是否可以使用PowerShell创建zip存档?


当前回答

如果你安装了WinRAR:

function ZipUsingRar([String] $directory, [String] $zipFileName)
{
  Write-Output "Performing operation ""Zip File"" on Target ""Item: $directory Destination:"
  Write-Output ($zipFileName + """")
  $pathToWinRar = "c:\Program Files\WinRAR\WinRar.exe";
  [Array]$arguments = "a", "-afzip", "-df", "-ep1", "$zipFileName", "$directory";
  & $pathToWinRar $arguments;
}

参数的含义:afzip创建zip归档,df删除文件,ep1不创建归档内的完整目录路径

其他回答

这也可以在不使用临时文件夹的情况下压缩单个文件,并使用原生的。net 4.5,从c#转换到这个StackOverflow答案。它使用了更好的使用语法。

用法:

zipfile - zipfilen输出.zip -sourceFile输入。sql -file, inside.zip.sql

代码:

function ZipFiles([string] $zipFilename, [string] $sourceFile, [string] $filename)
{
    $fullSourceFile = (Get-Item -Path "$sourceFile" -Verbose).FullName
    $fullZipFile = (Get-Item -Path "$zipFilename" -Verbose).FullName

    Add-Type -AssemblyName System.IO
    Add-Type -AssemblyName System.IO.Compression
    Add-Type -AssemblyName System.IO.Compression.FileSystem

    Using-Object ($fs = New-Object System.IO.FileStream($fullZipFile, [System.IO.FileMode]::Create)) {
         Using-Object ($arch = New-Object System.IO.Compression.ZipArchive($fs, [System.IO.Compression.ZipArchiveMode]::Create)) {
             [System.IO.Compression.ZipFileExtensions]::CreateEntryFromFile($arch, $fullSourceFile, $filename)
        }
    }
}

使用:

function Using-Object
{
    [CmdletBinding()]
    param (
        [Parameter(Mandatory = $true)]
        [AllowEmptyString()]
        [AllowEmptyCollection()]
        [AllowNull()]
        [Object]
        $InputObject,

        [Parameter(Mandatory = $true)]
        [scriptblock]
        $ScriptBlock
    )

    try
    {
        . $ScriptBlock
    }
    finally
    {
        if ($null -ne $InputObject -and $InputObject -is [System.IDisposable])
        {
            $InputObject.Dispose()
        }
    }
}

下面是工作代码,压缩源文件夹中的所有文件,并在目标文件夹中创建一个zip文件。

    $DestZip="C:\Destination\"
    $Source = "C:\Source\"

    $folder = Get-Item -Path $Source

    $ZipTimestamp = Get-Date -format yyyyMMdd-HHmmss;
    $ZipFileName  = $DestZip + "Backup_" + $folder.name + "_" + $ZipTimestamp + ".zip" 

    $Source

    set-content $ZipFileName ("PK" + [char]5 + [char]6 + ("$([char]0)" * 18)) 
    # Wait for the zip file to be created.
    while (!(Test-Path -PathType leaf -Path $ZipFileName))
    {    
        Start-Sleep -Milliseconds 20
    } 
    $ZipFile = (new-object -com shell.application).NameSpace($ZipFileName)

    Write-Output (">> Waiting Compression : " + $ZipFileName)       

    #BACKUP - COPY
    $ZipFile.CopyHere($Source) 

    $ZipFileName
    # ARCHIVE

    Read-Host "Please Enter.."

Windows下压缩解压目录的完整命令行如下:

压缩: powershell.exe -nologo -noprofile -command "&{添加- type -A 'System.IO.Compression.FileSystem';[IO.Compression.ZipFile]:: CreateFromDirectory (C: \印度河,“C: \ Indus.zip”);}” 提取: powershell.exe -nologo -noprofile -command "& {Add-Type -A 'System.IO.Compression.FileSystem';[IO.Compression.ZipFile]::ExtractToDirectory('C:\ industrial .zip','C:\Indus');}”

编辑二——这段代码是一个非常丑陋的旧代码。你不会想要的。

这将使用system . io . package . zippackage将。\in文件的内容压缩为。\out.zip

$zipArchive = $pwd.path + "\out.zip"
[System.Reflection.Assembly]::Load("WindowsBase,Version=3.0.0.0, Culture=neutral, PublicKeyToken=31bf3856ad364e35")
$ZipPackage=[System.IO.Packaging.ZipPackage]::Open($zipArchive,
  [System.IO.FileMode]"OpenOrCreate", [System.IO.FileAccess]"ReadWrite")
$in = gci .\in | select -expand fullName
[array]$files = $in -replace "C:","" -replace "\\","/"
ForEach ($file In $files)
{
   $partName=New-Object System.Uri($file, [System.UriKind]"Relative")
   $part=$ZipPackage.CreatePart($partName, "application/zip",
      [System.IO.Packaging.CompressionOption]"Maximum")
   $bytes=[System.IO.File]::ReadAllBytes($file)
   $stream=$part.GetStream()
   $stream.Write($bytes, 0, $bytes.Length)
   $stream.Close()
}
$ZipPackage.Close()

编辑:不可靠的大文件,可能>10mb, YMMV。与appdomain证据和隔离存储有关。更友好的。net 4.5方法在PS v3上工作得很好,但在我的情况下需要更多的内存。要从PS v2使用. net 4,配置文件需要一个不受支持的调整。

System.IO.Packaging.ZipPackage呢?

它需要。net 3.0或更高版本。

#Load some assemblys. (No line break!)
[System.Reflection.Assembly]::Load("WindowsBase, Version=3.0.0.0, Culture=neutral, PublicKeyToken=31bf3856ad364e35")

#Create a zip file named "MyZipFile.zip". (No line break!)
$ZipPackage=[System.IO.Packaging.ZipPackage]::Open("C:\MyZipFile.zip",
   [System.IO.FileMode]"OpenOrCreate", [System.IO.FileAccess]"ReadWrite")

#The files I want to add to my archive:
$files = @("/Penguins.jpg", "/Lighthouse.jpg")

#For each file you want to add, we must extract the bytes
#and add them to a part of the zip file.
ForEach ($file In $files)
{
   $partName=New-Object System.Uri($file, [System.UriKind]"Relative")
   #Create each part. (No line break!)
   $part=$ZipPackage.CreatePart($partName, "",
      [System.IO.Packaging.CompressionOption]"Maximum")
   $bytes=[System.IO.File]::ReadAllBytes($file)
   $stream=$part.GetStream()
   $stream.Write($bytes, 0, $bytes.Length)
   $stream.Close()
}

#Close the package when we're done.
$ZipPackage.Close()

通过安德斯·赫塞尔博姆