如何将格式为“%d/%m/%Y”的字符串转换为时间戳?
"01/12/2011" -> 1322697600
如何将格式为“%d/%m/%Y”的字符串转换为时间戳?
"01/12/2011" -> 1322697600
当前回答
似乎相当有效:
import datetime
day, month, year = '01/12/2011'.split('/')
datetime.datetime(int(year), int(month), int(day)).timestamp()
1.61µs±120 ns /循环(7次运行的平均值±标准值,每次100000次循环)
其他回答
我使用ciso8601,它比datetime的strptime快62倍。
t = "01/12/2011"
ts = ciso8601.parse_datetime(t)
# to get time in seconds:
time.mktime(ts.timetuple())
你可以在这里了解更多。
很多答案都没有考虑到日期一开始就很天真
为了正确,您需要首先将初始日期设置为具有时区意识的datetime
import datetime
import pytz
# naive datetime
d = datetime.datetime.strptime('01/12/2011', '%d/%m/%Y')
>>> datetime.datetime(2011, 12, 1, 0, 0)
# add proper timezone
pst = pytz.timezone('America/Los_Angeles')
d = pst.localize(d)
>>> datetime.datetime(2011, 12, 1, 0, 0,
tzinfo=<DstTzInfo 'America/Los_Angeles' PST-1 day, 16:00:00 STD>)
# convert to UTC timezone
utc = pytz.UTC
d = d.astimezone(utc)
>>> datetime.datetime(2011, 12, 1, 8, 0, tzinfo=<UTC>)
# epoch is the beginning of time in the UTC timestamp world
epoch = datetime.datetime(1970,1,1,0,0,0,tzinfo=pytz.UTC)
>>> datetime.datetime(1970, 1, 1, 0, 0, tzinfo=<UTC>)
# get the total second difference
ts = (d - epoch).total_seconds()
>>> 1322726400.0
另外:
小心,在datetime中使用pytz for tzinfo。datetime不适用于许多时区。参见datetime with pytz timezone。不同的偏移量取决于tzinfo的设置方式
# Don't do this:
d = datetime.datetime(2011, 12, 1,0,0,0, tzinfo=pytz.timezone('America/Los_Angeles'))
>>> datetime.datetime(2011, 1, 12, 0, 0,
tzinfo=<DstTzInfo 'America/Los_Angeles' LMT-1 day, 16:07:00 STD>)
# tzinfo in not PST but LMT here, with a 7min offset !!!
# when converting to UTC:
d = d.astimezone(pytz.UTC)
>>> datetime.datetime(2011, 1, 12, 7, 53, tzinfo=<UTC>)
# you end up with an offset
https://en.wikipedia.org/wiki/Local_mean_time
你可以从两个方向,unix epoch <==> datetime:
import datetime
import time
the_date = datetime.datetime.fromtimestamp( 1639763585 )
unix_time = time.mktime(the_date.timetuple())
assert ( the_date == datetime.datetime.fromtimestamp(unix_time) ) & \
( time.mktime(the_date.timetuple()) == unix_time )
似乎相当有效:
import datetime
day, month, year = '01/12/2011'.split('/')
datetime.datetime(int(year), int(month), int(day)).timestamp()
1.61µs±120 ns /循环(7次运行的平均值±标准值,每次100000次循环)
我建议约会日期:
import dateutil.parser
dateutil.parser.parse("01/12/2011", dayfirst=True).timestamp()