根据最高的两个答案，我有一个小方法:

<span class="btn btn-info btn-minier popover-info" data-rel="popover"
                                              data-placement="bottom" data-html="true" title=""
                                              data-content="popover-content"
                                              data-original-title="popover-title">
                                            <i class="ace-icon fa fa-info smaller-100"></i>
                                        </span>

            $('[data-rel=popover]').popover({html: true});
            $(document).on("shown.bs.popover", '[data-rel=popover]', function () {
                $('[data-rel="popover"][popover-show="1"]').popover('hide');
                $(this).attr('popover-show', '1');
            });
            $(document).on("hidden.bs.popover", '[data-rel=popover]', function () {
                if ($(this).attr('popover-show') === '0') {
                    // My important fix: using bootstrap 3.4.1, if hide popover by .popover('hide') and click to show, popover internal treat it is already shown and dispatch hidden event immediately without popover anything.
                    $(this).popover('toggle');
                } else {
                    $(this).attr('popover-show', '0');
                }
            });
            $('html').on('click', function (e) {
                if (typeof $(e.target).data('original-title') == 'undefined'
                    && typeof $(e.target).parent().data('original-title') == 'undefined'
                    && !$(e.target).parents().is('.popover.in')) {
                    $('[data-rel="popover"][popover-show="1"]').popover('hide');
                }
            });

修改后的接受方案。我的经验是，在一些弹窗被隐藏后，它们必须被点击两次才能再次显示。下面是我所做的，以确保弹窗('hide')不会被已经隐藏的弹窗调用。

$('body').on('click', function (e) {
    $('[data-original-title]').each(function () {
        //the 'is' for buttons that trigger popups
        //the 'has' for icons within a button that triggers a popup
        if (!$(this).is(e.target) && $(this).has(e.target).length === 0 && $('.popover').has(e.target).length === 0) {
            var popoverElement = $(this).data('bs.popover').tip();
            var popoverWasVisible = popoverElement.is(':visible');

            if (popoverWasVisible) {
                $(this).popover('hide');
                $(this).click(); // double clicking required to reshow the popover if it was open, so perform one click now
            }
        }
    });
});

我做了一个jsfiddle来告诉你如何做到这一点:

http://jsfiddle.net/3yHTH/

其思想是在单击按钮时显示弹出窗口，在单击按钮外时隐藏弹出窗口。

HTML

<a id="button" href="#" class="btn btn-danger">Click for popover</a>

JS

$('#button').popover({
    trigger: 'manual',
    position: 'bottom',
    title: 'Example',
    content: 'Popover example for SO'
}).click(function(evt) {
    evt.stopPropagation();
    $(this).popover('show');
});

$('html').click(function() {
    $('#button').popover('hide');
});

根据最高的两个答案，我有一个小方法:

<span class="btn btn-info btn-minier popover-info" data-rel="popover"
                                              data-placement="bottom" data-html="true" title=""
                                              data-content="popover-content"
                                              data-original-title="popover-title">
                                            <i class="ace-icon fa fa-info smaller-100"></i>
                                        </span>

            $('[data-rel=popover]').popover({html: true});
            $(document).on("shown.bs.popover", '[data-rel=popover]', function () {
                $('[data-rel="popover"][popover-show="1"]').popover('hide');
                $(this).attr('popover-show', '1');
            });
            $(document).on("hidden.bs.popover", '[data-rel=popover]', function () {
                if ($(this).attr('popover-show') === '0') {
                    // My important fix: using bootstrap 3.4.1, if hide popover by .popover('hide') and click to show, popover internal treat it is already shown and dispatch hidden event immediately without popover anything.
                    $(this).popover('toggle');
                } else {
                    $(this).attr('popover-show', '0');
                }
            });
            $('html').on('click', function (e) {
                if (typeof $(e.target).data('original-title') == 'undefined'
                    && typeof $(e.target).parent().data('original-title') == 'undefined'
                    && !$(e.target).parents().is('.popover.in')) {
                    $('[data-rel="popover"][popover-show="1"]').popover('hide');
                }
            });

演示:http://jsfiddle.net/nessajtr/yxpM5/1/

var clickOver = clickOver || {};
clickOver.uniqueId = $.now();

clickOver.ClickOver = function (selector, options) {
    var self = this;

    //default values
    var isVisible, clickedAway = false;

    var callbackMethod = options.content;
var uniqueDiv = document.createElement("div");
var divId = uniqueDiv.id = ++clickOver.uniqueId;
uniqueDiv.innerHTML = options.loadingContent();

options.trigger = 'manual';
options.animation = false;
options.content = uniqueDiv;

self.onClose = function () {
    $("#" + divId).html(options.loadingContent());
    $(selector).popover('hide')
    isVisible = clickedAway = false;
};
self.onCallback = function (result) {
    $("#" + divId).html(result);
};

$(selector).popover(options);

//events
$(selector).bind("click", function (e) {
    $(selector).filter(function (f) {
        return $(selector)[f] != e.target;
    }).popover('hide');

    $(selector).popover("show");
    callbackMethod(self.onCallback);

    isVisible = !(clickedAway = false);
});

$(document).bind("click", function (e) {
    if (isVisible && clickedAway && $(e.target).parents(".popover").length == 0) {
        self.onClose();
        isVisible = clickedAway = false;
    } else clickedAway = true;
});

}

这是我的解。

只需将此属性添加到html元素，以关闭弹出窗口在下次点击。

data-trigger="focus"

参考来自https://getbootstrap.com/docs/3.3/javascript/#dismiss-on-next-click