获取所有字典/对象值的最短方法:

Object.keys(dict).map(k => dict[k]);

或者这样:

Object.entries(dict).map([k,v] => /* ... */);

这个怎么样?

for (let [key, value] of Object.entries(obj)) {
    ...
}

要遍历键/值，使用for in循环:

for (let key in myDictionary) {
    let value = myDictionary[key];
    // Use `key` and `value`
}

获取所有字典/对象值的最短方法:

Object.keys(dict).map(k => dict[k]);

或者这样:

Object.entries(dict).map([k,v] => /* ... */);

要得到钥匙:

function GetDictionaryKeysAsArray(dict: {[key: string]: string;}): string[] {
  let result: string[] = [];
  Object.keys(dict).map((key) =>
    result.push(key),
  );
  return result;
}

这是我的函数，希望对大家有所帮助

function recordToArray<TypeOfSchema>(
  data: Record<string, TypeOfSchema>
): Array<TypeOfSchema> {
  return Object.keys(data).map((key: string) => ({ id: key, ...data[key] }));
}