我试图使用堆栈和选项卡导航器切换屏幕。
const MainNavigation = StackNavigator({
otp: { screen: OTPlogin },
otpverify: { screen: OTPverification},
userVerified: {
screen: TabNavigator({
List: { screen: List },
Settings: { screen: Settings }
}),
},
});
在这种情况下,首先使用堆栈导航器,然后使用制表器。我想从堆栈导航器中隐藏头文件。这是不正常工作时,我使用导航选项::
navigationOptions: { header: { visible: false } }
我试图在前两个组件上使用这段代码在stacknavigator。
如果我使用这一行,然后得到一些错误,如:
另一种隐藏特定屏幕标题的方法是尝试使用React中的useLayoutEffect。
是这样的:
import { View, Text, Button } from "react-native";
import React, { useLayoutEffect } from "react";
import { useNavigation } from "@react-navigation/native";
import useAuth from "../hooks/userAuth";
const HomeScreen = () => {
const navigation = useNavigation();
const { logout } = useAuth();
useLayoutEffect(() => {
navigation.setOptions({
headerShown: false,
});
}, []);
return (
<View>
<Text>I am the HomeScreen</Text>
<Button
title="Go to Chat Screen"
onPress={() => navigation.navigate("Chat")}
/>
<Button title="Logout" onPress={logout} />
</View>
);
};
export default HomeScreen;
这通常允许隐藏组件头,它将在屏幕呈现时执行。
另一种隐藏特定屏幕标题的方法是尝试使用React中的useLayoutEffect。
是这样的:
import { View, Text, Button } from "react-native";
import React, { useLayoutEffect } from "react";
import { useNavigation } from "@react-navigation/native";
import useAuth from "../hooks/userAuth";
const HomeScreen = () => {
const navigation = useNavigation();
const { logout } = useAuth();
useLayoutEffect(() => {
navigation.setOptions({
headerShown: false,
});
}, []);
return (
<View>
<Text>I am the HomeScreen</Text>
<Button
title="Go to Chat Screen"
onPress={() => navigation.navigate("Chat")}
/>
<Button title="Logout" onPress={logout} />
</View>
);
};
export default HomeScreen;
这通常允许隐藏组件头,它将在屏幕呈现时执行。