我使用Java，我有一个JSON字符串:
{
"name" : "abc" ,
"email id " : ["abc@gmail.com","def@gmail.com","ghi@gmail.com"]
}
然后是我的Java地图:
Map<String, Object> retMap = new HashMap<String, Object>();
我想把所有来自JSONObject的数据存储在那个HashMap中。
有人能为此提供代码吗?我想用org。json库。
当前回答
如果你讨厌递归-使用Stack和javax。将一个json字符串转换成一个地图列表:
import java.io.InputStream;
import java.util.ArrayList;
import java.util.HashMap;
import java.util.List;
import java.util.Map;
import java.util.Stack;
import javax.json.Json;
import javax.json.stream.JsonParser;
public class TestCreateObjFromJson {
public static List<Map<String,Object>> extract(InputStream is) {
List extracted = new ArrayList<>();
JsonParser parser = Json.createParser(is);
String nextKey = "";
Object nextval = "";
Stack s = new Stack<>();
while(parser.hasNext()) {
JsonParser.Event event = parser.next();
switch(event) {
case START_ARRAY : List nextList = new ArrayList<>();
if(!s.empty()) {
// If this is not the root object, add it to tbe parent object
setValue(s,nextKey,nextList);
}
s.push(nextList);
break;
case START_OBJECT : Map<String,Object> nextMap = new HashMap<>();
if(!s.empty()) {
// If this is not the root object, add it to tbe parent object
setValue(s,nextKey,nextMap);
}
s.push(nextMap);
break;
case KEY_NAME : nextKey = parser.getString();
break;
case VALUE_STRING : setValue(s,nextKey,parser.getString());
break;
case VALUE_NUMBER : setValue(s,nextKey,parser.getLong());
break;
case VALUE_TRUE : setValue(s,nextKey,true);
break;
case VALUE_FALSE : setValue(s,nextKey,false);
break;
case VALUE_NULL : setValue(s,nextKey,"");
break;
case END_OBJECT :
case END_ARRAY : if(s.size() > 1) {
// If this is not a root object, move up
s.pop();
} else {
// If this is a root object, add ir ro rhw final
extracted.add(s.pop());
}
default : break;
}
}
return extracted;
}
private static void setValue(Stack s, String nextKey, Object v) {
if(Map.class.isAssignableFrom(s.peek().getClass()) ) ((Map)s.peek()).put(nextKey, v);
else ((List)s.peek()).add(v);
}
}
其他回答
最新更新:我已经使用fastxmljackson Databind2.12.3转换JSON字符串到映射，映射到JSON字符串。
// javax.ws.rs.core.Response clientresponse = null; // Read JSON with Jersey 2.0 (JAX-RS 2.0)
// String json_string = clientresponse.readEntity(String.class);
String json_string = "[\r\n"
+ "{\"domain\":\"stackoverflow.com\", \"userId\":5081877, \"userName\":\"Yash\"},\r\n"
+ "{\"domain\":\"stackoverflow.com\", \"userId\":6575754, \"userName\":\"Yash\"}\r\n"
+ "]";
System.out.println("Input/Response JSON string:"+json_string);
ObjectMapper mapper = new com.fasterxml.jackson.databind.ObjectMapper();
//java.util.Map<String, String> map = mapper.readValue(json_string, java.util.Map.class);
List<Map<String, Object>> listOfMaps = mapper.readValue(json_string, new com.fasterxml.jackson.core.type.TypeReference< List<Map<String, Object>>>() {});
System.out.println("fasterxml JSON string to List of Map:"+listOfMaps);
String json = mapper.writeValueAsString(listOfMaps);
System.out.println("fasterxml List of Map to JSON string:[compact-print]"+json);
json = mapper.writerWithDefaultPrettyPrinter().writeValueAsString(listOfMaps);
System.out.println("fasterxml List of Map to JSON string:[pretty-print]"+json);
输出:
Input/Response JSON string:[
{"domain":"stackoverflow.com", "userId":5081877, "userName":"Yash"},
{"domain":"stackoverflow.com", "userId":6575754, "userName":"Yash"}
]
fasterxml JSON string to List of Map:[{domain=stackoverflow.com, userId=5081877, userName=Yash}, {domain=stackoverflow.com, userId=6575754, userName=Yash}]
fasterxml List of Map to JSON string:[compact-print][{"domain":"stackoverflow.com","userId":5081877,"userName":"Yash"},{"domain":"stackoverflow.com","userId":6575754,"userName":"Yash"}]
fasterxml List of Map to JSON string:[pretty-print][ {
"domain" : "stackoverflow.com",
"userId" : 5081877,
"userName" : "Yash"
