public static void main(String[] args) throws InterruptedException {
  //type code


  short z=1000;
  Thread.sleep(z);/*will provide 1 second delay. alter data type of z or value of z for longer delays required */

  //type code
}

eg:-

class TypeCasting {

  public static void main(String[] args) throws InterruptedException {
    short f = 1;
    int a = 123687889;
    short b = 2;
    long c = 4567;
    long d=45;
    short z=1000;
    System.out.println("Value of a,b and c are\n" + a + "\n" + b + "\n" + c + "respectively");
    c = a;
    b = (short) c;
    System.out.println("Typecasting...........");
    Thread.sleep(z);
    System.out.println("Value of B after Typecasting" + b);
    System.out.println("Value of A is" + a);


  }
}

你们有很多书要读。从编译器错误到异常处理，线程和线程中断。但这将达到你想要的效果:

try {
    Thread.sleep(1000);                 //1000 milliseconds is one second.
} catch(InterruptedException ex) {
    Thread.currentThread().interrupt();
}

正如其他用户所说的，你应该用try{…} catch{…}。但是自从Java 1.5发布以来，有了一个TimeUnit类，它的功能与Thread.sleep(millis)相同，但更方便。 您可以选择睡眠操作的时间单位。

try {
    TimeUnit.NANOSECONDS.sleep(100);
    TimeUnit.MICROSECONDS.sleep(100);
    TimeUnit.MILLISECONDS.sleep(100);
    TimeUnit.SECONDS.sleep(100);
    TimeUnit.MINUTES.sleep(100);
    TimeUnit.HOURS.sleep(100);
    TimeUnit.DAYS.sleep(100);
} catch (InterruptedException e) {
    //Handle exception
}

它还有其他的方法: TimeUnit Oracle文档

看看这篇关于如何正确做到这一点的简短文章。

本质上:捕获InterruptedException。记住，您必须添加这个捕获块。这篇文章对此作了进一步的解释。

使用下面的编码结构来处理异常

try {
  Thread.sleep(1000);
} catch (InterruptedException ie) {
    //Handle exception
}

试试这个:

try{

    Thread.sleep(100);
}catch(Exception e)
{
   System.out.println("Exception caught");
}