Spring Boot中是否有Filter类(用于web应用程序)的注释?也许@Filter ?

我想在我的项目中添加一个自定义过滤器。

Spring Boot参考指南中提到过 FilterRegistrationBean,但我不确定如何使用它。


当前回答

首先,将@ServletComponentScan添加到SpringBootApplication类中。

@ServletComponentScan
public class Application {

其次,创建一个过滤器文件,扩展filter或第三方过滤器类,并像这样添加@WebFilter到这个文件:

@Order(1) //optional
@WebFilter(filterName = "XXXFilter", urlPatterns = "/*",
    dispatcherTypes = {DispatcherType.REQUEST, DispatcherType.FORWARD},
    initParams = {@WebInitParam(name = "confPath", value = "classpath:/xxx.xml")})
public class XXXFilter extends Filter{

其他回答

没有特殊的注释来表示servlet筛选器。您只需声明一个Filter类型的@Bean(或FilterRegistrationBean)。在Boot自己的EndpointWebMvcAutoConfiguration中有一个例子(为所有响应添加自定义头);

如果你只声明一个过滤器,它将被应用到所有的请求。如果您还添加了一个FilterRegistrationBean,您可以另外指定要应用的单个servlet和url模式。

注意:

从Spring Boot 1.4开始,FilterRegistrationBean不再弃用,而是简单地将包从org.springframework. Boot .context. embedd.filterregistrationbean移动到org.springframework.boot.web.servlet.FilterRegistrationBean

如果您使用Spring Boot + Spring Security,则可以在安全配置中执行此操作。

在下面的示例中,我在UsernamePasswordAuthenticationFilter之前添加了一个自定义过滤器(请参阅所有默认的Spring安全过滤器及其顺序)。

@EnableWebSecurity
class SecurityConfig extends WebSecurityConfigurerAdapter {

    @Autowired FilterDependency filterDependency;

    @Override
    protected void configure(HttpSecurity http) throws Exception {
        http
            .addFilterBefore(
                new MyFilter(filterDependency),
                UsernamePasswordAuthenticationFilter.class);
    }
}

还有筛选器类

class MyFilter extends OncePerRequestFilter  {
    private final FilterDependency filterDependency;

    public MyFilter(FilterDependency filterDependency) {
        this.filterDependency = filterDependency;
    }

    @Override
    protected void doFilterInternal(HttpServletRequest request,
        HttpServletResponse response,
        FilterChain filterChain)
        throws ServletException, IOException {

        // Filter
        filterChain.doFilter(request, response);
    }
}

你主要需要两样东西:

Add @ServletComponentScan to your Main Class You may add a package named filter inside it. You create a Filter class that has the following: @Component @Order(Ordered.HIGHEST_PRECEDENCE) public class RequestFilter implements Filter { // whatever field you have public void doFilter(ServletRequest req, ServletResponse res, FilterChain chain) { HttpServletResponse response = (HttpServletResponse) res; HttpServletRequest request = (HttpServletRequest) req; // Whatever implementation you want try { chain.doFilter(req, res); } catch(Exception e) { e.printStackTrace(); } } public void init(FilterConfig filterConfig) { } public void destroy() { } }

对于Spring Boot在我所做的任何配置类:

@Bean
public OncePerRequestFilter myFilter() {
    return new OncePerRequestFilter() {
        @Override
        protected void doFilterInternal(HttpServletRequest request, HttpServletResponse response, FilterChain filterChain) throws ServletException, IOException {
            AuthUser authUser = SecurityUtil.safeGet(); // applied after secutiry filters
            ...
            filterChain.doFilter(request, response);
        }
    };
}

这就是全部,不需要任何注册。参见什么是OncePerRequestFilter?

Use:

@WebFilter(urlPatterns="/*")
public class XSSFilter implements Filter {

    private static final org.apache.log4j.Logger LOGGER = LogManager.getLogger(XSSFilter.class);

    @Override
    public void init(FilterConfig filterConfig) throws ServletException {
        LOGGER.info("Initiating XSSFilter... ");
    }

    @Override
    public void doFilter(ServletRequest request, ServletResponse response, FilterChain chain)
            throws IOException, ServletException {
        HttpServletRequest req = (HttpServletRequest) request;
        HttpRequestWrapper requestWrapper = new HttpRequestWrapper(req);
        chain.doFilter(requestWrapper, response);
    }

    @Override
    public void destroy() {
        LOGGER.info("Destroying XSSFilter... ");
    }

}

你需要实现Filter,并且它需要用@WebFilter(urlPatterns="/*")进行注释。

在Application或Configuration类中,您需要添加@ServletComponentScan。通过此操作,您的筛选器将被注册。