type="text/javascript"
 src="//cdnjs.cloudflare.com/ajax/libs/jquery-cookie/1.4.1/jquery.cookie.min.js">

所以你可以这样读cookie:

var value = $.cookie("obligations");

你也可以写cookie:

$.cookie('obligations', 'new_value');
$.cookie('obligations', 'new_value', { expires: 14, path: '/' });

删除cookie:

$.removeCookie('obligations');

其他回答

我是这样做的。这样我就有了一个对象来分隔值。有了这个,你可以把cookie传递给父节点,然后你可以通过键来访问你的值

var cookies=getCookieVal(mycookie);
alert(cookies.mykey);
function getCookieVal(parent) {
            var cookievalue = $.cookie(parent).split('&');
            var obj = {};
            $.each(cookievalue, function (i, v) {
                var key = v.substr(0, v.indexOf("="));
                var val = v.substr(v.indexOf("=") + 1, v.length);

                obj[key] = val;

            });
            return obj;
        }  

一行转换cookie为JavaScript对象或地图

Object.fromEntries(document.cookie.split('; ').map(v=>v.split(/=(.*)/s).map(decodeURIComponent)))
new Map(document.cookie.split('; ').map(v=>v.split(/=(.*)/s).map(decodeURIComponent)))

我喜欢使用闭包按名称获取cookie值。下面的闭包将允许您通过名称获取cookie值,但只有在更新了cookie字符串时才会解析cookie字符串。

您可以通过以下方法检索cookie的值:

var foo = cookies.get( "bar" );

代码:

var cookies = ( function() {
    var cookieString = null;
    var cookieArray = [];

    function getValOf( name ) {
        if ( newCookies() ) {
            parseCookieString()
        }
        return cookieArray[ name ];
    }

    // Check if new cookies have been added
    function newCookies() {
        return cookieString === document.cookie;
    }

    function parseCookieString() {
        cookieString = document.cookie;

        // Separate cookies
        var cookies = cookieString.split( ";" );

        // Empty previous cookies
        cookieArray = [];

        // Update cookieArray with new name-value pairs
        for ( var i in cookies ) {

            // Separate name and value
            var nameVal = cookies[ i ].split( "=" );
            var name = nameVal[ 0 ].trim();
            var value = nameVal[ 1 ].trim();

            // Add cookie name value pair to dictionary
            cookieArray[ name ] = value;
        }
    }

    return {

        /**
         * Returns value or undefined
         */
        get: function( name ) {
            return getValOf( name );
        }  
    };
})();

JS中的Set-Cookie

document.cookie = 'fb-event-id=15648779++';

通过名称函数获取cookie

function getCookie(name) {
    // Split cookie string and get all individual name=value pairs in an array
    var cookieArr = document.cookie.split(";");
    // Loop through the array elements
    for(var i = 0; i < cookieArr.length; i++) {
        var cookiePair = cookieArr[i].split("=");
        /* Removing whitespace at the beginning of the cookie name
        and compare it with the given string */
        if(name == cookiePair[0].trim()) {
            // Decode the cookie value and return
            return decodeURIComponent(cookiePair[1]);
        }
    } 
    // Return null if not found
    return null;
}

这是如何使用getCookie函数

var eventID = getCookie('fb-event-id')

通过名称获取cookie只需将cookie的名称传递给下面的函数

function getCookie(cname) {
  var name = cname + "=";
  var decodedCookie = decodeURIComponent(document.cookie);
  var ca = decodedCookie.split(';');
  for(var i = 0; i <ca.length; i++) {
    var c = ca[i];
    while (c.charAt(0) == ' ') {
      c = c.substring(1);
    }
    if (c.indexOf(name) == 0) {
      return c.substring(name.length, c.length);
    }
  }
  return "";
}