我怎么能从今天的日期和一个人的出生日期找到一个python年龄?出生日期来自Django模型中的DateField。
当前回答
from datetime import date
def calculate_age(born):
today = date.today()
try:
birthday = born.replace(year=today.year)
except ValueError: # raised when birth date is February 29 and the current year is not a leap year
birthday = born.replace(year=today.year, month=born.month+1, day=1)
if birthday > today:
return today.year - born.year - 1
else:
return today.year - born.year
更新:使用丹尼的解决方案,效果更好
其他回答
如果你想用django模板打印在页面中,那么下面的代码就足够了:
{{ birth_date|timesince }}
from datetime import date
days_in_year = 365.2425
age = int((date.today() - birth_date).days / days_in_year)
在Python 3中,你可以对datetime.timedelta执行除法:
from datetime import date, timedelta
age = (date.today() - birth_date) // timedelta(days=365.2425)
serializers.py
age = serializers.SerializerMethodField('get_age')
class Meta:
model = YourModel
fields = [..,'','birthdate','age',..]
import datetime
def get_age(self, instance):
return datetime.datetime.now().year - instance.birthdate.year
最简单的方法是使用python-dateutil
import datetime
import dateutil
def birthday(date):
# Get the current date
now = datetime.datetime.utcnow()
now = now.date()
# Get the difference between the current date and the birthday
age = dateutil.relativedelta.relativedelta(now, date)
age = age.years
return age
进口日期时间
def age(date_of_birth):
if date_of_birth > datetime.date.today().replace(year = date_of_birth.year):
return datetime.date.today().year - date_of_birth.year - 1
else:
return datetime.date.today().year - date_of_birth.year
在你的情况下:
import datetime
# your model
def age(self):
if self.birthdate > datetime.date.today().replace(year = self.birthdate.year):
return datetime.date.today().year - self.birthdate.year - 1
else:
return datetime.date.today().year - self.birthdate.year
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