如何将一些数据转移到另一个片段同样,它是做了额外的意图?
当前回答
getArguments()返回null因为“它没有得到任何东西”
试试这段代码来处理这种情况
if(getArguments()!=null)
{
int myInt = getArguments().getInt(key, defaultValue);
}
其他回答
使用片段传递数据的完整代码
Fragment fragment = new Fragment(); // replace your custom fragment class
Bundle bundle = new Bundle();
FragmentTransaction fragmentTransaction = getSupportFragmentManager().beginTransaction();
bundle.putString("key","value"); // use as per your need
fragment.setArguments(bundle);
fragmentTransaction.addToBackStack(null);
fragmentTransaction.replace(viewID,fragment);
fragmentTransaction.commit();
在自定义片段类中
Bundle mBundle = new Bundle();
mBundle = getArguments();
mBundle.getString(key); // key must be same which was given in first fragment
输入片段
public class SecondFragment extends Fragment {
EditText etext;
Button btn;
String etex;
@Override
public View onCreateView(LayoutInflater inflater, ViewGroup container, Bundle savedInstanceState) {
View v = inflater.inflate(R.layout.secondfragment, container, false);
etext = (EditText) v.findViewById(R.id.editText4);
btn = (Button) v.findViewById(R.id.button);
btn.setOnClickListener(mClickListener);
return v;
}
View.OnClickListener mClickListener = new View.OnClickListener() {
@Override
public void onClick(View v) {
etex = etext.getText().toString();
FragmentTransaction transection = getFragmentManager().beginTransaction();
Viewfragment mfragment = new Viewfragment();
//using Bundle to send data
Bundle bundle = new Bundle();
bundle.putString("textbox", etex);
mfragment.setArguments(bundle); //data being send to SecondFragment
transection.replace(R.id.frame, mfragment);
transection.isAddToBackStackAllowed();
transection.addToBackStack(null);
transection.commit();
}
};
}
你的视图片段
public class Viewfragment extends Fragment {
TextView txtv;
public View onCreateView(LayoutInflater inflater, ViewGroup container, Bundle savedInstanceState) {
View v = inflater.inflate(R.layout.viewfrag,container,false);
txtv = (TextView) v.findViewById(R.id.textView4);
Bundle bundle=getArguments();
txtv.setText(String.valueOf(bundle.getString("textbox")));
return v;
}
}
只是扩展一下前面的答案——它可以帮助到一些人。如果你的getArguments()返回null,把它放在onCreate()方法,而不是你的片段的构造函数:
@Override
public void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
int index = getArguments().getInt("index");
}
为了进一步扩展前面的答案,就像Ankit说的,对于复杂的对象,你需要实现Serializable。例如,对于简单对象:
public class MyClass implements Serializable {
private static final long serialVersionUID = -2163051469151804394L;
private int id;
private String created;
}
在你的FromFragment中:
Bundle args = new Bundle();
args.putSerializable(TAG_MY_CLASS, myClass);
Fragment toFragment = new ToFragment();
toFragment.setArguments(args);
getFragmentManager()
.beginTransaction()
.replace(R.id.body, toFragment, TAG_TO_FRAGMENT)
.addToBackStack(TAG_TO_FRAGMENT).commit();
在你的ToFragment:
@Override
public View onCreateView(LayoutInflater inflater, ViewGroup container,
Bundle savedInstanceState) {
Bundle args = getArguments();
MyClass myClass = (MyClass) args
.getSerializable(TAG_MY_CLASS);
使用Bundle。这里有一个例子:
Fragment fragment = new Fragment();
Bundle bundle = new Bundle();
bundle.putInt(key, value);
fragment.setArguments(bundle);
Bundle为许多数据类型提供了方法。看到这个
然后在你的片段,检索数据(例如在onCreate()方法):
Bundle bundle = this.getArguments();
if (bundle != null) {
int myInt = bundle.getInt(key, defaultValue);
}
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