}, {
"domain" : "stackoverflow.com",
"userId" : 6575754,
"userName" : "Yash"
} ]
将JSON字符串转换为Map
public static java.util.Map<String, Object> jsonString2Map( String jsonString ) throws org.json.JSONException {
Map<String, Object> keys = new HashMap<String, Object>();
org.json.JSONObject jsonObject = new org.json.JSONObject( jsonString ); // HashMap
java.util.Iterator<?> keyset = jsonObject.keys(); // HM
while (keyset.hasNext()) {
String key = (String) keyset.next();
Object value = jsonObject.get(key);
System.out.print("\n Key : "+key);
if ( value instanceof org.json.JSONObject ) {
System.out.println("Incomin value is of JSONObject : ");
keys.put( key, jsonString2Map( value.toString() ));
} else if ( value instanceof org.json.JSONArray) {
org.json.JSONArray jsonArray = jsonObject.getJSONArray(key);
//JSONArray jsonArray = new JSONArray(value.toString());
keys.put( key, jsonArray2List( jsonArray ));
} else {
keyNode( value);
keys.put( key, value );
}
}
return keys;
}
将JSON数组转换为列表
public static java.util.List<Object> jsonArray2List( org.json.JSONArray arrayOFKeys ) throws org.json.JSONException {
System.out.println("Incoming value is of JSONArray : =========");
java.util.List<Object> array2List = new java.util.ArrayList<Object>();
for ( int i = 0; i < arrayOFKeys.length(); i++ ) {
if ( arrayOFKeys.opt(i) instanceof org.json.JSONObject ) {
Map<String, Object> subObj2Map = jsonString2Map(arrayOFKeys.opt(i).toString());
array2List.add(subObj2Map);
} else if ( arrayOFKeys.opt(i) instanceof org.json.JSONArray ) {
java.util.List<Object> subarray2List = jsonArray2List((org.json.JSONArray) arrayOFKeys.opt(i));
array2List.add(subarray2List);
} else {
keyNode( arrayOFKeys.opt(i) );
array2List.add( arrayOFKeys.opt(i) );
}
}
return array2List;
}
public static Object keyNode(Object o) {
if (o instanceof String || o instanceof Character) return (String) o;
else if (o instanceof Number) return (Number) o;
else return o;
}
显示任意格式的JSON
public static void displayJSONMAP( Map<String, Object> allKeys ) throws Exception{
Set<String> keyset = allKeys.keySet(); // HM$keyset
if (! keyset.isEmpty()) {
Iterator<String> keys = keyset.iterator(); // HM$keysIterator
while (keys.hasNext()) {
String key = keys.next();
Object value = allKeys.get( key );
if ( value instanceof Map ) {
System.out.println("\n Object Key : "+key);
displayJSONMAP(jsonString2Map(value.toString()));
}else if ( value instanceof List ) {
System.out.println("\n Array Key : "+key);
JSONArray jsonArray = new JSONArray(value.toString());
jsonArray2List(jsonArray);
}else {
System.out.println("key : "+key+" value : "+value);
}
}
}
}
谷歌。gson到HashMap。
使用JSON -simple，您可以将数据JSON转换为映射和映射到JSON。
try
{
JSONObject obj11 = new JSONObject();
obj11.put(1, "Kishan");
obj11.put(2, "Radhesh");
obj11.put(3, "Sonal");
obj11.put(4, "Madhu");
Map map = new HashMap();
obj11.toJSONString();
map = obj11;
System.out.println(map.get(1));
JSONObject obj12 = new JSONObject();
obj12 = (JSONObject) map;
System.out.println(obj12.get(1));
}
catch(Exception e)
{
System.err.println("EROR : 01 :"+e);
}
使用Jackson转换:
JSONObject obj = new JSONObject().put("abc", "pqr").put("xyz", 5);
Map<String, Object> map = new ObjectMapper().readValue(obj.toString(), new TypeReference<Map<String, Object>>() {});
想象一下你有如下的邮件列表。不受任何编程语言的限制，
emailsList = ["abc@gmail.com","def@gmail.com","ghi@gmail.com"]
下面是JAVA代码-用于将json转换为map
JSONObject jsonObj = new JSONObject().put("name","abc").put("email id",emailsList);
Map<String, Object> s = jsonObj.getMap();
希望这能起作用，试试这个:
import com.fasterxml.jackson.databind.ObjectMapper;
Map<String, Object> response = new ObjectMapper().readValue(str, HashMap.class);
str，你的JSON字符串
就这么简单，如果你想要电子邮件，
String emailIds = response.get("email id").toString();
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