考虑使用最接近的

$('table+table form').closest('tr').filter(':not(:last-child)').submit(function (ev, frm) {
        frm = $(ev.target).closest('form');
        $.ajax({
            type: frm.attr('method'),
            url: frm.attr('action'),
            data: frm.serialize(),
            success: function (data) {
                alert(data);
            }
        })
        ev.preventDefault();
    });

这段代码甚至可以使用文件输入

$(document).on("submit", "form", function(event)
{
    event.preventDefault();        
    $.ajax({
        url: $(this).attr("action"),
        type: $(this).attr("method"),
        dataType: "JSON",
        data: new FormData(this),
        processData: false,
        contentType: false,
        success: function (data, status)
        {

        },
        error: function (xhr, desc, err)
        {


        }
    });        
});

JavaScript

(function ($) {
    var form= $('#add-form'),
      input = $('#exampleFormControlTextarea1');


   form.submit(function(event) {

       event.preventDefault(); 

       var req = $.ajax({
           url: form.attr('action'),
           type: 'POST',
           data: form.serialize()
       });
    req.done(function(data) {
       if (data === 'success') {
           var li = $('<li class="list-group-item">'+ input.val() +'</li>');
            li.hide()
                .appendTo('.list-group')
                .fadeIn();
            $('input[type="text"],textarea').val('');
        }
   });
});


}(jQuery));

HTML

    <ul class="list-group col-sm-6 float-left">
            <?php
            foreach ($data as $item) {
                echo '<li class="list-group-item">'.$item.'</li>';
            }
            ?>
        </ul>

        <form id="add-form" class="col-sm-6 float-right" action="_inc/add-new.php" method="post">
            <p class="form-group">
                <textarea class="form-control" name="message" id="exampleFormControlTextarea1" rows="3" placeholder="Is there something new?"></textarea>
            </p>
            <button type="submit" class="btn btn-danger">Add new item</button>
        </form>

如果你使用form.serialize() -你需要给每个表单元素一个这样的名字:

<input id="firstName" name="firstName" ...

表单像这样被序列化:

firstName=Chris&lastName=Halcrow ...

Try

fetch(form.action,{method:'post', body: new FormData(form)});

function send(e,form) { fetch(form.action,{method:'post', body: new FormData(form)}); console.log('We submit form asynchronously (AJAX)'); e.preventDefault(); } <form method="POST" action="myapi/send" onsubmit="send(event,this)" name="orderproductForm"> <input hidden name="csrfToken" value="$0meh@$h"> <input name="email" value="aa@bb.com"> <input name="phone" value="123-456-666"> <input type="submit"> </form> Look on Chrome Console > Network after/before 'submit'

这是一个简单的参考:

// this is the id of the form
$("#idForm").submit(function(e) {

    e.preventDefault(); // avoid to execute the actual submit of the form.

    var form = $(this);
    var actionUrl = form.attr('action');
    
    $.ajax({
        type: "POST",
        url: actionUrl,
        data: form.serialize(), // serializes the form's elements.
        success: function(data)
        {
          alert(data); // show response from the php script.
        }
    });
    
});