在swift 3.0中，您可以将整数更改为字符串，如下所示

let a:String = String(stringInterpolationSegment: 15)

另一种方法是

let number: Int = 15
let _numberInStringFormate: String = String(number)

//或任何整数来代替15

为了在将来节省你的时间和麻烦，你可以做一个Int扩展。通常我会创建一个共享代码文件，在其中放置扩展名、枚举和其他有趣的东西。下面是扩展代码的样子:

extension Int
{
    func toString() -> String
    {
        var myString = String(self)
        return myString
    }
}

之后，当你想将int型转换为字符串时，你可以这样做:

var myNumber = 0
var myNumberAsString = myNumber.toString()

我更喜欢使用字符串插值

let x = 45
let string = "\(x)"

每个对象都有一些字符串表示。这样事情就简单多了。例如，如果您需要创建具有多个值的字符串。你也可以在里面做任何数学运算或者使用一些条件

let text = "\(count) \(count > 1 ? "items" : "item") in the cart. Sum: $\(sum + shippingPrice)"

弦乐演奏

稍微讲讲性能 UI测试包在iPhone 7(真实设备)与iOS 14

let i = 0
lt result1 = String(i) //0.56s 5890kB
lt result2 = "\(i)" //0.624s 5900kB
lt result3 = i.description //0.758s 5890kB

import XCTest

class ConvertIntToStringTests: XCTestCase {
    let count = 1_000_000
    
    func measureFunction(_ block: () -> Void) {
        let metrics: [XCTMetric] = [
            XCTClockMetric(),
            XCTMemoryMetric()
        ]
        let measureOptions = XCTMeasureOptions.default
        measureOptions.iterationCount = 5
        
        measure(metrics: metrics, options: measureOptions) {
            block()
        }
    }

    func testIntToStringConstructor() {
        var result = ""
        measureFunction {
            for i in 0...count {
                result += String(i)
            }
        }
    }
    
    func testIntToStringInterpolation() {
        var result = ""
        measureFunction {
            for i in 0...count {
                result += "\(i)"
            }
        }
    }
    
    func testIntToStringDescription() {
        var result = ""
        measureFunction {
            for i in 0...count {
                result += i.description
            }
        }
    }
}

有多种方法:

var str1:String="\(23)"
var str2:String=String(format:"%d",234)

将Unicode Int转换为字符串

对于那些想要将Int转换为Unicode字符串的人，您可以执行以下操作:

let myInteger: Int = 97

// convert Int to a valid UnicodeScalar
guard let myUnicodeScalar = UnicodeScalar(myInteger) else {
    return ""
}

// convert UnicodeScalar to String
let myString = String(myUnicodeScalar)

// results
print(myString) // a

或者:

let myInteger: Int = 97
if let myUnicodeScalar = UnicodeScalar(myInteger) {
    let myString = String(myUnicodeScalar)
}