我想写一个带out参数的async方法,像这样:
public async void Method1()
{
int op;
int result = await GetDataTaskAsync(out op);
}
我如何做到这一点在GetDataTaskAsync?
我想写一个带out参数的async方法,像这样:
public async void Method1()
{
int op;
int result = await GetDataTaskAsync(out op);
}
我如何做到这一点在GetDataTaskAsync?
当前回答
模式匹配来拯救!c# 9(我认为)之后:
// example of a method that would traditionally would use an out parameter
public async Task<(bool success, int? value)> TryGetAsync()
{
int? value = // get it from somewhere
return (value.HasValue, value);
}
像这样使用它:
if (await TryGetAsync() is (true, int value))
{
Console.WriteLine($"This is the value: {value}");
}
其他回答
c# 7+的解决方案是使用隐式元组语法。
private async Task<(bool IsSuccess, IActionResult Result)> TryLogin(OpenIdConnectRequest request)
{
return (true, BadRequest(new OpenIdErrorResponse
{
Error = OpenIdConnectConstants.Errors.AccessDenied,
ErrorDescription = "Access token provided is not valid."
}));
}
返回结果使用方法签名定义的属性名。例句:
var foo = await TryLogin(request);
if (foo.IsSuccess)
return foo.Result;
我有同样的问题,因为我喜欢使用Try-method-pattern,基本上似乎与async- wait-paradigm不兼容…
对我来说重要的是,我可以在一个if-子句中调用try -方法,而不必预先定义out-变量,但可以像下面的例子那样内联执行:
if (TryReceive(out string msg))
{
// use msg
}
所以我提出了以下解决方案:
注意:新的解决方案更优越,因为它可以与在这里的许多其他答案中描述的仅返回元组的方法一起使用,这可能经常在现有代码中找到!
新的解决方案:
Create extension methods for ValueTuples: public static class TupleExtensions { public static bool TryOut<P2>(this ValueTuple<bool, P2> tuple, out P2 p2) { bool p1; (p1, p2) = tuple; return p1; } public static bool TryOut<P2, P3>(this ValueTuple<bool, P2, P3> tuple, out P2 p2, out P3 p3) { bool p1; (p1, p2, p3) = tuple; return p1; } // continue to support larger tuples... } Define async Try-method like this: public async Task<(bool, string)> TryReceiveAsync() { string message; bool success; // ... return (success, message); } Call the async Try-method like this: if ((await TryReceiveAsync()).TryOut(out string msg)) { // use msg }
旧的解决方案:
Define a helper struct: public struct AsyncOut<T, OUT> { private readonly T returnValue; private readonly OUT result; public AsyncOut(T returnValue, OUT result) { this.returnValue = returnValue; this.result = result; } public T Out(out OUT result) { result = this.result; return returnValue; } public T ReturnValue => returnValue; public static implicit operator AsyncOut<T, OUT>((T returnValue ,OUT result) tuple) => new AsyncOut<T, OUT>(tuple.returnValue, tuple.result); } Define async Try-method like this: public async Task<AsyncOut<bool, string>> TryReceiveAsync() { string message; bool success; // ... return (success, message); } Call the async Try-method like this: if ((await TryReceiveAsync()).Out(out string msg)) { // use msg }
对于多个out参数,您可以定义额外的结构(例如AsyncOut<T,OUT1, OUT2>),或者您可以返回一个元组。
这与Michael Gehling提供的答案非常相似,但我有自己的解决方案,直到我找到了他的解决方案,并注意到我不是第一个想到使用隐式转换的人。
无论如何,当nullable设置为启用时,我也想共享
public readonly struct TryResult<TOut>
{
#region constructors
public TryResult(bool success, TOut? value) => (Success, Value) = (success, value);
#endregion
#region properties
public bool Success { get; init; }
[MemberNotNullWhen(true, nameof(Success))] public TOut? Value { get; init; }
#endregion
#region methods
public static implicit operator bool(TryResult<TOut> result) => result.Success;
public static implicit operator TryResult<TOut>(TOut value) => new (true, value);
public void Deconstruct(out bool success, out TOut? value) => (success, value) = (Success, Value);
public TryResult<TOut> Out([NotNullWhen(true)] out TOut? value)
{
value = Value;
return this;
}
#endregion
}
然后你可以像这样写一个Try方法:
public static async Task<TryResult<byte[]>> TryGetBytesAsync(string file) =>
File.Exists(file)
? await File.ReadAllBytesAsync(file)
: default(TryResult<byte[]>);
像这样叫它:
if ((await TryGetBytesAsync(file)).Out(out var bytes))
Console.WriteLine($"File has {bytes.Length} bytes.");
您可以通过使用TPL(任务并行库)而不是直接使用await关键字来做到这一点。
private bool CheckInCategory(int? id, out Category category)
{
if (id == null || id == 0)
category = null;
else
category = Task.Run(async () => await _context.Categories.FindAsync(id ?? 0)).Result;
return category != null;
}
if(!CheckInCategory(int? id, out var category)) return error
你不能有带ref或out参数的异步方法。
Lucian Wischik解释了为什么这是不可能的MSDN线程:http://social.msdn.microsoft.com/Forums/en-US/d2f48a52-e35a-4948-844d-828a1a6deb74/why-async-methods-cannot-have-ref-or-out-parameters
As for why async methods don't support out-by-reference parameters? (or ref parameters?) That's a limitation of the CLR. We chose to implement async methods in a similar way to iterator methods -- i.e. through the compiler transforming the method into a state-machine-object. The CLR has no safe way to store the address of an "out parameter" or "reference parameter" as a field of an object. The only way to have supported out-by-reference parameters would be if the async feature were done by a low-level CLR rewrite instead of a compiler-rewrite. We examined that approach, and it had a lot going for it, but it would ultimately have been so costly that it'd never have happened.
对于这种情况,一个典型的解决方法是让async方法返回一个元组。 你可以像这样重写你的方法:
public async Task Method1()
{
var tuple = await GetDataTaskAsync();
int op = tuple.Item1;
int result = tuple.Item2;
}
public async Task<Tuple<int, int>> GetDataTaskAsync()
{
//...
return new Tuple<int, int>(1, 2);
}