我知道这是一个老线程，但我从python的官方网站上发现了一些有趣的东西。只是为了分享另一个想法，删除所有的内容在一个目录。因为我在使用shutil.rmtree()时有一些授权问题，我不想删除目录并重新创建它。原始地址是http://docs.python.org/2/library/os.html#os.walk。希望这能帮助到一些人。

def emptydir(top):
    if(top == '/' or top == "\\"): return
    else:
        for root, dirs, files in os.walk(top, topdown=False):
            for name in files:
                os.remove(os.path.join(root, name))
            for name in dirs:
                os.rmdir(os.path.join(root, name))

使用操作系统。Python 3.6+中的scandir和上下文管理器协议:

import os
import shutil

with os.scandir(target_dir) as entries:
    for entry in entries:
        if entry.is_dir() and not entry.is_symlink():
            shutil.rmtree(entry.path)
        else:
            os.remove(entry.path)

Python的早期版本:

import os
import shutil

# Gather directory contents
contents = [os.path.join(target_dir, i) for i in os.listdir(target_dir)]

# Iterate and remove each item in the appropriate manner
[shutil.rmtree(i) if os.path.isdir(i) and not os.path.islink(i) else os.remove(i) for i in contents]

注:以防有人对我的答案投了反对票，我在这里有一些事情要解释。

Everyone likes short 'n' simple answers. However, sometimes the reality is not so simple. Back to my answer. I know shutil.rmtree() could be used to delete a directory tree. I've used it many times in my own projects. But you must realize that the directory itself will also be deleted by shutil.rmtree(). While this might be acceptable for some, it's not a valid answer for deleting the contents of a folder (without side effects). I'll show you an example of the side effects. Suppose that you have a directory with customized owner and mode bits, where there are a lot of contents. Then you delete it with shutil.rmtree() and rebuild it with os.mkdir(). And you'll get an empty directory with default (inherited) owner and mode bits instead. While you might have the privilege to delete the contents and even the directory, you might not be able to set back the original owner and mode bits on the directory (e.g. you're not a superuser). Finally, be patient and read the code. It's long and ugly (in sight), but proven to be reliable and efficient (in use).

这里有一个冗长而丑陋，但可靠而有效的解决方案。

它解决了一些其他答案没有解决的问题:

它正确地处理符号链接，包括不对符号链接调用shutil.rmtree()(如果它链接到一个目录，它将通过os.path.isdir()测试;甚至os.walk()的结果也包含符号链接目录)。 它可以很好地处理只读文件。

下面是代码(唯一有用的函数是clear_dir()):

import os
import stat
import shutil


# http://stackoverflow.com/questions/1889597/deleting-directory-in-python
def _remove_readonly(fn, path_, excinfo):
    # Handle read-only files and directories
    if fn is os.rmdir:
        os.chmod(path_, stat.S_IWRITE)
        os.rmdir(path_)
    elif fn is os.remove:
        os.lchmod(path_, stat.S_IWRITE)
        os.remove(path_)


def force_remove_file_or_symlink(path_):
    try:
        os.remove(path_)
    except OSError:
        os.lchmod(path_, stat.S_IWRITE)
        os.remove(path_)


# Code from shutil.rmtree()
def is_regular_dir(path_):
    try:
        mode = os.lstat(path_).st_mode
    except os.error:
        mode = 0
    return stat.S_ISDIR(mode)


def clear_dir(path_):
    if is_regular_dir(path_):
        # Given path is a directory, clear its content
        for name in os.listdir(path_):
            fullpath = os.path.join(path_, name)
            if is_regular_dir(fullpath):
                shutil.rmtree(fullpath, onerror=_remove_readonly)
            else:
                force_remove_file_or_symlink(fullpath)
    else:
        # Given path is a file or a symlink.
        # Raise an exception here to avoid accidentally clearing the content
        # of a symbolic linked directory.
        raise OSError("Cannot call clear_dir() on a symbolic link")

这应该做的技巧，只是使用OS模块列出，然后删除!

import os
DIR = os.list('Folder')
for i in range(len(DIR)):
    os.remove('Folder'+chr(92)+i)

为我工作过，有任何问题请告诉我!

使用rmtree并重新创建文件夹可以工作，但是我在删除并立即在网络驱动器上重新创建文件夹时遇到了错误。

建议的使用walk的解决方案不能工作，因为它使用rmtree删除文件夹，然后可能会尝试使用os。解除之前在这些文件夹中的文件的链接。这将导致一个错误。

发布的glob解决方案还将尝试删除非空文件夹，从而导致错误。

我建议你使用:

folder_path = '/path/to/folder'
for file_object in os.listdir(folder_path):
    file_object_path = os.path.join(folder_path, file_object)
    if os.path.isfile(file_object_path) or os.path.islink(file_object_path):
        os.unlink(file_object_path)
    else:
        shutil.rmtree(file_object_path)

我觉得这个密码起作用了。它不会删除文件夹，您可以使用此代码删除具有特定扩展名的文件。

import os
import glob

files = glob.glob(r'path/*')
for items in files:
    os.remove(items)