function removeAccents(strAccents){
    strAccents = strAccents.split('');
    strAccentsOut = new Array();
    strAccentsLen = strAccents.length;
    var accents = 'ÀÁÂÃÄÅàáâãäåÒÓÔÕÕÖØòóôõöøÈÉÊËèéêëðÇçÐÌÍÎÏìíîïÙÚÛÜùúûüÑñŠšŸÿýŽž';
    var accentsOut = ['A','A','A','A','A','A','a','a','a','a','a','a','O','O','O','O','O','O','O','o','o','o','o','o','o','E','E','E','E','e','e','e','e','e','C','c','D','I','I','I','I','i','i','i','i','U','U','U','U','u','u','u','u','N','n','S','s','Y','y','y','Z','z'];
    for (var y = 0; y < strAccentsLen; y++) {
        if (accents.indexOf(strAccents[y]) != -1) {
            strAccentsOut[y] = accentsOut[accents.indexOf(strAccents[y])];
        }
        else
            strAccentsOut[y] = strAccents[y];
    }
    strAccentsOut = strAccentsOut.join('');
    return strAccentsOut;
}

新RegExp的格式为

RegExp(something, 'modifiers');

所以你会想

accentsTidy = function(s){
                        var r=s.toLowerCase();
                        r = r.replace(new RegExp("\\s", 'g'),"");
                        r = r.replace(new RegExp("[àáâãäå]", 'g'),"a");
                        r = r.replace(new RegExp("æ", 'g'),"ae");
                        r = r.replace(new RegExp("ç", 'g'),"c");
                        r = r.replace(new RegExp("[èéêë]", 'g'),"e");
                        r = r.replace(new RegExp("[ìíîï]", 'g'),"i");
                        r = r.replace(new RegExp("ñ", 'g'),"n");                            
                        r = r.replace(new RegExp("[òóôõö]", 'g'),"o");
                        r = r.replace(new RegExp("œ", 'g'),"oe");
                        r = r.replace(new RegExp("[ùúûü]", 'g'),"u");
                        r = r.replace(new RegExp("[ýÿ]", 'g'),"y");
                        r = r.replace(new RegExp("\\W", 'g'),"");
                        return r;
                };

谢谢大家 我使用这个版本并说明原因(因为我在开始时错过了这些解释，所以我试图帮助下一个读者，如果他和我一样无聊…)

备注:我想要一个高效的解决方案，所以:

只有一次regexp编译(如果需要) 每个字符串只扫描一个字符串 查找已翻译字符的有效方法 等等……

我的版本是: (里面没有新的技术技巧，只有一些精选的+解释)

makeSortString = (function() {
    var translate_re = /[¹²³áàâãäåaaaÀÁÂÃÄÅAAAÆccç©CCÇÐÐèéê?ëeeeeeÈÊË?EEEEE€gGiìíîïìiiiÌÍÎÏ?ÌIIIlLnnñNNÑòóôõöoooøÒÓÔÕÖOOOØŒr®Ršs?ߊS?ùúûüuuuuÙÚÛÜUUUUýÿÝŸžzzŽZZ]/g;
    var translate = {
"¹":"1","²":"2","³":"3","á":"a","à":"a","â":"a","ã":"a","ä":"a","å":"a","a":"a","a":"a","a":"a","À":"a","Á":"a","Â":"a","Ã":"a","Ä":"a","Å":"a","A":"a","A":"a",
"A":"a","Æ":"a","c":"c","c":"c","ç":"c","©":"c","C":"c","C":"c","Ç":"c","Ð":"d","Ð":"d","è":"e","é":"e","ê":"e","?":"e","ë":"e","e":"e","e":"e","e":"e","e":"e",
"e":"e","È":"e","Ê":"e","Ë":"e","?":"e","E":"e","E":"e","E":"e","E":"e","E":"e","€":"e","g":"g","G":"g","i":"i","ì":"i","í":"i","î":"i","ï":"i","ì":"i","i":"i",
"i":"i","i":"i","Ì":"i","Í":"i","Î":"i","Ï":"i","?":"i","Ì":"i","I":"i","I":"i","I":"i","l":"l","L":"l","n":"n","n":"n","ñ":"n","N":"n","N":"n","Ñ":"n","ò":"o",
"ó":"o","ô":"o","õ":"o","ö":"o","o":"o","o":"o","o":"o","ø":"o","Ò":"o","Ó":"o","Ô":"o","Õ":"o","Ö":"o","O":"o","O":"o","O":"o","Ø":"o","Œ":"o","r":"r","®":"r",
"R":"r","š":"s","s":"s","?":"s","ß":"s","Š":"s","S":"s","?":"s","ù":"u","ú":"u","û":"u","ü":"u","u":"u","u":"u","u":"u","u":"u","Ù":"u","Ú":"u","Û":"u","Ü":"u",
"U":"u","U":"u","U":"u","U":"u","ý":"y","ÿ":"y","Ý":"y","Ÿ":"y","ž":"z","z":"z","z":"z","Ž":"z","Z":"z","Z":"z"
    };
    return function(s) {
        return(s.replace(translate_re, function(match){return translate[match];}) );
    }
})();

