我尝试过延迟(或休眠)我的Java程序,但是出现了一个错误。

我无法使用Thread.sleep(x)或wait()。同样的错误信息出现:

interruptedexception;必须被捕获或宣布被丢弃。

在使用Thread.sleep()或wait()方法之前,是否需要任何步骤?


当前回答

Thread.sleep()对于初学者来说很简单,可能适用于单元测试和概念证明。

但是请不要在产品代码中使用sleep()。最终sleep()可能会狠狠地咬你一口。

多线程/多核java应用程序使用“线程等待”概念的最佳实践。Wait释放线程持有的所有锁和监控器,这允许其他线程获得这些监控器,并在您的线程平静睡眠时继续执行。

下面的代码演示了该技术:

import java.util.concurrent.TimeUnit;
public class DelaySample {
    public static void main(String[] args) {
       DelayUtil d = new DelayUtil();
       System.out.println("started:"+ new Date());
       d.delay(500);
       System.out.println("half second after:"+ new Date());
       d.delay(1, TimeUnit.MINUTES); 
       System.out.println("1 minute after:"+ new Date());
    }
}

DelayUtil实现:

import java.util.concurrent.TimeUnit;
import java.util.concurrent.locks.Condition;
import java.util.concurrent.locks.ReentrantLock;

public class DelayUtil {
    /** 
    *  Delays the current thread execution. 
    *  The thread loses ownership of any monitors. 
    *  Quits immediately if the thread is interrupted
    *  
    * @param durationInMillis the time duration in milliseconds
    */
   public void delay(final long durationInMillis) {
      delay(durationInMillis, TimeUnit.MILLISECONDS);
   }

   /** 
    * @param duration the time duration in the given {@code sourceUnit}
    * @param unit
    */
    public void delay(final long duration, final TimeUnit unit) {
        long currentTime = System.currentTimeMillis();
        long deadline = currentTime+unit.toMillis(duration);
        ReentrantLock lock = new ReentrantLock();
        Condition waitCondition = lock.newCondition();

        while ((deadline-currentTime)>0) {
            try {
                lock.lockInterruptibly();    
                waitCondition.await(deadline-currentTime, TimeUnit.MILLISECONDS);
            } catch (InterruptedException e) {
                Thread.currentThread().interrupt();
                return;
            } finally {
                lock.unlock();
            }
            currentTime = System.currentTimeMillis();
        }
    }
}

其他回答

试试这个:

try{

    Thread.sleep(100);
}catch(Exception e)
{
   System.out.println("Exception caught");
}

Thread.sleep()对于初学者来说很简单,可能适用于单元测试和概念证明。

但是请不要在产品代码中使用sleep()。最终sleep()可能会狠狠地咬你一口。

多线程/多核java应用程序使用“线程等待”概念的最佳实践。Wait释放线程持有的所有锁和监控器,这允许其他线程获得这些监控器,并在您的线程平静睡眠时继续执行。

下面的代码演示了该技术:

import java.util.concurrent.TimeUnit;
public class DelaySample {
    public static void main(String[] args) {
       DelayUtil d = new DelayUtil();
       System.out.println("started:"+ new Date());
       d.delay(500);
       System.out.println("half second after:"+ new Date());
       d.delay(1, TimeUnit.MINUTES); 
       System.out.println("1 minute after:"+ new Date());
    }
}

DelayUtil实现:

import java.util.concurrent.TimeUnit;
import java.util.concurrent.locks.Condition;
import java.util.concurrent.locks.ReentrantLock;

public class DelayUtil {
    /** 
    *  Delays the current thread execution. 
    *  The thread loses ownership of any monitors. 
    *  Quits immediately if the thread is interrupted
    *  
    * @param durationInMillis the time duration in milliseconds
    */
   public void delay(final long durationInMillis) {
      delay(durationInMillis, TimeUnit.MILLISECONDS);
   }

   /** 
    * @param duration the time duration in the given {@code sourceUnit}
    * @param unit
    */
    public void delay(final long duration, final TimeUnit unit) {
        long currentTime = System.currentTimeMillis();
        long deadline = currentTime+unit.toMillis(duration);
        ReentrantLock lock = new ReentrantLock();
        Condition waitCondition = lock.newCondition();

        while ((deadline-currentTime)>0) {
            try {
                lock.lockInterruptibly();    
                waitCondition.await(deadline-currentTime, TimeUnit.MILLISECONDS);
            } catch (InterruptedException e) {
                Thread.currentThread().interrupt();
                return;
            } finally {
                lock.unlock();
            }
            currentTime = System.currentTimeMillis();
        }
    }
}

放置你的线程。睡在一个尝试捕捉块

try {
    //thread to sleep for the specified number of milliseconds
    Thread.sleep(100);
} catch ( java.lang.InterruptedException ie) {
    System.out.println(ie);
}

一种更简单的等待方法是使用System.currentTimeMillis(),它返回自UTC 1970年1月1日午夜以来的毫秒数。例如,等待5秒:

public static void main(String[] args) {
    //some code
    long original = System.currentTimeMillis();
    while (true) {
        if (System.currentTimeMillis - original >= 5000) {
            break;
        }
    }
    //more code after waiting
}

这样,您就不必处理线程和异常。 希望这能有所帮助!

或者,如果你不想处理线程,试试这个方法:

public static void pause(int seconds){
    Date start = new Date();
    Date end = new Date();
    while(end.getTime() - start.getTime() < seconds * 1000){
        end = new Date();
    }
}

它在您调用它时开始,在秒数过去时结束。