如果你讨厌递归-使用Stack和javax。将一个json字符串转换成一个地图列表:

import java.io.InputStream;
import java.util.ArrayList;
import java.util.HashMap;
import java.util.List;
import java.util.Map;
import java.util.Stack;
import javax.json.Json;
import javax.json.stream.JsonParser;

public class TestCreateObjFromJson {
    public static List<Map<String,Object>> extract(InputStream is) {
        List extracted = new ArrayList<>();
        JsonParser parser = Json.createParser(is);

        String nextKey = "";
        Object nextval = "";
        Stack s = new Stack<>();
        while(parser.hasNext()) {
            JsonParser.Event event = parser.next();
            switch(event) {
                case START_ARRAY :  List nextList = new ArrayList<>();
                                    if(!s.empty()) {
                                        // If this is not the root object, add it to tbe parent object
                                        setValue(s,nextKey,nextList);
                                    }
                                    s.push(nextList);
                                    break;
                case START_OBJECT : Map<String,Object> nextMap = new HashMap<>();
                                    if(!s.empty()) {
                                        // If this is not the root object, add it to tbe parent object
                                        setValue(s,nextKey,nextMap);
                                    }
                                    s.push(nextMap);
                                    break;
                case KEY_NAME : nextKey = parser.getString();
                                break;
                case VALUE_STRING : setValue(s,nextKey,parser.getString());
                                    break;
                case VALUE_NUMBER : setValue(s,nextKey,parser.getLong());
                                    break;
                case VALUE_TRUE :   setValue(s,nextKey,true);
                                    break;
                case VALUE_FALSE :  setValue(s,nextKey,false);
                                    break;
                case VALUE_NULL :   setValue(s,nextKey,"");
                                    break;
                case END_OBJECT :   
                case END_ARRAY  :   if(s.size() > 1) {
                                        // If this is not a root object, move up
                                        s.pop(); 
                                    } else {
                                        // If this is a root object, add ir ro rhw final 
                                        extracted.add(s.pop()); 
                                    }
                default         :   break;
            }
        }

        return extracted;
    }

    private static void setValue(Stack s, String nextKey, Object v) {
        if(Map.class.isAssignableFrom(s.peek().getClass()) ) ((Map)s.peek()).put(nextKey, v);
        else ((List)s.peek()).add(v);
    }
}

如果你想要无库版本，这里是与regex的解决方案:

public static HashMap<String, String> jsonStringToMap(String inputJsonString) {
    final String regex = "(?:\\\"|\\')(?<key>[\\w\\d]+)(?:\\\"|\\')(?:\\:\\s*)(?:\\\"|\\')?(?<value>[\\w\\s-]*)(?:\\\"|\\')?";
    HashMap<String, String> map = new HashMap<>();
    final Pattern pattern = Pattern.compile(regex, Pattern.MULTILINE);
    final Matcher matcher = pattern.matcher(inputJsonString);

    while (matcher.find()) {
        for (int i = 1; i <= matcher.groupCount(); i++) {
            map.put(matcher.group("key"), matcher.group("value"));
        }
    }
    return map;
}

希望这能起作用，试试这个:

import com.fasterxml.jackson.databind.ObjectMapper;
Map<String, Object> response = new ObjectMapper().readValue(str, HashMap.class);

str，你的JSON字符串

就这么简单，如果你想要电子邮件，

String emailIds = response.get("email id").toString();

You can convert any JSON to map by using Jackson library as below: String json = "{\r\n\"name\" : \"abc\" ,\r\n\"email id \" : [\"abc@gmail.com\",\"def@gmail.com\",\"ghi@gmail.com\"]\r\n}"; ObjectMapper mapper = new ObjectMapper(); Map<String, Object> map = new HashMap<String, Object>(); // convert JSON string to Map map = mapper.readValue(json, new TypeReference<Map<String, Object>>() {}); System.out.println(map); Maven Dependencies for Jackson : <dependency> <groupId>com.fasterxml.jackson.core</groupId> <artifactId>jackson-core</artifactId> <version>2.5.3</version> <scope>compile</scope> </dependency> <dependency> <groupId>com.fasterxml.jackson.core</groupId> <artifactId>jackson-databind</artifactId> <version>2.5.3</version> <scope>compile</scope> </dependency> Hope this will help. Happy coding :)

这是一个老问题，但可能仍然与某些人有关。 假设你有字符串HashMap hash和JsonObject JsonObject。

1)定义键列表。 例子:

ArrayList<String> keyArrayList = new ArrayList<>();  
keyArrayList.add("key0");   
keyArrayList.add("key1");  

2)创建foreach循环，从jsonObject中添加哈希:

for(String key : keyArrayList){  
    hash.put(key, jsonObject.getString(key));
}

这就是我的方法，希望它能回答问题。

想象一下你有如下的邮件列表。不受任何编程语言的限制，

emailsList = ["abc@gmail.com","def@gmail.com","ghi@gmail.com"]

下面是JAVA代码-用于将json转换为map

JSONObject jsonObj = new JSONObject().put("name","abc").put("email id",emailsList);
Map<String, Object> s = jsonObj.getMap();