假设您在HTML表单中创建了一个向导。一个按钮后退，一个按钮前进。因为当您按Enter键时，返回按钮首先出现在标记中，它将使用该按钮提交表单。
例子:
< >形式 <！—将光标移至该字段，按“Enter”。—> <input type="text" name="field1" /> <！这是提交的按钮——> <input type="submit" name="prev" value="Previous Page" /> <！——但这是我想提交的按钮——> <input type="submit" name="next" value=" next Page" /> > < /形式
我想要确定当用户按Enter键时使用哪个按钮提交表单。这样，当您按下Enter键时，向导将移动到下一页，而不是上一页。你必须使用tabindex来做这个吗?
当前回答
我用这种方法解决了一个非常相似的问题:
If JavaScript is enabled (in most cases nowadays) then all the submit buttons are "degraded" to buttons at page load via JavaScript (jQuery). Click events on the "degraded" button typed buttons are also handled via JavaScript. If JavaScript is not enabled then the form is served to the browser with multiple submit buttons. In this case hitting Enter on a textfield within the form will submit the form with the first button instead of the intended default, but at least the form is still usable: you can submit with both the prev and next buttons.
工作的例子:
<html> <head> <script src="https://ajax.googleapis.com/ajax/libs/jquery/1.12.4/jquery.min.js"></script> </head> <body> <form action="http://httpbin.org/post" method="post"> If JavaScript is disabled, then you CAN submit the form with button1, button2 or button3. If you press enter on a text field, then the form is submitted with the first submit button. If JavaScript is enabled, then the submit typed buttons without the 'defaultSubmitButton' style are converted to button typed buttons. If you press Enter on a text field, then the form is submitted with the only submit button (the one with class defaultSubmitButton) If you click on any other button in the form, then the form is submitted with that button's value. <br /> <input type="text" name="text1" ></input> <button type="submit" name="action" value="button1" >button 1</button> <br /> <input type="text" name="text2" ></input> <button type="submit" name="action" value="button2" >button 2</button> <br /> <input type="text" name="text3" ></input> <button class="defaultSubmitButton" type="submit" name="action" value="button3" >default button</button> </form> <script> $(document).ready(function(){ /* Change submit typed buttons without the 'defaultSubmitButton' style to button typed buttons */ $('form button[type=submit]').not('.defaultSubmitButton').each(function(){ $(this).attr('type', 'button'); }); /* Clicking on button typed buttons results in: 1. Setting the form's submit button's value to the clicked button's value, 2. Clicking on the form's submit button */ $('form button[type=button]').click(function( event ){ var form = event.target.closest('form'); var submit = $("button[type='submit']",form).first(); submit.val(event.target.value); submit.click(); }); }); </script> </body> </html>
其他回答
这是我尝试过的:
你需要确保你给你的按钮不同的名字 编写if语句，在单击任意一个按钮时执行所需的操作。
<form>
<input type="text" name="field1" /> <!-- Put your cursor in this field and press Enter -->
<input type="submit" name="prev" value="Previous Page" /> <!-- This is the button that will submit -->
<input type="submit" name="next" value="Next Page" /> <!-- But this is the button that I WANT to submit -->
</form>
在PHP中,
if(isset($_POST['prev']))
{
header("Location: previous.html");
die();
}
if(isset($_POST['next']))
{
header("Location: next.html");
die();
}
将之前的按钮类型更改为这样的按钮:
<input type="button" name="prev" value="Previous Page" />
现在Next按钮将是默认的，另外你也可以添加默认属性，这样你的浏览器就会高亮显示它:
<input type="submit" name="next" value="Next Page" default />
从https://html.spec.whatwg.org/multipage/forms.html implicit-submission
表单元素的默认按钮是树中的第一个提交按钮 它的表单所有者是该表单元素。 如果用户代理支持让用户隐式提交表单 (例如，在某些平台上，在输入文本时按下“enter”键 字段被隐式聚焦提交表单)…
将下一个输入设置为type="submit"，并将前一个输入更改为type="button"，应该会得到所需的默认行为。
<form>
<input type="text" name="field1" /> <!-- put your cursor in this field and press Enter -->
<input type="button" name="prev" value="Previous Page" /> <!-- This is the button that will submit -->
<input type="submit" name="next" value="Next Page" /> <!-- But this is the button that I WANT to submit -->
</form>
我将使用JavaScript提交表单。该函数将由表单元素的OnKeyPress事件触发，并检测是否选择了Enter键。如果是这种情况，它将提交表单。
这里有两页给出了如何做到这一点的技巧:1、2。基于这些，下面是一个用法示例(基于这里):
<SCRIPT TYPE="text/javascript">//<!--
function submitenter(myfield,e) {
var keycode;
if (window.event) {
keycode = window.event.keyCode;
} else if (e) {
keycode = e.which;
} else {
return true;
}
if (keycode == 13) {
myfield.form.submit();
return false;
} else {
return true;
}
}
//--></SCRIPT>
<INPUT NAME="MyText" TYPE="Text" onKeyPress="return submitenter(this,event)" />
另一个简单的选项是将返回按钮放在HTML代码中的提交按钮之后，但将其浮动到左侧，这样它就会出现在提交按钮之前的页面上。
要做到这一点，只需改变制表符顺序即可。保持简单。
