我也遇到了同样的情况。我尝试了超时解决方案，但不可靠。我发现如果你只调用它两次，位置就会正确刷新

function getLocation(callback)
{   
    if(navigator.geolocation)
    {
        navigator.geolocation.getCurrentPosition(function(position)
        {
            navigator.geolocation.getCurrentPosition(callback, function(){},{maximumAge:0, timeout:10000});
        },function(){}, {maximumAge:0, timeout:10000});
    }
    return true;
}

这当然是有点慢，但我没有给我错误的位置一次。我有它击中超时几次，没有返回任何东西，但除此之外，它工作得很好。我知道这仍然有点老套，我期待有人找到真正的解决方案。

或者，如果你想确保它会一直尝试，直到你想放弃，你可以试试这样的方法。

//example
$(document).ready(function(){
    getLocation(function(position){
        //do something cool with position
        console.log(position);
    });
});


var GPSTimeout = 10; //init global var NOTE: I noticed that 10 gives me the quickest result but play around with this number to your own liking


//function to be called where you want the location with the callback(position)
function getLocation(callback)
{   
    if(navigator.geolocation)
    {
        var clickedTime = (new Date()).getTime(); //get the current time
        GPSTimeout = 10; //reset the timeout just in case you call it more then once
        ensurePosition(callback, clickedTime); //call recursive function to get position
    }
    return true;
}

//recursive position function
function ensurePosition(callback, timestamp)
{
    if(GPSTimeout < 6000)//set at what point you want to just give up
    {
        //call the geolocation function
        navigator.geolocation.getCurrentPosition(
            function(position) //on success
        {
                //if the timestamp that is returned minus the time that was set when called is greater then 0 the position is up to date
            if(position.timestamp - timestamp >= 0)
                {
                    GPSTimeout = 10; //reset timeout just in case
                    callback(position); //call the callback function you created
                }
                else //the gps that was returned is not current and needs to be refreshed
                {
                    GPSTimeout += GPSTimeout; //increase the timeout by itself n*2
                    ensurePosition(callback, timestamp); //call itself to refresh
                }
            },
            function() //error: gps failed so we will try again
            {
                GPSTimeout += GPSTimeout; //increase the timeout by itself n*2
                ensurePosition(callback, timestamp);//call itself to try again
            },
            {maximumAge:0, timeout:GPSTimeout}
        )
    }       
}

我可能在这里有一些打字和拼写错误，但我希望你能明白。如果有人有问题或者找到更好的建议，请告诉我。

对于开发iPhone应用程序的人来说……

如果你的代码在ios9 +的UIWebView中运行，那么你必须在应用的plist中设置NSLocationWhenInUseUsageDescription。

如果你不设置它，那么getCurrentPosition将永远不会回调，用户也永远不会被提示。

在我们的例子中，它总是第一次工作，但重新运行函数3-4次以上，它就失败了。

简单的解决方法:将其值存储在LocalStorage中。

之前:

navigator.geolocation.getCurrentPosition((position) => {
  let val = results[0].address_components[2].long_name;
  doSthWithVal(val);      
}, (error) => { });

后:

if(localStorage.getItem('getCurrentPosition') !== null) {
  doSthWithVal(localStorage.getItem('getCurrentPosition'));
}
else {
  navigator.geolocation.getCurrentPosition((position) => {
      let val = results[0].address_components[2].long_name;
      localStorage.setItem('getCurrentPosition',val);
      doSthWithVal(val);      
  }, (error) => { });
}

你不会得到一个错误消息，因为默认情况下它没有超时(至少我认为)。我用firefox也遇到过同样的问题，只是对我来说，firefox总是超时。您可以像这样自己设置一个超时。

我的功能在chrome中工作得很好，但我每次在firefox中都会超时。

    navigator.geolocation.getCurrentPosition(
        function(position) {
            //do succes handling
        },
        function errorCallback(error) {
            //do error handling
        },
        {
            timeout:5000
        }
    );

我建议你仔细观察你的错误。一切都被期待。为每件事都准备一个备份计划。我使用一些默认值或值从我的数据库自己的情况下谷歌地理位置和导航地理位置失败。

我发现，这种方法行不通

navigator.geolocation.getCurrentPosition(function() {...}, function(err) {...}, {});

But

这种方法非常有效

function storeCoordinates(position) {
    console.log(position.coords.latitude, position.coords.longitude);
}    

function errorHandler() {...}

navigator.geolocation.getCurrentPosition(storeCoordinates, errorHandler, { enableHighAccuracy: true, timeout: 20000, maximumAge: 0 });

传递给geolocation . getcurrentposition()的第二个参数是要处理任何地理位置错误的函数。错误处理函数本身接收一个PositionError对象，其中包含关于地理定位尝试失败原因的详细信息。我建议输出错误到控制台，如果你有任何问题:

var positionOptions = { timeout: 10000 };
navigator.geolocation.getCurrentPosition(updateLocation, errorHandler, positionOptions);
function updateLocation(position) {
  // The geolocation succeeded, and the position is available
}
function errorHandler(positionError) {
  if (window.console) {
    console.log(positionError);
  }
}

Doing this in my code revealed the message "Network location provider at 'https://www.googleapis.com/' : Returned error code 400". Turns out Google Chrome uses the Google APIs to get a location on devices that don't have GPS built in (for example, most desktop computers). Google returns an approximate latitude/longitude based on the user's IP address. However, in developer builds of Chrome (such as Chromium on Ubuntu) there is no API access key included in the browser build. This causes the API request to fail silently. See Chromium Issue 179686: Geolocation giving 403 error for details.