我是这样用的:

var without_accents = makeSortString("wïthêüÄTrèsBïgüeAk100t");
// I let you guess the result,
// no I was kidding you : I give you the result : witheuatresbigueak100t

评论:

Tthe instruction inside it is done once (after, makeSortString != undefined) function(){...} is stored once in makeSortString, so the "big" translate_re and translate objects are stored once When you call makeSortString('something') it call directly the inside function which calls only s.replace(...) : it is efficient s.replace uses regexp (the special syntax of var translate_re= .... is in fact equivalent to var translate_re = new RegExp("[¹....Z]","g"); but the compilation of the regexp is done once for all, and the scan of the s String is done one for a call of the function (not for every character as it would be in a loop) For each character found s.replace calls function(match) where parameter match contains the character found, and it call the corresponding translated character (translate[match]) Translate[match] is probably efficient too as the javascript translate object is probably implemented by javascript with a hashtab or something equivalent and allow the program to find the translated character almost directly and not for instance through a loop on a array of all characters to find the right one (which would be awfully unefficient).

从te reo Māori语言中移除宏子 给那些来这里想从马āori语中去掉宏子的人。 注意:当我格式化代码时，Stackblitz删除了map键上的单引号-他们必须确信这是OK的。这个代码的子集，谢谢

'use strict'; var macronMap = { ā: 'a', ē: 'e', ī: 'i', ō: 'o', ū: 'u', Ā: 'A', Ē: 'E', Ī: 'I', Ō: 'O', Ū: 'U', }; function deMacron(str) { return str.replace(/[^A-Za-z0-9\[\] ]/g, function (char) { return macronMap[char] || char; }); } function macronFree(str) { return str === deMacron(str); } console.assert( 'a, e, i, o, u, A, E, I, O, U' === deMacron('ā, ē, ī, ō, ū, Ā, Ē, Ī, Ō, Ū') ); console.assert(macronFree('a, e, i, o, u, A, E, I, O, U')); console.assert(!macronFree('ā, ē, ī, ō, ū, Ā, Ē, Ī, Ō, Ū')); document.body.append(deMacron('ā, ē, ī, ō, ū, Ā, Ē, Ī, Ō, Ū'));

标准化变音符是非常有用的

    const { normalize } = require('normalize-diacritics');
     
    /** Assuming top-level await is enabled... */
    await normalize('söme stüff with áccènts'); // 'some stuff with accents'

有很多这样的方法，但我认为这个方法简单且足够好:

 function remove_accents(strAccents) {
    var strAccents = strAccents.split('');
    var strAccentsOut = new Array();
    var strAccentsLen = strAccents.length;
    var accents =    "ÀÁÂÃÄÅàáâãäåÒÓÔÕÕÖØòóôõöøÈÉÊËèéêëÇçðÐÌÍÎÏìíîïÙÚÛÜùúûüÑñŠšŸÿýŽž";
    var accentsOut = "AAAAAAaaaaaaOOOOOOOooooooEEEEeeeeCcdDIIIIiiiiUUUUuuuuNnSsYyyZz";
    for (var y = 0; y < strAccentsLen; y++) {
        if (accents.indexOf(strAccents[y]) != -1) {
            strAccentsOut[y] = accentsOut.substr(accents.indexOf(strAccents[y]), 1);
        } else
            strAccentsOut[y] = strAccents[y];
    }
    strAccentsOut = strAccentsOut.join('');

    return strAccentsOut;
}

如果你还想删除特殊字符，并转换下划线中的空格和连字符，请执行以下操作:

string = remove_accents(string);
string = string.replace(/[^a-z0-9\s]/gi, '').replace(/[-\s]/g, '_');