所有这些都创建了字符串“01”:

>python -m timeit "'{:02d}'.format(1)"
1000000 loops, best of 5: 357 nsec per loop

>python -m timeit "'{0:0{1}d}'.format(1,2)"
500000 loops, best of 5: 607 nsec per loop

>python -m timeit "f'{1:02d}'"
1000000 loops, best of 5: 281 nsec per loop

>python -m timeit "f'{1:0{2}d}'"
500000 loops, best of 5: 423 nsec per loop

>python -m timeit "str(1).zfill(2)"
1000000 loops, best of 5: 271 nsec per loop

>python
Python 3.8.1 (tags/v3.8.1:1b293b6, Dec 18 2019, 23:11:46) [MSC v.1916 64 bit (AMD64)] on win32

Use:

'00'[len(str(i)):] + str(i)

或者使用数学模块:

import math
'00'[math.ceil(math.log(i, 10)):] + str(i)

使用格式字符串- http://docs.python.org/lib/typesseq-strings.html

例如:

python -c 'print "%(num)02d" % {"num":5}'

我是这样做的:

str(1).zfill(len(str(total)))

基本上zfill取你想加的前导零的个数，所以很容易取最大的数字，把它转换成字符串并得到长度，像这样:

Python 3.6.5 (default, May 11 2018, 04:00:52) 
[GCC 8.1.0] on linux
Type "help", "copyright", "credits" or "license" for more information.
>>> total = 100
>>> print(str(1).zfill(len(str(total))))
001
>>> total = 1000
>>> print(str(1).zfill(len(str(total))))
0001
>>> total = 10000
>>> print(str(1).zfill(len(str(total))))
00001
>>> 

width = 5
num = 3
formatted = (width - len(str(num))) * "0" + str(num)
print formatted

或者另一个解。

"{:0>2}".format(number)