我有一个函数,返回5个混合大小写字符。如果我对这个字符串进行查询,不管大小写,它都会返回值。

如何使MySQL字符串查询区分大小写?


当前回答

太好了!

我和你们分享一个比较密码的函数的代码:

SET pSignal =
(SELECT DECODE(r.usignal,'YOURSTRINGKEY') FROM rsw_uds r WHERE r.uname =
in_usdname AND r.uvige = 1);

SET pSuccess =(SELECT in_usdsignal LIKE BINARY pSignal);

IF pSuccess = 1 THEN
      /*Your code if match*/
ELSE
      /*Your code if don't match*/

END IF;

其他回答

下面是MySQL版本等于或高于5.5的情况。

添加到/etc/mysql/my.cnf

  [mysqld]
  ...
  character-set-server=utf8
  collation-server=utf8_bin
  ...

我尝试的所有其他排序似乎都不区分大小写,只有“utf8_bin”有效。

在这之后不要忘记重新启动mysql:

   sudo service mysql restart

根据http://dev.mysql.com/doc/refman/5.0/en/case-sensitivity.html,还有一个“latin1_bin”。

“utf8_general_cs”不被mysql启动接受。(我把“_cs”读成“区分大小写”- ??)

Mysql默认情况下不区分大小写,请尝试将语言排序规则更改为latin1_general_cs

太好了!

我和你们分享一个比较密码的函数的代码:

SET pSignal =
(SELECT DECODE(r.usignal,'YOURSTRINGKEY') FROM rsw_uds r WHERE r.uname =
in_usdname AND r.uvige = 1);

SET pSuccess =(SELECT in_usdsignal LIKE BINARY pSignal);

IF pSuccess = 1 THEN
      /*Your code if match*/
ELSE
      /*Your code if don't match*/

END IF;

http://dev.mysql.com/doc/refman/5.0/en/case-sensitivity.html

The default character set and collation are latin1 and latin1_swedish_ci, so nonbinary string comparisons are case insensitive by default. This means that if you search with col_name LIKE 'a%', you get all column values that start with A or a. To make this search case sensitive, make sure that one of the operands has a case sensitive or binary collation. For example, if you are comparing a column and a string that both have the latin1 character set, you can use the COLLATE operator to cause either operand to have the latin1_general_cs or latin1_bin collation:

col_name COLLATE latin1_general_cs LIKE 'a%'
col_name LIKE 'a%' COLLATE latin1_general_cs
col_name COLLATE latin1_bin LIKE 'a%'
col_name LIKE 'a%' COLLATE latin1_bin

如果希望始终以区分大小写的方式对待列,请使用区分大小写或二进制排序规则来声明它。

不使用=运算符,您可能希望使用LIKE或LIKE二进制

// this returns 1 (true)
select 'A' like 'a'

// this returns 0 (false)
select 'A' like binary 'a'


select * from user where username like binary 'a'

在它的条件下,它会取a和不取a