如果你使用org。JSONObject有一个toMap()方法。 你可以轻松做到:

Map<String, Object> myMap = myJsonObject.toMap();

java库可以将json字符串转换为哈希映射。我是这个项目的维护者。

代码示例:

import com.github.underscore.U;
import java.util.*;

public class Main {

    @SuppressWarnings("unchecked")
    public static void main(String[] args) {
        String json = "{"
            + "    \"data\" :"
            + "    {"
            + "        \"field1\" : \"value1\","
            + "        \"field2\" : \"value2\""
            + "    }"
            + "}";

       Map<String, Object> data = (Map) U.get((Map<String, Object>) U.fromJson(json), "data");
       System.out.println(data);

       // {field1=value1, field2=value2}
    }
}

如果你需要没有任何依赖的纯Java，你可以使用Java 8中内置的Nashorn API。在Java 11中已弃用。

这对我来说很管用:

...
import javax.script.ScriptEngine;
import javax.script.ScriptEngineManager;
import javax.script.ScriptException;
...

public class JsonUtils {

    public static Map parseJSON(String json) throws ScriptException {
        ScriptEngineManager sem = new ScriptEngineManager();
        ScriptEngine engine = sem.getEngineByName("javascript");

        String script = "Java.asJSONCompatible(" + json + ")";

        Object result = engine.eval(script);

        return (Map) result;
    }
}

示例使用

JSON:

{
    "data":[
        {"id":1,"username":"bruce"},
        {"id":2,"username":"clark"},
        {"id":3,"username":"diana"}
    ]
}

代码:

...
import jdk.nashorn.internal.runtime.JSONListAdapter;
...

public static List<String> getUsernamesFromJson(Map json) {
    List<String> result = new LinkedList<>();

    JSONListAdapter data = (JSONListAdapter) json.get("data");

    for(Object obj : data) {
        Map map = (Map) obj;
        result.add((String) map.get("username"));
    }

    return result;
}

使用GSON库:

import com.google.gson.Gson;
import com.google.common.reflect.TypeToken;
import java.lang.reclect.Type;

使用以下代码:

Type mapType = new TypeToken<Map<String, Map>>(){}.getType();  
Map<String, String[]> son = new Gson().fromJson(easyString, mapType);

我的文章可能会对其他人有所帮助，所以想象一下你有一个带有特定对象值的地图，就像这样:

{  
   "shopping_list":{  
      "996386":{  
         "id":996386,
         "label":"My 1st shopping list",
         "current":true,
         "nb_reference":6
      },
      "888540":{  
         "id":888540,
         "label":"My 2nd shopping list",
         "current":false,
         "nb_reference":2
      }
   }
}

用GSON库解析这个JSON文件很简单: 如果你的项目是maven化的

<dependency>
    <groupId>com.google.code.gson</groupId>
    <artifactId>gson</artifactId>
    <version>2.3.1</version>
</dependency>

然后使用下面的片段:

import com.google.gson.Gson;
import com.google.gson.JsonElement;
import com.google.gson.JsonObject;
import com.google.gson.JsonParser;

//Read the JSON file
JsonElement root = new JsonParser().parse(new FileReader("/path/to/the/json/file/in/your/file/system.json"));

//Get the content of the first map
JsonObject object = root.getAsJsonObject().get("shopping_list").getAsJsonObject();

//Iterate over this map
Gson gson = new Gson();
for (Entry<String, JsonElement> entry : object.entrySet()) {
    ShoppingList shoppingList = gson.fromJson(entry.getValue(), ShoppingList.class);
    System.out.println(shoppingList.getLabel());
}

对应的POJO应该是这样的:

public class ShoppingList {

    int id;

    String label;

    boolean current;

    int nb_reference;

    //Setters & Getters !!!!!
}

希望能有所帮助!

使用JSON库，例如http://www.json.org/java/

// Assume you have a Map<String, String> in JSONObject jdata
@SuppressWarnings("unchecked")
Iterator<String> nameItr = jdata.keys();
Map<String, String> outMap = new HashMap<String, String>();
while(nameItr.hasNext()) {
    String name = nameItr.next();
    outMap.put(name, jdata.getString(name));

}