我使用这段代码来获得完整的URL:
$actual_link = 'http://'.$_SERVER['HTTP_HOST'].$_SERVER['PHP_SELF'];
问题是我在我的.htaccess中使用了一些掩码,所以我们在URL中看到的并不总是文件的真实路径。
我需要的是得到URL, URL中写了什么,不多不少——完整的URL。
我需要得到它如何出现在web浏览器的导航栏,而不是服务器上文件的真实路径。
我使用这段代码来获得完整的URL:
$actual_link = 'http://'.$_SERVER['HTTP_HOST'].$_SERVER['PHP_SELF'];
问题是我在我的.htaccess中使用了一些掩码,所以我们在URL中看到的并不总是文件的真实路径。
我需要的是得到URL, URL中写了什么,不多不少——完整的URL。
我需要得到它如何出现在web浏览器的导航栏,而不是服务器上文件的真实路径。
当前回答
这是我的解决方案-代码的灵感来自特雷西调试器。更改为支持不同的服务器端口。您可以获得完整的当前URL,包括$_SERVER['REQUEST_URI']或只是基本的服务器URL。检查我的函数:
function getCurrentUrl($full = true) {
if (isset($_SERVER['REQUEST_URI'])) {
$parse = parse_url(
(isset($_SERVER['HTTPS']) && strcasecmp($_SERVER['HTTPS'], 'off') ? 'https://' : 'http://') .
(isset($_SERVER['HTTP_HOST']) ? $_SERVER['HTTP_HOST'] : (isset($_SERVER['SERVER_NAME']) ? $_SERVER['SERVER_NAME'] : '')) . (($full) ? $_SERVER['REQUEST_URI'] : null)
);
$parse['port'] = $_SERVER["SERVER_PORT"]; // Setup protocol for sure (80 is default)
return http_build_url('', $parse);
}
}
下面是测试代码:
// Follow $_SERVER variables was set only for test
$_SERVER['HTTPS'] = 'off'; // on
$_SERVER['SERVER_PORT'] = '9999'; // Setup
$_SERVER['HTTP_HOST'] = 'some.crazy.server.5.name:8088'; // Port is optional there
$_SERVER['REQUEST_URI'] = '/150/tail/single/normal?get=param';
echo getCurrentUrl();
// http://some.crazy.server.5.name:9999/150/tail/single/normal?get=param
echo getCurrentUrl(false);
// http://some.crazy.server.5.name:9999/
其他回答
在网页上输出链接的简短版本
$url = "//{$_SERVER['HTTP_HOST']}{$_SERVER['REQUEST_URI']}";
$escaped_url = htmlspecialchars( $url, ENT_QUOTES, 'UTF-8' );
echo '<a href="' . $escaped_url . '">' . $escaped_url . '</a>';
下面是关于//example.com/path/格式的问题和边缘情况的更多细节
完整版
function url_origin( $s, $use_forwarded_host = false )
{
$ssl = ( ! empty( $s['HTTPS'] ) && $s['HTTPS'] == 'on' );
$sp = strtolower( $s['SERVER_PROTOCOL'] );
$protocol = substr( $sp, 0, strpos( $sp, '/' ) ) . ( ( $ssl ) ? 's' : '' );
$port = $s['SERVER_PORT'];
$port = ( ( ! $ssl && $port=='80' ) || ( $ssl && $port=='443' ) ) ? '' : ':'.$port;
$host = ( $use_forwarded_host && isset( $s['HTTP_X_FORWARDED_HOST'] ) ) ? $s['HTTP_X_FORWARDED_HOST'] : ( isset( $s['HTTP_HOST'] ) ? $s['HTTP_HOST'] : null );
$host = isset( $host ) ? $host : $s['SERVER_NAME'] . $port;
return $protocol . '://' . $host;
}
function full_url( $s, $use_forwarded_host = false )
{
return url_origin( $s, $use_forwarded_host ) . $s['REQUEST_URI'];
}
$absolute_url = full_url( $_SERVER );
echo $absolute_url;
这是一个经过大量修改的http://snipplr.com/view.php?codeview&id=2734(现在已经不存在了)
URL结构:
scheme://username:password@domain:port/path?query_string#fragment_id
粗体部分将不包含在函数中
注:
This function does not include username:password from a full URL or the fragment (hash). It will not show the default port 80 for HTTP and port 443 for HTTPS. Only tested with http and https schemes. The #fragment_id is not sent to the server by the client (browser) and will not be added to the full URL. $_GET will only contain foo=bar2 for an URL like /example?foo=bar1&foo=bar2. Some CMS's and environments will rewrite $_SERVER['REQUEST_URI'] and return /example?foo=bar2 for an URL like /example?foo=bar1&foo=bar2, use $_SERVER['QUERY_STRING'] in this case. Keep in mind that an URI = URL + URN, but due to popular use, URL now means both URI and URL. You should remove HTTP_X_FORWARDED_HOST if you do not plan to use proxies or balancers. The spec says that the Host header must contain the port number unless it is the default number.
