我尝试过延迟(或休眠)我的Java程序,但是出现了一个错误。
我无法使用Thread.sleep(x)或wait()。同样的错误信息出现:
interruptedexception;必须被捕获或宣布被丢弃。
在使用Thread.sleep()或wait()方法之前,是否需要任何步骤?
我尝试过延迟(或休眠)我的Java程序,但是出现了一个错误。
我无法使用Thread.sleep(x)或wait()。同样的错误信息出现:
interruptedexception;必须被捕获或宣布被丢弃。
在使用Thread.sleep()或wait()方法之前,是否需要任何步骤?
当前回答
Thread.sleep()对于初学者来说很简单,可能适用于单元测试和概念证明。
但是请不要在产品代码中使用sleep()。最终sleep()可能会狠狠地咬你一口。
多线程/多核java应用程序使用“线程等待”概念的最佳实践。Wait释放线程持有的所有锁和监控器,这允许其他线程获得这些监控器,并在您的线程平静睡眠时继续执行。
下面的代码演示了该技术:
import java.util.concurrent.TimeUnit;
public class DelaySample {
public static void main(String[] args) {
DelayUtil d = new DelayUtil();
System.out.println("started:"+ new Date());
d.delay(500);
System.out.println("half second after:"+ new Date());
d.delay(1, TimeUnit.MINUTES);
System.out.println("1 minute after:"+ new Date());
}
}
DelayUtil实现:
import java.util.concurrent.TimeUnit;
import java.util.concurrent.locks.Condition;
import java.util.concurrent.locks.ReentrantLock;
public class DelayUtil {
/**
* Delays the current thread execution.
* The thread loses ownership of any monitors.
* Quits immediately if the thread is interrupted
*
* @param durationInMillis the time duration in milliseconds
*/
public void delay(final long durationInMillis) {
delay(durationInMillis, TimeUnit.MILLISECONDS);
}
/**
* @param duration the time duration in the given {@code sourceUnit}
* @param unit
*/
public void delay(final long duration, final TimeUnit unit) {
long currentTime = System.currentTimeMillis();
long deadline = currentTime+unit.toMillis(duration);
ReentrantLock lock = new ReentrantLock();
Condition waitCondition = lock.newCondition();
while ((deadline-currentTime)>0) {
try {
lock.lockInterruptibly();
waitCondition.await(deadline-currentTime, TimeUnit.MILLISECONDS);
} catch (InterruptedException e) {
Thread.currentThread().interrupt();
return;
} finally {
lock.unlock();
}
currentTime = System.currentTimeMillis();
}
}
}
其他回答
试试这个:
try{
Thread.sleep(100);
}catch(Exception e)
{
System.out.println("Exception caught");
}
Thread.sleep()对于初学者来说很简单,可能适用于单元测试和概念证明。
但是请不要在产品代码中使用sleep()。最终sleep()可能会狠狠地咬你一口。
多线程/多核java应用程序使用“线程等待”概念的最佳实践。Wait释放线程持有的所有锁和监控器,这允许其他线程获得这些监控器,并在您的线程平静睡眠时继续执行。
下面的代码演示了该技术:
import java.util.concurrent.TimeUnit;
public class DelaySample {
public static void main(String[] args) {
DelayUtil d = new DelayUtil();
System.out.println("started:"+ new Date());
d.delay(500);
System.out.println("half second after:"+ new Date());
d.delay(1, TimeUnit.MINUTES);
System.out.println("1 minute after:"+ new Date());
}
}
DelayUtil实现:
import java.util.concurrent.TimeUnit;
import java.util.concurrent.locks.Condition;
import java.util.concurrent.locks.ReentrantLock;
public class DelayUtil {
/**
* Delays the current thread execution.
* The thread loses ownership of any monitors.
* Quits immediately if the thread is interrupted
*
* @param durationInMillis the time duration in milliseconds
*/
public void delay(final long durationInMillis) {
delay(durationInMillis, TimeUnit.MILLISECONDS);
}
/**
* @param duration the time duration in the given {@code sourceUnit}
* @param unit
*/
public void delay(final long duration, final TimeUnit unit) {
long currentTime = System.currentTimeMillis();
long deadline = currentTime+unit.toMillis(duration);
ReentrantLock lock = new ReentrantLock();
Condition waitCondition = lock.newCondition();
while ((deadline-currentTime)>0) {
try {
lock.lockInterruptibly();
waitCondition.await(deadline-currentTime, TimeUnit.MILLISECONDS);
} catch (InterruptedException e) {
Thread.currentThread().interrupt();
return;
} finally {
lock.unlock();
}
currentTime = System.currentTimeMillis();
}
}
}
放置你的线程。睡在一个尝试捕捉块
try {
//thread to sleep for the specified number of milliseconds
Thread.sleep(100);
} catch ( java.lang.InterruptedException ie) {
System.out.println(ie);
}
一种更简单的等待方法是使用System.currentTimeMillis(),它返回自UTC 1970年1月1日午夜以来的毫秒数。例如,等待5秒:
public static void main(String[] args) {
//some code
long original = System.currentTimeMillis();
while (true) {
if (System.currentTimeMillis - original >= 5000) {
break;
}
}
//more code after waiting
}
这样,您就不必处理线程和异常。 希望这能有所帮助!
或者,如果你不想处理线程,试试这个方法:
public static void pause(int seconds){
Date start = new Date();
Date end = new Date();
while(end.getTime() - start.getTime() < seconds * 1000){
end = new Date();
}
}
它在您调用它时开始,在秒数过去时结束。