import org.json.JSONObject;

    HashMap<Object, Object> map = new HashMap<>();
    String[] list={"Grader","Participant"};
    String[] list1={"Assistant","intern"};
    map.put("TeachingAssistant",list);
    map.put("Writer",list1);
    JSONObject jsonObject = new JSONObject(map);
    System.out.printf(jsonObject.toString());

    // Result: {"TeachingAssistant":["Grader","Participant"],"Writer":["Assistant","intern"]}

你可以使用XStream——它真的很方便。请看这里的例子

package com.thoughtworks.xstream.json.test;

import com.thoughtworks.xstream.XStream;
import com.thoughtworks.xstream.io.json.JettisonMappedXmlDriver;

public class WriteTest {

    public static void main(String[] args) {

      HashMap<String,String> map = new HashMap<String,String>();
      map.add("1", "a");
      map.add("2", "b");
      XStream xstream = new XStream(new JettisonMappedXmlDriver());

      System.out.println(xstream.toXML(map));       

    }

}

这通常是Json库的工作，你不应该尝试自己做。所有json库都应该实现您所要求的内容，而且您可以做到 在页面底部的json.org上找到Java Json库的列表。

如果你正在使用net.sf.json.JSONObject，那么你不会在其中找到JSONObject(map)构造函数。您必须使用公共静态JSONObject fromObject(对象对象)方法。该方法接受JSON格式的字符串、map、dynabean和javabean。

JSONObject jsonObject = JSONObject.fromObject（myMap）;

    import org.json.JSONObject;

    HashMap<Object, Object> map = new HashMap<>();
    String[] list={"Grader","Participant"};
    String[] list1={"Assistant","intern"};
    map.put("TeachingAssistant",list);
    map.put("Writer",list1);
    JSONObject jsonObject = new JSONObject(map);
    System.out.printf(jsonObject.toString());

    // Result: {"TeachingAssistant":["Grader","Participant"],"Writer":["Assistant","intern"]}

对于使用org.json.simple的用户。JSONObject，你可以将映射转换为Json String并解析它来获得JSONObject。

JSONObject object = (JSONObject) new JSONParser().parse(JSONObject.toJSONString(map));