我试图实现一些沿着for-each的线,我想采取返回的选择语句的id,并使用它们中的每一个。

DECLARE @i int
DECLARE @PractitionerId int
DECLARE @numrows int
DECLARE @Practitioner TABLE (
    idx smallint Primary Key IDENTITY(1,1)
    , PractitionerId int
)

INSERT @Practitioner
SELECT distinct PractitionerId FROM Practitioner

SET @i = 1
SET @numrows = (SELECT COUNT(*) FROM Practitioner)
IF @numrows > 0
    WHILE (@i <= (SELECT MAX(idx) FROM Practitioner))
    BEGIN

        SET @PractitionerId = (SELECT PractitionerId FROM @Practitioner WHERE idx = @i)

        --Do something with Id here
        PRINT @PractitionerId

        SET @i = @i + 1
    END

目前我有一些看起来像上面的东西,但我得到了错误:

无效的列名'idx'。


当前回答

您的select count和select max应该来自您的表变量,而不是实际的表

DECLARE @i int
DECLARE @PractitionerId int
DECLARE @numrows int
DECLARE @Practitioner TABLE (
    idx smallint Primary Key IDENTITY(1,1)
    , PractitionerId int
)

INSERT @Practitioner
SELECT distinct PractitionerId FROM Practitioner

SET @i = 1
SET @numrows = (SELECT COUNT(*) FROM @Practitioner)
IF @numrows > 0
    WHILE (@i <= (SELECT MAX(idx) FROM @Practitioner))
    BEGIN

        SET @PractitionerId = (SELECT PractitionerId FROM @Practitioner WHERE idx = @i)

        --Do something with Id here
        PRINT @PractitionerId

        SET @i = @i + 1
    END

其他回答

您似乎想要使用游标。尽管大多数时候最好使用基于集合的解决方案,但有时CURSOR是最佳解决方案。在不了解你的实际问题的情况下,我们帮不了你:

DECLARE @PractitionerId int

DECLARE MY_CURSOR CURSOR 
  LOCAL STATIC READ_ONLY FORWARD_ONLY
FOR 
SELECT DISTINCT PractitionerId 
FROM Practitioner

OPEN MY_CURSOR
FETCH NEXT FROM MY_CURSOR INTO @PractitionerId
WHILE @@FETCH_STATUS = 0
BEGIN 
    --Do something with Id here
    PRINT @PractitionerId
    FETCH NEXT FROM MY_CURSOR INTO @PractitionerId
END
CLOSE MY_CURSOR
DEALLOCATE MY_CURSOR

这是一个更好的解决方案。

DECLARE @i int
            DECLARE @curren_val int
            DECLARE @numrows int
            create table #Practitioner (idx int IDENTITY(1,1), PractitionerId int)
            INSERT INTO #Practitioner (PractitionerId) values (10),(20),(30)
            SET @i = 1
            SET @numrows = (SELECT COUNT(*) FROM #Practitioner)
            IF @numrows > 0
            WHILE (@i <= (SELECT MAX(idx) FROM #Practitioner))
            BEGIN

                SET @curren_val = (SELECT PractitionerId FROM #Practitioner WHERE idx = @i)

                --Do something with Id here
                PRINT @curren_val
                SET @i = @i + 1
            END

这里我在表中添加了一些值,因为最初它是空的。

我们可以访问或在循环体中做任何事情,我们可以通过在表定义中定义idx来访问它。

              BEGIN
                SET @curren_val = (SELECT PractitionerId FROM #Practitioner WHERE idx = @i)

                --Do something with Id here

                PRINT @curren_val
                SET @i = @i + 1
            END

我想说,除了列idx在你选择的表中不存在之外,一切都可能正常。也许你想从@从业者中选择:

WHILE (@i <= (SELECT MAX(idx) FROM @Practitioner))

因为在上面的代码中是这样定义的:

DECLARE @Practitioner TABLE (
    idx smallint Primary Key IDENTITY(1,1)
    , PractitionerId int
)

在你的版本中,下面这行是错误的:

WHILE (@i <= (SELECT MAX(idx) FROM @Practitioner))

(没有@)

也许可以改变您的命名约定,使表更加不同。

您的select count和select max应该来自您的表变量,而不是实际的表

DECLARE @i int
DECLARE @PractitionerId int
DECLARE @numrows int
DECLARE @Practitioner TABLE (
    idx smallint Primary Key IDENTITY(1,1)
    , PractitionerId int
)

INSERT @Practitioner
SELECT distinct PractitionerId FROM Practitioner

SET @i = 1
SET @numrows = (SELECT COUNT(*) FROM @Practitioner)
IF @numrows > 0
    WHILE (@i <= (SELECT MAX(idx) FROM @Practitioner))
    BEGIN

        SET @PractitionerId = (SELECT PractitionerId FROM @Practitioner WHERE idx = @i)

        --Do something with Id here
        PRINT @PractitionerId

        SET @i = @i + 1
    END