我有一张桌子
create table us
(
a number
);
现在我有如下数据:
a
1
2
3
4
null
null
null
8
9
现在我需要一个查询来计算列a中的空值和非空值
我有一张桌子
create table us
(
a number
);
现在我有如下数据:
a
1
2
3
4
null
null
null
8
9
现在我需要一个查询来计算列a中的空值和非空值
当前回答
这适用于Oracle和SQL Server(你可能可以让它在其他RDBMS上工作):
select sum(case when a is null then 1 else 0 end) count_nulls
, count(a) count_not_nulls
from us;
Or:
select count(*) - count(a), count(a) from us;
其他回答
用于计数非空值
select count(*) from us where a is not null;
用于计算空值
select count(*) from us where a is null;
试试这个. .
SELECT CASE
WHEN a IS NULL THEN 'Null'
ELSE 'Not Null'
END a,
Count(1)
FROM us
GROUP BY CASE
WHEN a IS NULL THEN 'Null'
ELSE 'Not Null'
END
正如我理解你的查询,你只需要运行这个脚本并获得Total Null,Total NotNull行,
select count(*) - count(a) as 'Null', count(a) as 'Not Null' from us;
所有的答案要么是错误的,要么是非常过时的。
执行此查询的简单而正确的方法是使用COUNT_IF函数。
SELECT
COUNT_IF(a IS NULL) AS nulls,
COUNT_IF(a IS NOT NULL) AS not_nulls
FROM
us
如果我理解正确,你想在一个列中计数所有NULL和所有NOT NULL…
如果是正确的:
SELECT count(*) FROM us WHERE a IS NULL
UNION ALL
SELECT count(*) FROM us WHERE a IS NOT NULL
阅读评论后,编辑了完整的查询:]
SELECT COUNT(*), 'null_tally' AS narrative
FROM us
WHERE a IS NULL
UNION
SELECT COUNT(*), 'not_null_tally' AS narrative
FROM us
WHERE a IS NOT NULL;