如何在Python中列出目录中的所有文件并将其添加到列表中?


当前回答

从目录及其所有子目录获取完整文件路径

import os

def get_filepaths(directory):
    """
    This function will generate the file names in a directory 
    tree by walking the tree either top-down or bottom-up. For each 
    directory in the tree rooted at directory top (including top itself), 
    it yields a 3-tuple (dirpath, dirnames, filenames).
    """
    file_paths = []  # List which will store all of the full filepaths.

    # Walk the tree.
    for root, directories, files in os.walk(directory):
        for filename in files:
            # Join the two strings in order to form the full filepath.
            filepath = os.path.join(root, filename)
            file_paths.append(filepath)  # Add it to the list.

    return file_paths  # Self-explanatory.

# Run the above function and store its results in a variable.   
full_file_paths = get_filepaths("/Users/johnny/Desktop/TEST")

我在上述函数中提供的路径包含3个文件,其中两个位于根目录中,另一个位于名为“subfolder”的子文件夹中打印将打印列表的完整文件路径:['/Users/johnny/Desktop/TEST/file1.txt','/Users/johnny/Desctop/TEST-file2.txt','/Users/johnny/Desktop/STEST/SUBFOLDER/file3.dat']

如果愿意,您可以打开并阅读内容,或者只关注扩展名为“.dat”的文件,如下面的代码所示:

for f in full_file_paths:
  if f.endswith(".dat"):
    print f

/用户/johnny/Desktop/TEST/SUBFOLDER/file3.dat

其他回答

def list_files(path):
    # returns a list of names (with extension, without full path) of all files 
    # in folder path
    files = []
    for name in os.listdir(path):
        if os.path.isfile(os.path.join(path, name)):
            files.append(name)
    return files 
import os
os.listdir("somedirectory")

将返回“somedirectory”中所有文件和目录的列表。

dircache是“自2.6版以来已弃用:Python 3.0中已删除dircache模块。”

import dircache
list = dircache.listdir(pathname)
i = 0
check = len(list[0])
temp = []
count = len(list)
while count != 0:
  if len(list[i]) != check:
     temp.append(list[i-1])
     check = len(list[i])
  else:
    i = i + 1
    count = count - 1

print temp

仅获取文件列表(无子目录)的单行解决方案:

filenames = next(os.walk(path))[2]

或绝对路径名:

paths = [os.path.join(path, fn) for fn in next(os.walk(path))[2]]

使用发电机

import os
def get_files(search_path):
     for (dirpath, _, filenames) in os.walk(search_path):
         for filename in filenames:
             yield os.path.join(dirpath, filename)
list_files = get_files('.')
for filename in list_files:
    print(filename)