假设您在HTML表单中创建了一个向导。一个按钮后退，一个按钮前进。因为当您按Enter键时，返回按钮首先出现在标记中，它将使用该按钮提交表单。
例子:
< >形式 <！—将光标移至该字段，按“Enter”。—> <input type="text" name="field1" /> <！这是提交的按钮——> <input type="submit" name="prev" value="Previous Page" /> <！——但这是我想提交的按钮——> <input type="submit" name="next" value=" next Page" /> > < /形式
我想要确定当用户按Enter键时使用哪个按钮提交表单。这样，当您按下Enter键时，向导将移动到下一页，而不是上一页。你必须使用tabindex来做这个吗?
当前回答
我认为这是一个简单的解决方法。将Previous按钮类型更改为button，并添加一个新的onclick属性，值为jQuery(this).attr('type'，'submit');
因此，当用户单击Previous按钮时，它的类型将被更改为submit，表单将与Previous按钮一起提交。
<form>
<!-- Put your cursor in this field and press Enter -->
<input type="text" name="field1" />
<!-- This is the button that will submit -->
<input type="button" onclick="jQuery(this).attr('type','submit');" name="prev" value="Previous Page" />
<!-- But this is the button that I WANT to submit -->
<input type="submit" name="next" value="Next Page" />
</form>
其他回答
我用这种方法解决了一个非常相似的问题:
If JavaScript is enabled (in most cases nowadays) then all the submit buttons are "degraded" to buttons at page load via JavaScript (jQuery). Click events on the "degraded" button typed buttons are also handled via JavaScript. If JavaScript is not enabled then the form is served to the browser with multiple submit buttons. In this case hitting Enter on a textfield within the form will submit the form with the first button instead of the intended default, but at least the form is still usable: you can submit with both the prev and next buttons.
工作的例子:
<html> <head> <script src="https://ajax.googleapis.com/ajax/libs/jquery/1.12.4/jquery.min.js"></script> </head> <body> <form action="http://httpbin.org/post" method="post"> If JavaScript is disabled, then you CAN submit the form with button1, button2 or button3. If you press enter on a text field, then the form is submitted with the first submit button. If JavaScript is enabled, then the submit typed buttons without the 'defaultSubmitButton' style are converted to button typed buttons. If you press Enter on a text field, then the form is submitted with the only submit button (the one with class defaultSubmitButton) If you click on any other button in the form, then the form is submitted with that button's value. <br /> <input type="text" name="text1" ></input> <button type="submit" name="action" value="button1" >button 1</button> <br /> <input type="text" name="text2" ></input> <button type="submit" name="action" value="button2" >button 2</button> <br /> <input type="text" name="text3" ></input> <button class="defaultSubmitButton" type="submit" name="action" value="button3" >default button</button> </form> <script> $(document).ready(function(){ /* Change submit typed buttons without the 'defaultSubmitButton' style to button typed buttons */ $('form button[type=submit]').not('.defaultSubmitButton').each(function(){ $(this).attr('type', 'button'); }); /* Clicking on button typed buttons results in: 1. Setting the form's submit button's value to the clicked button's value, 2. Clicking on the form's submit button */ $('form button[type=button]').click(function( event ){ var form = event.target.closest('form'); var submit = $("button[type='submit']",form).first(); submit.val(event.target.value); submit.click(); }); }); </script> </body> </html>
当我第一次遇到这种情况时，我想出了一个onclick()/JavaScript hack，当选择不是prev/next时，我仍然喜欢它的简单性。它是这样的:
@model myApp.Models.myModel
<script type="text/javascript">
function doOperation(op) {
document.getElementById("OperationId").innerText = op;
// you could also use Ajax to reference the element.
}
</script>
<form>
<input type="text" id = "TextFieldId" name="TextField" value="" />
<input type="hidden" id="OperationId" name="Operation" value="" />
<input type="submit" name="write" value="Write" onclick='doOperation("Write")'/>
<input type="submit" name="read" value="Read" onclick='doOperation("Read")'/>
</form>
当单击任何一个提交按钮时，它将所需的操作存储在一个隐藏字段中(该字段是包含在与表单关联的模型中的字符串字段)，并将表单提交给控制器，由控制器进行所有决定。在控制器中，你只需写:
// Do operation according to which submit button was clicked
// based on the contents of the hidden Operation field.
if (myModel.Operation == "Read")
{
// Do read logic
}
else if (myModel.Operation == "Write")
{
// Do write logic
}
else
{
// Do error logic
}
您还可以使用数值操作代码来避免字符串解析，但是除非使用枚举，否则代码可读性较差、可修改性较差、自文档性较差，解析也很简单。
有时palotasb提供的解决方案是不够的。有一些用例，例如“Filter”提交按钮被放置在“Next和Previous”按钮之上。我找到了一个解决办法:复制提交按钮，这需要作为默认提交按钮在一个隐藏的div，并把它放在任何其他提交按钮上面的表单。
从技术上讲，当按下Enter时，它将由不同的按钮提交，而不是单击可见的Next按钮。但是由于名称和值是相同的，所以结果没有区别。
<html> <head> <style> div.defaultsubmitbutton { display: none; } </style> </head> <body> <form action="action" method="get"> <div class="defaultsubmitbutton"> <input type="submit" name="next" value="Next"> </div> <p><input type="text" name="filter"><input type="submit" value="Filter"></p> <p>Filtered results</p> <input type="radio" name="choice" value="1">Filtered result 1 <input type="radio" name="choice" value="2">Filtered result 2 <input type="radio" name="choice" value="3">Filtered result 3 <div> <input type="submit" name="prev" value="Prev"> <input type="submit" name="next" value="Next"> </div> </form> </body> </html>
我只是让按钮向右浮动。
这样，Prev按钮在Next按钮的左边，但在HTML结构中Next在前面:
.f { 浮:正确; ｝ .clr { 明确:; ｝ <form action="action" method="get"> <input type="text" name="abc"> < div id = "按钮" > <input type="submit" class="f" name="next" value=" next" > <input type="submit" class="f" name="prev" value=" prev" > < div class = " clr " > < / div > < !这个div可以防止后面的元素随按钮一起浮动。保持他们“内部”div#按钮—> < / div > > < /形式
优于其他建议的优点:没有JavaScript代码，可访问，两个按钮都保持type="submit"。
给你的提交按钮设置相同的名称，就像这样:
<input type="submit" name="submitButton" value="Previous Page" />
<input type="submit" name="submitButton" value="Next Page" />
当用户按下Enter并将请求发送到服务器时，您可以在服务器端代码中检查submitButton的值，该代码包含一组表单名称/值对。例如，在ASP Classic中:
If Request.Form("submitButton") = "Previous Page" Then
' Code for the previous page
ElseIf Request.Form("submitButton") = "Next Page" Then
' Code for the next page
End If
参考:在一个表单上使用多个提交按钮
