我如何从十六进制字符串格式创建一个UIColor,如#00FF00?
当前回答
Swift 5, iOS 14
convenience init(hex: String, alpha: CGFloat = 1.0) {
var hexFormatted: String = hex.trimmingCharacters(in: CharacterSet.whitespacesAndNewlines).uppercased()
if hexFormatted.hasPrefix("#") {
hexFormatted = String(hexFormatted.dropFirst())
}
assert(hexFormatted.count == 6, "Invalid hex code used.")
var rgbValue: UInt64 = 0
Scanner(string: hexFormatted).scanHexInt64(&rgbValue)
self.init(red: CGFloat((rgbValue & 0xFF0000) >> 16) / 255.0,
green: CGFloat((rgbValue & 0x00FF00) >> 8) / 255.0,
blue: CGFloat(rgbValue & 0x0000FF) / 255.0,
alpha: alpha)
}
其他回答
上面的几个解决方案涉及到一些不必要的nsstring使用。这个UIColor类扩展更简单更快:
+ colorWithHex:(UInt32)hex alpha:(CGFloat)alpha
{
return [UIColor colorWithRed:((hex & 0xFF0000) >> 16)/255.0
green:((hex & 0x00FF00) >> 8)/255.0
blue:( hex & 0x0000FF)/255.0
alpha:alpha];
}
简单来说:
return [UIColor colorWithHex:0x006400 alpha:1.0]; // HTML darkgreen
swift 1.2更新
class func colorWithHexString (hex:String) -> UIColor {
var cString: NSString = hex.stringByTrimmingCharactersInSet(NSCharacterSet.whitespaceAndNewlineCharacterSet()).uppercaseString
if (cString.hasPrefix("#")) {
cString = cString.substringFromIndex(1)
}
if (count(cString as String) != 6) {
return UIColor.grayColor()
}
var rString: String = cString.substringToIndex(2)
var gString: String = (cString.substringFromIndex(2) as NSString).substringToIndex(2)
var bString: String = (cString.substringFromIndex(4) as NSString).substringToIndex(2)
var r:CUnsignedInt = 0, g:CUnsignedInt = 0, b:CUnsignedInt = 0;
NSScanner(string: rString).scanHexInt(&r)
NSScanner(string: gString).scanHexInt(&g)
NSScanner(string: bString).scanHexInt(&b)
return UIColor(red: CGFloat(Float(r) / 255.0), green: CGFloat(Float(g) / 255.0), blue: CGFloat(Float(b) / 255.0), alpha: CGFloat(1))
}
在swift中,我用以下方法创建了一个类扩展,将十六进制代码转换为UIColor。
extension UIColor {
convenience init(R: CGFloat, G: CGFloat, B: CGFloat, alpha: CGFloat) {
self.init(red: R/255.0, green: G/255.0, blue: B/255.0, alpha: alpha)
}
class func colorWithHex(hex: UInt, alpha: CGFloat) -> UIColor {
return UIColor(R: CGFloat((hex & 0xFF0000) >> 16), G: CGFloat((hex & 0x00FF00) >> 8), B: CGFloat(hex & 0x0000FF), alpha: alpha)
}
}
我找到了一个很好的UIColor类别,UIColor+PXExtensions。
用法:UIColor *mycolor = [UIColor pxColorWithHexValue:@"#BADA55"];
而且,为了防止链接到我的要点失败,这里是实际的实现代码:
//
// UIColor+PXExtensions.m
//
#import "UIColor+UIColor_PXExtensions.h"
@implementation UIColor (UIColor_PXExtensions)
+ (UIColor*)pxColorWithHexValue:(NSString*)hexValue
{
//Default
UIColor *defaultResult = [UIColor blackColor];
//Strip prefixed # hash
if ([hexValue hasPrefix:@"#"] && [hexValue length] > 1) {
hexValue = [hexValue substringFromIndex:1];
}
//Determine if 3 or 6 digits
NSUInteger componentLength = 0;
if ([hexValue length] == 3)
{
componentLength = 1;
}
else if ([hexValue length] == 6)
{
componentLength = 2;
}
else
{
return defaultResult;
}
BOOL isValid = YES;
CGFloat components[3];
//Seperate the R,G,B values
for (NSUInteger i = 0; i < 3; i++) {
NSString *component = [hexValue substringWithRange:NSMakeRange(componentLength * i, componentLength)];
if (componentLength == 1) {
component = [component stringByAppendingString:component];
}
NSScanner *scanner = [NSScanner scannerWithString:component];
unsigned int value;
isValid &= [scanner scanHexInt:&value];
components[i] = (CGFloat)value / 256.0f;
}
if (!isValid) {
return defaultResult;
}
return [UIColor colorWithRed:components[0]
green:components[1]
blue:components[2]
alpha:1.0];
}
@end
您可以使用各种在线工具将HEX字符串转换为实际的UIColor。查看uicolor.org或UI颜色选择器。输出将被转换为Objective-C代码,如下所示:
[UIColor colorWithRed:0.93 green:0.80 blue:0.80 alpha:1.0];
可以嵌入到应用程序中。希望这能有所帮助!
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