Gson还可以用于序列化任意复杂的对象。

下面是如何使用它:

Gson gson = new Gson(); 
String json = gson.toJson(myObject); 

Gson将自动将集合转换为JSON数组。Gson可以序列化私有字段并自动忽略瞬态字段。

对于使用org.json.simple的用户。JSONObject，你可以将映射转换为Json String并解析它来获得JSONObject。

JSONObject object = (JSONObject) new JSONParser().parse(JSONObject.toJSONString(map));

你可以使用XStream——它真的很方便。请看这里的例子

package com.thoughtworks.xstream.json.test;

import com.thoughtworks.xstream.XStream;
import com.thoughtworks.xstream.io.json.JettisonMappedXmlDriver;

public class WriteTest {

    public static void main(String[] args) {

      HashMap<String,String> map = new HashMap<String,String>();
      map.add("1", "a");
      map.add("2", "b");
      XStream xstream = new XStream(new JettisonMappedXmlDriver());

      System.out.println(xstream.toXML(map));       

    }

}

这个解决方案适用于复杂的json:

public Object toJSON(Object object) throws JSONException {
    if (object instanceof HashMap) {
        JSONObject json = new JSONObject();
        HashMap map = (HashMap) object;
        for (Object key : map.keySet()) {
            json.put(key.toString(), toJSON(map.get(key)));
        }
        return json;
    } else if (object instanceof Iterable) {
        JSONArray json = new JSONArray();
        for (Object value : ((Iterable) object)) {
            json.put(toJSON(value));
        }
        return json;
    }
    else {
        return object;
    }
}

使用json的示例

Map<String, Object> data = new HashMap<String, Object>();
    data.put( "name", "Mars" );
    data.put( "age", 32 );
    data.put( "city", "NY" );
    JSONObject json = new JSONObject();
    json.putAll( data );
    System.out.printf( "JSON: %s", json.toString(2) );

输出:

JSON: {
  "age": 32,
  "name": "Mars",
  "city": "NY"
}

你也可以尝试使用谷歌的GSON。谷歌的GSON是将Java对象转换为JSON表示形式的最佳库。

http://code.google.com/p/google-gson/

您可以使用Jackson将Map转换为JSON，如下所示:

Map<String,Object> map = new HashMap<>();
//You can convert any Object.
String[] value1 = new String[] { "value11", "value12", "value13" };
String[] value2 = new String[] { "value21", "value22", "value23" };
map.put("key1", value1);
map.put("key2", value2);
map.put("key3","string1");
map.put("key4","string2");

String json = new ObjectMapper().writeValueAsString(map);
System.out.println(json);

Jackson的Maven依赖:

<dependency>
    <groupId>com.fasterxml.jackson.core</groupId>
    <artifactId>jackson-core</artifactId>
    <version>2.5.3</version>
    <scope>compile</scope>
</dependency>

<dependency>
    <groupId>com.fasterxml.jackson.core</groupId>
    <artifactId>jackson-databind</artifactId>
    <version>2.5.3</version>
    <scope>compile</scope>
</dependency>

If you are using `JSONObject` library, you can convert map to `JSON` as follows: JSONObject Library: import org.json.JSONObject; Map<String, Object> map = new HashMap<>(); // Convert a map having list of values. String[] value1 = new String[] { "value11", "value12", "value13" }; String[] value2 = new String[] { "value21", "value22", "value23" }; map.put("key1", value1); map.put("key2", value2); JSONObject json = new JSONObject(map); System.out.println(json); Maven Dependencies for `JSONObject` : <dependency> <groupId>org.json</groupId> <artifactId>json</artifactId> <version>20140107</version> </dependency> Hope this will help. Happy coding.