我需要更改表中几个列的数据类型。

对于单个列,下面的工作很好:

ALTER TABLE tblcommodityOHLC
ALTER COLUMN
    CC_CommodityContractID NUMERIC(18,0) 

但是如何在一条语句中修改多个列呢?以下选项无效:

ALTER TABLE tblcommodityOHLC
ALTER COLUMN
    CC_CommodityContractID NUMERIC(18,0), 
    CM_CommodityID NUMERIC(18,0)

当前回答

select 'ALTER TABLE ' + OBJECT_NAME(o.object_id) + 
    ' ALTER COLUMN ' + c.name + ' DATETIME2 ' + 
    CASE WHEN c.is_nullable = 0 THEN 'NOT NULL' ELSE 'NULL' END
from sys.objects o
inner join sys.columns c on o.object_id = c.object_id
inner join sys.types t on c.system_type_id = t.system_type_id
where o.type='U'
and c.name = 'Timestamp'
and t.name = 'datetime'
order by OBJECT_NAME(o.object_id)

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其他回答

如果我正确理解了你的问题,你可以使用下面提到的查询在一个表中添加多个列。

查询:

Alter table tablename add (column1 dataype, column2 datatype);

多亏了Evan的代码示例,我能够对其进行更多的修改,使其更特定于以特定列名开头的表,并处理约束的细节。我运行该代码,然后复制[code]列并毫无问题地执行它。

USE [Table_Name]
GO
SELECT
     TABLE_CATALOG
    ,TABLE_SCHEMA
    ,TABLE_NAME
    ,COLUMN_NAME
    ,DATA_TYPE
    ,'ALTER TABLE ['+TABLE_SCHEMA+'].['+TABLE_NAME+'] DROP CONSTRAINT [DEFAULT_'+TABLE_NAME+'_'+COLUMN_NAME+']; 
ALTER TABLE  ['+TABLE_SCHEMA+'].['+TABLE_NAME+'] ALTER COLUMN ['+COLUMN_NAME+'] datetime2 (7) NOT NULL 
ALTER TABLE  ['+TABLE_SCHEMA+'].['+TABLE_NAME+'] ADD CONSTRAINT [DEFAULT_'+TABLE_NAME+'_'+COLUMN_NAME+'] DEFAULT (''3/6/2018 6:47:23 PM'') FOR ['+COLUMN_NAME+']; 
GO' AS '[CODE]'
FROM INFORMATION_SCHEMA.COLUMNS
WHERE TABLE_NAME LIKE 'form_%' AND TABLE_SCHEMA = 'dbo'
 AND (COLUMN_NAME = 'FormInserted' OR COLUMN_NAME = 'FormUpdated')
 AND DATA_TYPE = 'datetime'
-- create temp table 
CREATE TABLE temp_table_alter
(
column_name varchar(255)    
);

-- insert those coulmns in temp table for which we nee to alter size of columns 
INSERT INTO temp_table_alter (column_name) VALUES ('colm1');
INSERT INTO temp_table_alter (column_name) VALUES ('colm2');
INSERT INTO temp_table_alter (column_name) VALUES ('colm3');
INSERT INTO temp_table_alter (column_name) VALUES ('colm4');

DECLARE @col_name_var varchar(255);
DECLARE alter_table_cursor CURSOR FOR
select column_name from temp_table_alter ;

OPEN alter_table_cursor
FETCH NEXT FROM alter_table_cursor INTO @col_name_var
WHILE @@FETCH_STATUS = 0
 BEGIN

 PRINT('ALTER COLUMN ' + @col_name_var);
 EXEC ('ALTER TABLE Original-table  ALTER COLUMN ['+ @col_name_var + '] DECIMAL(11,2);')

 FETCH NEXT FROM alter_table_cursor INTO @col_name_var
 END

CLOSE alter_table_cursor
DEALLOCATE alter_table_cursor

-- at the end drop temp table
drop table temp_table_alter;

正如其他人回答的那样,您需要多个ALTER TABLE语句。 试一试:

ALTER TABLE tblcommodityOHLC alter column CC_CommodityContractID NUMERIC(18,0);
ALTER TABLE tblcommodityOHLC alter column CM_CommodityID NUMERIC(18,0);
select 'ALTER TABLE ' + OBJECT_NAME(o.object_id) + 
    ' ALTER COLUMN ' + c.name + ' DATETIME2 ' + 
    CASE WHEN c.is_nullable = 0 THEN 'NOT NULL' ELSE 'NULL' END
from sys.objects o
inner join sys.columns c on o.object_id = c.object_id
inner join sys.types t on c.system_type_id = t.system_type_id
where o.type='U'
and c.name = 'Timestamp'
and t.name = 'datetime'
order by OBJECT_NAME(o.object_id)

由devio提供