没有回答提到过度简化但有效的代码，所以下面是:

public class TreeNodeArray<T> {
    public T value;
    public final  java.util.List<TreeNodeArray<T>> kids =  new java.util.ArrayList<TreeNodeArray<T>>();
}

如果您正在编写白板代码、进行面试，或者只是计划使用树，那么这些内容就有点冗长了。

应该进一步说，树不像Pair那样存在的原因是，你应该将你的数据封装在使用它的类中，最简单的实现是这样的:

/***
/* Within the class that's using a binary tree for any reason. You could 
/* generalize with generics IFF the parent class needs different value types.
 */
private class Node {
  public String value;
  public Node[] nodes; // Or an Iterable<Node> nodes;
}

这就是任意宽度的树。

如果你想要一个二叉树，它通常更容易使用命名字段:

private class Node { // Using package visibility is an option
  String value;
  Node left;
  Node right;
}

或者如果你想要一个trie

private class Node {
  String value;
  Map<char, Node> nodes;
}

现在你说你想要

给定一个表示给定节点的输入字符串，能够获得所有的子节点(某种类型的列表或字符串数组)

听起来像是你的家庭作业。 但既然我有理由相信任何最后期限都已经过去了……

import java.util.Arrays;
import java.util.ArrayList;
import java.util.List;

public class kidsOfMatchTheseDays {
 static private class Node {
   String value;
   Node[] nodes;
 }

 // Pre-order; you didn't specify.
 static public List<String> list(Node node, String find) {
   return list(node, find, new ArrayList<String>(), false);
 }

 static private ArrayList<String> list(
     Node node,
     String find,
     ArrayList<String> list,
     boolean add) {
   if (node == null) {
     return list;
   }
   if (node.value.equals(find)) {
     add = true;
   }
   if (add) {
     list.add(node.value);
   }
   if (node.nodes != null) {
     for (Node child: node.nodes) {
       list(child, find, list, add);
     }
   }
   return list;
 }

 public static final void main(String... args) {
   // Usually never have to do setup like this, so excuse the style
   // And it could be cleaner by adding a constructor like:
   //     Node(String val, Node... children) {
   //         value = val;
   //         nodes = children;
   //     }
   Node tree = new Node();
   tree.value = "root";
   Node[] n = {new Node(), new Node()};
   tree.nodes = n;
   tree.nodes[0].value = "leftish";
   tree.nodes[1].value = "rightish-leafy";
   Node[] nn = {new Node()};
   tree.nodes[0].nodes = nn;
   tree.nodes[0].nodes[0].value = "off-leftish-leaf";
   // Enough setup
   System.out.println(Arrays.toString(list(tree, args[0]).toArray()));
 }
}

这让你使用:

$ java kidsOfMatchTheseDays leftish
[leftish, off-leftish-leaf]
$ java kidsOfMatchTheseDays root
[root, leftish, off-leftish-leaf, rightish-leafy]
$ java kidsOfMatchTheseDays rightish-leafy
[rightish-leafy]
$ java kidsOfMatchTheseDays a
[]

简单的例子:

public class ArbrePlaner {

public static void main(String[] args) {
    ArbrePlaner ll = new ArbrePlaner();
    
    ll.add(1,"A");
    ll.add(2,"B");
    ll.add(1,"C");
    ll.add(3,"D");
    ll.add(1,"Z");
    
    for(int i = 0; i < ll.size; i++){
    //  System.out.println(ll.isIdExist(i));
        System.out.println("-----------------");
        System.out.println(ll.getIdAt(i)+" :");
        linkedList lst = ll.getListDataById(ll.getIdAt(i));
        for(int j = 0; j < lst.size; j++){
            System.out.println(lst.getElementAt(j));
        }
    }
    
    
    
    
}

private int size;
private Noeud root;

public Noeud add(long Id, Object data){
    if(isIdExist(Id)){
        Noeud nd = getNoeudId(Id);
        nd.add(data);
        return nd;
    }else{
        Noeud nd = new Noeud(Id, data, this.root);
        this.root = nd;
        this.size++;
        return nd;
    }
}
 
 public Object getDataById(long Id, int x){
        Noeud thisNode = this.root;
        while(thisNode!=null){
            if(thisNode.getId() == Id){
                return thisNode.getLl().getElementAt(x);
            }
            thisNode = thisNode.getNextNoeud();
        }
        return null;
    }
 
 public long getIdAt(int x){
        if(size >= x){
            Noeud nd = this.root;
            for(int i = 0; i<x; i++)try {nd = nd.getNextNoeud();} catch (Exception e) {return -1;}
            return nd.getId();
        }
            return -1;
    }
 
