使用纯JavaScript以可重用的方式在单个函数中预览多个文件和单个文件

函数imagePreviewFunc（即，previewerId）{let files=that.filepreviewerId.innerHTML=“”//重置图像预览元素for（假设i=0；i<files.length；i++）{let imager=document.createElement（“img”）；imager.src=URL.createObjectURL（文件[i]）；previewerId.append（成像器）；}}<input accept=“image/*”type='file'id=“imageInput_1”onchange=“imagePreviewFunc（this，imagePreview_1）”/><div id=“imagePreview_1”>此分区用于单图像预览</div><hr/><input class=“form control”accept=“image/*”type='file'id=“imageInput_2”multiple=“true”onchange=“imagePreviewFunc（this，imagePreview_2）”/><div id=“imagePreview_2”>此div用于多图像预览</div>

我编辑了@Ivan的答案，以显示“无预览可用”图像，如果它不是图像：

function readURL(input) {
    var url = input.value;
    var ext = url.substring(url.lastIndexOf('.') + 1).toLowerCase();
    if (input.files && input.files[0]&& (ext == "gif" || ext == "png" || ext == "jpeg" || ext == "jpg")) {
        var reader = new FileReader();

        reader.onload = function (e) {
            $('.imagepreview').attr('src', e.target.result);
        }

        reader.readAsDataURL(input.files[0]);
    }else{
         $('.imagepreview').attr('src', '/assets/no_preview.png');
    }
}

对于我的应用程序，使用加密的GET url参数，只有这一点有效。我总是得到一个TypeError：$（…）为空。摘自https://developer.mozilla.org/en-US/docs/Web/API/FileReader/readAsDataURL

函数previewFile（）{var preview=document.querySelector（'img'）；var file=document.querySelector（'input[type=file]'）.files[0]；var reader=新文件读取器（）；reader.addEventListener（“load”，函数（）{preview.src=读取结果；}，假）；if（文件）{reader.readAsDataURL（文件）；}}<input-type=“file”onchange=“previewFile（）”><br><img src=“”height=“200”alt=“图像预览…”>

在使用jQuery/javascript上载之前预览多个图像？

这将一次预览多个文件作为缩略图图像

Html

<input id="ImageMedias" multiple="multiple" name="ImageMedias" type="file"
accept=".jfif,.jpg,.jpeg,.png,.gif" class="custom-file-input"  value="">                                    
<div id="divImageMediaPreview"></div>

剧本

$("#ImageMedias").change(function () {
    if (typeof (FileReader) != "undefined") {
        var dvPreview = $("#divImageMediaPreview");
        dvPreview.html("");            
        $($(this)[0].files).each(function () {
            var file = $(this);                
                var reader = new FileReader();
                reader.onload = function (e) {
                    var img = $("<img />");
                    img.attr("style", "width: 150px; height:100px; padding: 10px");
                    img.attr("src", e.target.result);
                    dvPreview.append(img);
                }
                reader.readAsDataURL(file[0]);                
        });
    } else {
        alert("This browser does not support HTML5 FileReader.");
    }
});

Codepen上的工作演示

jsfiddle上的工作演示

我希望这会有所帮助。

创建一个加载文件并触发自定义事件的函数怎么样。然后将侦听器附加到输入。这样，我们可以更灵活地使用文件，而不仅仅是预览图像。

/**
 * @param {domElement} input - The input element
 * @param {string} typeData - The type of data to be return in the event object. 
 */
function loadFileFromInput(input,typeData) {
    var reader,
        fileLoadedEvent,
        files = input.files;

    if (files && files[0]) {
        reader = new FileReader();

        reader.onload = function (e) {
            fileLoadedEvent = new CustomEvent('fileLoaded',{
                detail:{
                    data:reader.result,
                    file:files[0]  
                },
                bubbles:true,
                cancelable:true
            });
            input.dispatchEvent(fileLoadedEvent);
        }
        switch(typeData) {
            case 'arraybuffer':
                reader.readAsArrayBuffer(files[0]);
                break;
            case 'dataurl':
                reader.readAsDataURL(files[0]);
                break;
            case 'binarystring':
                reader.readAsBinaryString(files[0]);
                break;
            case 'text':
                reader.readAsText(files[0]);
                break;
        }
    }
}
function fileHandler (e) {
    var data = e.detail.data,
        fileInfo = e.detail.file;

    img.src = data;
}
var input = document.getElementById('inputId'),
    img = document.getElementById('imgId');

input.onchange = function (e) {
    loadFileFromInput(e.target,'dataurl');
};

input.addEventListener('fileLoaded',fileHandler)

也许我的代码不如一些用户，但我想你会明白这一点的

这里有一种在上传前使用纯javascript预览图像的简单方法；

//profile_change is the id of the input field where we choose an image
document.getElementById("profile_change").addEventListener("change", function() {

//Here we select the first file among the selected files.
const file = this.files[0];

/*here i used a label for the input field which is an image and this image will 
  represent the photo selected and profile_label is the id of this label */
const profile_label = document.getElementById("profile_label");

//Here we check if a file is selected
if(file) {
    //Here we bring in the FileReader which reads the file info. 
    const reader = new FileReader();
    
    /*After reader loads we change the src attribute of the label to the url of the 
    new image selected*/
    reader.addEventListener("load", function() {
        dp_label.setAttribute("src", this.result);
    })

    /*Here we are reading the file as a url i.e, we try to get the location of the 
    file to set that as the src of the label which we did above*/
    reader.readAsDataURL(file);

}else {
    //Here we simply set the src as default, whatever you want if no file is selected.
    dp_label.setAttribute("src", "as_you_want")
}
});

这里是HTML；

<label for="profile_change">
            <img title="Change Profile Photo" id="profile_label" 
             src="as_you_want" alt="DP" style="height: 150px; width: 150px; 
               border-radius: 50%;" >
</label>
<input style="display: none;" id="profile_change" name="DP" type="file" class="detail form-control">