我一直试图在设备在android上启动时启动一项服务，但我无法让它工作。我在网上看了一些链接，但没有一个代码工作。我是不是忘了什么?
AndroidManifest.xml
<receiver
android:name=".StartServiceAtBootReceiver"
android:enabled="true"
android:exported="false"
android:label="StartServiceAtBootReceiver" >
<intent-filter>
<action android:name="android.intent.action._BOOT_COMPLETED" />
</intent-filter>
</receiver>
<service
android:name="com.test.RunService"
android:enabled="true" />
BroadcastReceiver
public void onReceive(Context context, Intent intent) {
if ("android.intent.action.BOOT_COMPLETED".equals(intent.getAction())) {
Intent serviceLauncher = new Intent(context, RunService.class);
context.startService(serviceLauncher);
Log.v("TEST", "Service loaded at start");
}
}
其他答案看起来不错，但我认为我应该把所有问题都归结为一个完整的答案。
你需要在AndroidManifest.xml文件中添加以下内容:
In your <manifest> element:
<uses-permission android:name="android.permission.RECEIVE_BOOT_COMPLETED" />
In your <application> element (be sure to use a fully-qualified [or relative] class name for your BroadcastReceiver):
<receiver android:name="com.example.MyBroadcastReceiver">
<intent-filter>
<action android:name="android.intent.action.BOOT_COMPLETED" />
</intent-filter>
</receiver>
(you don't need the android:enabled, exported, etc., attributes: the Android defaults are correct)
In MyBroadcastReceiver.java:
package com.example;
public class MyBroadcastReceiver extends BroadcastReceiver {
@Override
public void onReceive(Context context, Intent intent) {
Intent startServiceIntent = new Intent(context, MyService.class);
context.startService(startServiceIntent);
}
}
从最初的问题:
<receiver>元素是否在<application>元素中尚不清楚
不清楚是否为BroadcastReceiver指定了正确的全限定(或相对)类名
在<intent-filter>中有一个拼写错误