 public linkedList getListDataById(long Id){
        Noeud thisNode = this.root;
        while(thisNode!=null){
            if(thisNode.getId() == Id){
                return thisNode.getLl();
            }
            thisNode = thisNode.getNextNoeud();
        }
        return null;
    }
 
public boolean deleteById(long id){
    Noeud thisNode = this.root;
    Noeud prevNode = null;
    
    while(thisNode != null){
        if(thisNode.getId() == id){
            prevNode.setNextNoeud(thisNode.getNextNoeud());
            this.setSize(this.getSize()-1);
            return true;
        }
        prevNode = thisNode;
        thisNode = thisNode.getNextNoeud();
    }
    return false;
}

 public boolean isIdExist(long Id){
        Noeud thisNode = this.root;
        while(thisNode!=null){
            if(thisNode.getId()== Id){
                return true;
            }
            thisNode = thisNode.getNextNoeud();
        }
        return false;
    }

 public boolean isDataExist(long Id, Object data){
     if(isIdExist(Id)){
         Noeud thisNode = this.root;
            while(thisNode!=null){
                if(thisNode.getId() == Id){
                    linkedList ll = thisNode.getLl();
                    long x = ll.hashCode();
                    long y = data.hashCode();
                    if(x==y) return true;
                }
                thisNode = thisNode.getNextNoeud();
            }
     }
     return false;
 }
 
 public Noeud getNoeudId(long Id){
        Noeud thisNode = this.root;
        while(thisNode!=null){
            if(thisNode.getId() == Id){
                return thisNode;
            }
            thisNode = thisNode.getNextNoeud();
        }
        return null;
    }

public ArbrePlaner() {
    this.root = root;
}

public ArbrePlaner(Noeud root) {
    this.root = root;
}

public ArbrePlaner(int size, Noeud root) {
    this.size = size;
    this.root = root;
}

public int getSize() {
    return size;
}

public void setSize(int size) {
    this.size = size;
}

public Noeud getRoot() {
    return root;
}

public void setRoot(Noeud root) {
    this.root = root;
}

private class Noeud{
    private long id;
    private Noeud nextNoeud;
    private linkedList Ll;
    
    public void add(Object data){
        Ll.add(data);
    }
    
    public Noeud(long id, Object data ,Noeud nextNoeud){
        this.id = id;
        this.nextNoeud = nextNoeud;
        Ll = new linkedList();
        Ll.add(data);
    }
    
    public long getId() {
        return id;
    }
    
    public Noeud(Object data){
        Ll.add(data);
    }
            
    public void setId(long id) {
        this.id = id;
    }
    public Noeud getNextNoeud() {
        return nextNoeud;
    }
    public void setNextNoeud(Noeud nextNoeud) {
        this.nextNoeud = nextNoeud;
    }
    public linkedList getLl() {
        return Ll;
    }
    public void setLl(linkedList ll) {
        Ll = ll;
    }
}
}

与Gareth的答案相同，请检查DefaultMutableTreeNode。它不是一般的，但在其他方面似乎符合要求。即使它在javax中。swing包，它不依赖于任何AWT或swing类。事实上，源代码实际上有注释// ISSUE:这个类不依赖于AWT中的任何东西——移到java.util?

    // TestTree.java
// A simple test to see how we can build a tree and populate it
//
import java.awt.*;
import java.awt.event.*;
import javax.swing.*;
import javax.swing.tree.*;

public class TestTree extends JFrame {

  JTree tree;
  DefaultTreeModel treeModel;

  public TestTree( ) {
    super("Tree Test Example");
    setSize(400, 300);
    setDefaultCloseOperation(EXIT_ON_CLOSE);
  }

  public void init( ) {
    // Build up a bunch of TreeNodes. We use DefaultMutableTreeNode because the
    // DefaultTreeModel can use it to build a complete tree.
    DefaultMutableTreeNode root = new DefaultMutableTreeNode("Root");
    DefaultMutableTreeNode subroot = new DefaultMutableTreeNode("SubRoot");
    DefaultMutableTreeNode leaf1 = new DefaultMutableTreeNode("Leaf 1");
    DefaultMutableTreeNode leaf2 = new DefaultMutableTreeNode("Leaf 2");

    // Build our tree model starting at the root node, and then make a JTree out
    // of it.
    treeModel = new DefaultTreeModel(root);
    tree = new JTree(treeModel);

    // Build the tree up from the nodes we created.
    treeModel.insertNodeInto(subroot, root, 0);
    // Or, more succinctly:
    subroot.add(leaf1);
    root.add(leaf2);

    // Display it.
    getContentPane( ).add(tree, BorderLayout.CENTER);
  }

  public static void main(String args[]) {
    TestTree tt = new TestTree( );
    tt.init( );
    tt.setVisible(true);
  }
}

你可以使用Java的任何XML API作为文档和节点..因为XML是一个带有字符串的树结构