客户端(浏览器)控制变量:
$ _SERVER [' REQUEST_URI ']。任何不支持的字符在发送之前都由浏览器编码。 $_SERVER['HTTP_HOST'],根据PHP手册中的注释:http://php.net/manual/en/reserved.variables.php并不总是可用的 $_SERVER['HTTP_X_FORWARDED_HOST']由平衡器设置,在PHP手册中的$_SERVER变量列表中没有提到。
服务器控制变量:
$ _SERVER(“HTTPS”)。客户端选择使用此选项,但服务器返回的实际值为空或“on”。 $ _SERVER [' SERVER_PORT ']。服务器只接受允许的数字作为端口。 $ _SERVER [' SERVER_PROTOCOL ']。服务器只接受特定的协议。 $ _SERVER [' SERVER_NAME ']。它是在服务器配置中手动设置的,根据kralyk的说法,它不适用于IPv6。
相关:
PHP中的HTTP_HOST和SERVER_NAME之间的区别是什么? HTTP“主机”头参数中需要端口号吗? https://stackoverflow.com/a/28049503/175071
使用Apache环境变量很容易做到这一点。这只适用于Apache 2,我假设您正在使用Apache 2。
简单使用下面的PHP代码:
<?php
$request_url = apache_getenv("HTTP_HOST") . apache_getenv("REQUEST_URI");
echo $request_url;
?>
我用了这句话。
$base = "http://$_SERVER[SERVER_NAME]:$_SERVER[SERVER_PORT]$my_web_base_path";
$url = $base . "/" . dirname(dirname(__FILE__));
我觉得这个方法不错,试试吧
if($_SERVER['HTTP_HOST'] == "localhost"){
define('SITEURL', 'http://' . $_SERVER['HTTP_HOST']);
define('SITEPATH', $_SERVER['DOCUMENT_ROOT']);
define('CSS', $_SERVER['DOCUMENT_ROOT'] . '/css/');
define('IMAGES', $_SERVER['DOCUMENT_ROOT'] . '/images/');
}
else{
define('SITEURL', 'http://' . $_SERVER['HTTP_HOST']);
define('SITEPATH', $_SERVER['DOCUMENT_ROOT']);
define('TEMPLATE', $_SERVER['DOCUMENT_ROOT'] . '/incs/template/');
define('CSS', $_SERVER['DOCUMENT_ROOT'] . '/css/');
define('IMAGES', $_SERVER['DOCUMENT_ROOT'] . '/images/');
}
非常简单的用法:
function current_url() {
$current_url = ( $_SERVER["HTTPS"] != 'on' ) ? 'http://'.$_SERVER["SERVER_NAME"] : 'https://'.$_SERVER["SERVER_NAME"];
$current_url .= ( $_SERVER["SERVER_PORT"] != 80 ) ? ":".$_SERVER["SERVER_PORT"] : "";
$current_url .= $_SERVER["REQUEST_URI"];
return $current_url;
}