我使用Java,我有一个JSON字符串:

{
"name" : "abc" ,
"email id " : ["abc@gmail.com","def@gmail.com","ghi@gmail.com"]
}

然后是我的Java地图:

Map<String, Object> retMap = new HashMap<String, Object>();

我想把所有来自JSONObject的数据存储在那个HashMap中。

有人能为此提供代码吗?我想用org。json库。


当前回答

希望这能起作用,试试这个:

import com.fasterxml.jackson.databind.ObjectMapper;
Map<String, Object> response = new ObjectMapper().readValue(str, HashMap.class);

str,你的JSON字符串

就这么简单,如果你想要电子邮件,

String emailIds = response.get("email id").toString();

其他回答

import java.util.ArrayList;
import java.util.HashMap;
import java.util.Iterator;
import java.util.List;
import java.util.Map;

import org.json.simple.JSONArray;
import org.json.simple.JSONObject;


public class JsonUtils {

    public static Map<String, Object> jsonToMap(JSONObject json) {
        Map<String, Object> retMap = new HashMap<String, Object>();

        if(json != null) {
            retMap = toMap(json);
        }
        return retMap;
    }

    public static Map<String, Object> toMap(JSONObject object) {
        Map<String, Object> map = new HashMap<String, Object>();

        Iterator<String> keysItr = object.keySet().iterator();
        while(keysItr.hasNext()) {
            String key = keysItr.next();
            Object value = object.get(key);

            if(value instanceof JSONArray) {
                value = toList((JSONArray) value);
            }

            else if(value instanceof JSONObject) {
                value = toMap((JSONObject) value);
            }
            map.put(key, value);
        }
        return map;
    }

    public static List<Object> toList(JSONArray array) {
        List<Object> list = new ArrayList<Object>();
        for(int i = 0; i < array.size(); i++) {
            Object value = array.get(i);
            if(value instanceof JSONArray) {
                value = toList((JSONArray) value);
            }

            else if(value instanceof JSONObject) {
                value = toMap((JSONObject) value);
            }
            list.add(value);
        }
        return list;
    }
}

你也可以使用Jackson API:

    final String json = "....your json...";
    final ObjectMapper mapper = new ObjectMapper();
    final MapType type = mapper.getTypeFactory().constructMapType(
        Map.class, String.class, Object.class);
    final Map<String, Object> data = mapper.readValue(json, type);

使用Jackson转换:

JSONObject obj = new JSONObject().put("abc", "pqr").put("xyz", 5);

Map<String, Object> map = new ObjectMapper().readValue(obj.toString(), new TypeReference<Map<String, Object>>() {});

我只用了Gson

HashMap<String, Object> map = new Gson().fromJson(json.toString(), HashMap.class);

希望这能起作用,试试这个:

import com.fasterxml.jackson.databind.ObjectMapper;
Map<String, Object> response = new ObjectMapper().readValue(str, HashMap.class);

str,你的JSON字符串

就这么简单,如果你想要电子邮件,

String emailIds = response.get("email id").toString();