如何在我的工作副本中排除非指数的变更?


当前回答

它甚至在常见的 git 许可之外的目录中工作。

sudo chmod -R 664 ./* && git checkout -- . && git clean -dfx

最近发生在我身上

其他回答

没有一个解决方案工作,如果你只是改变了文件的许可(这是DOS/Windoze)

Mon 23/11/2015-15:16:34.80 C:\...\work\checkout\slf4j+> git status
On branch SLF4J_1.5.3
Changes not staged for commit:
  (use "git add ..." to update what will be committed)
  (use "git checkout -- ..." to discard changes in working directory)

        modified:   .gitignore
        modified:   LICENSE.txt
        modified:   TODO.txt
        modified:   codeStyle.xml
        modified:   pom.xml
        modified:   version.pl

no changes added to commit (use "git add" and/or "git commit -a")

Mon 23/11/2015-15:16:37.87 C:\...\work\checkout\slf4j+> git diff
diff --git a/.gitignore b/.gitignore
old mode 100644
new mode 100755
diff --git a/LICENSE.txt b/LICENSE.txt
old mode 100644
new mode 100755
diff --git a/TODO.txt b/TODO.txt
old mode 100644
new mode 100755
diff --git a/codeStyle.xml b/codeStyle.xml
old mode 100644
new mode 100755
diff --git a/pom.xml b/pom.xml
old mode 100644
new mode 100755
diff --git a/version.pl b/version.pl
old mode 100644
new mode 100755

Mon 23/11/2015-15:16:45.22 C:\...\work\checkout\slf4j+> git reset --hard HEAD
HEAD is now at 8fa8488 12133-CHIXMISSINGMESSAGES MALCOLMBOEKHOFF 20141223124940 Added .gitignore

Mon 23/11/2015-15:16:47.42 C:\...\work\checkout\slf4j+> git clean -f

Mon 23/11/2015-15:16:53.49 C:\...\work\checkout\slf4j+> git stash save -u
Saved working directory and index state WIP on SLF4J_1.5.3: 8fa8488 12133-CHIXMISSINGMESSAGES MALCOLMBOEKHOFF 20141223124940 Added .gitignore
HEAD is now at 8fa8488 12133-CHIXMISSINGMESSAGES MALCOLMBOEKHOFF 20141223124940 Added .gitignore

Mon 23/11/2015-15:17:00.40 C:\...\work\checkout\slf4j+> git stash drop
Dropped refs/stash@{0} (cb4966e9b1e9c9d8daa79ab94edc0c1442a294dd)

Mon 23/11/2015-15:17:06.75 C:\...\work\checkout\slf4j+> git stash drop
Dropped refs/stash@{0} (e6c49c470f433ce344e305c5b778e810625d0529)

Mon 23/11/2015-15:17:08.90 C:\...\work\checkout\slf4j+> git stash drop
No stash found.

Mon 23/11/2015-15:17:15.21 C:\...\work\checkout\slf4j+> git checkout -- .

Mon 23/11/2015-15:22:00.68 C:\...\work\checkout\slf4j+> git checkout -f -- .

Mon 23/11/2015-15:22:04.53 C:\...\work\checkout\slf4j+> git status
On branch SLF4J_1.5.3
Changes not staged for commit:
  (use "git add ..." to update what will be committed)
  (use "git checkout -- ..." to discard changes in working directory)

        modified:   .gitignore
        modified:   LICENSE.txt
        modified:   TODO.txt
        modified:   codeStyle.xml
        modified:   pom.xml
        modified:   version.pl

no changes added to commit (use "git add" and/or "git commit -a")

Mon 23/11/2015-15:22:13.06 C:\...\work\checkout\slf4j+> git diff
diff --git a/.gitignore b/.gitignore
old mode 100644
new mode 100755
diff --git a/LICENSE.txt b/LICENSE.txt
old mode 100644
new mode 100755
diff --git a/TODO.txt b/TODO.txt
old mode 100644
new mode 100755
diff --git a/codeStyle.xml b/codeStyle.xml
old mode 100644
new mode 100755
diff --git a/pom.xml b/pom.xml
old mode 100644
new mode 100755
diff --git a/version.pl b/version.pl
old mode 100644
new mode 100755

修复这一点的唯一方法是手动重新设置已更改的文件中的权限:

Mon 23/11/2015-15:25:43.79 C:\...\work\checkout\slf4j+> git status -s | egrep "^ M" | cut -c4- | for /f "usebackq tokens=* delims=" %A in (`more`) do chmod 644 %~A

Mon 23/11/2015-15:25:55.37 C:\...\work\checkout\slf4j+> git status
On branch SLF4J_1.5.3
nothing to commit, working directory clean

Mon 23/11/2015-15:25:59.28 C:\...\work\checkout\slf4j+>

Mon 23/11/2015-15:26:31.12 C:\...\work\checkout\slf4j+> git diff

它检查了当前目录的当前指数,从当前目录向下将文件中的所有变化抛弃。

git checkout .

或此,检查所有文件从指数,过写工作树文件。

git checkout-index -a -f

在我看来,

git clean -df

应该做技巧. 如 Git 文档上 git clean

git-clean - 从工作树中删除未追踪的文件

描述

清理工作树通过重复删除不受版本控制的文件,从当前目录开始. 通常,只有未知的文件到 Git 被删除,但如果 -x 选项被指定,忽略的文件也被删除. 例如,这可以有用去除所有构建产品. 如果任何可选的... 论点被提供,只有这些路径被影响。

选项

如果您想恢复未完成的文件,请使用 git restore --staged。

git checkout -f


男子Git-Checkout:

F、 - 力量

在切换分支时,即使指数或工作树与头部不同,也会进行进展,用来消除当地的变化。

在从指数中查看路径时,不要错过未嵌入的输入;相反,未嵌入的输入被忽略。