以下是我的解决方案：jsfiddle

下面的方法返回一个包含给定URL参数的字典。如果没有参数，则为空。

function getParams(url){
    var paramsStart = url.indexOf('?');
    var params = null;

    //no params available
    if(paramsStart != -1){
        var paramsString = url.substring(url.indexOf('?') + 1, url.length);

        //only '?' available
        if(paramsString != ""){
            var paramsPairs = paramsString.split('&');

            //preparing
            params = {};
            var empty = true;
            var index  = 0;
            var key = "";
            var val = "";

            for(i = 0, len = paramsPairs.length; i < len; i++){
                index = paramsPairs[i].indexOf('=');

                //if assignment symbol found
                if(index != -1){
                    key = paramsPairs[i].substring(0, index);
                    val = paramsPairs[i].substring(index + 1, paramsPairs[i].length);

                    if(key != "" && val != ""){

                        //extend here for decoding, integer parsing, whatever...

                        params[key] = val;

                        if(empty){
                            empty = false;
                        }
                    }                    
                }
            }

            if(empty){
                params = null;
            }
        }
    }

    return params;
}

Try

url.match(/[?&]c=([^&]*)/)[1]

var url=“www.test.com/t.html？a=1&bc=3&c=m2-m3-m4-5”；c=url.match（/[？&]c=（[^&]*）/）[1]；控制台日志（c）；

这是丹尼尔·索科洛夫斯基19年6月27日回答的改进。Regexp解释

[？&]第一个匹配的字符必须是？或&（省略ac=等参数）c=参数名称，结尾为=char（…）第一组匹配[^&]*零个或多个字符（*）不同于（^）&[1] 从匹配数组中选择第一组

简化版，已测试

function get(name){
    var r = /[?&]([^=#]+)=([^&#]*)/g,p={},match;
    while(match = r.exec(window.location)) p[match[1]] = match[2];
    return p[name];
}

用法：

var parameter=获取['parameter']

我在这里举了一个例子。但它在jQuery中。希望它能帮助其他人：

<script type="text/javascript" src="jquery.js"></script>
<script type="text/javascript" src="jquery.url.js"></script>

<!-- URL:  www.example.com/correct/?message=done&year=1990-->

<script type="text/javascript">
$(function(){
    $.url.attr('protocol')  // --> Protocol: "http"
    $.url.attr('path')          // --> host: "www.example.com"
    $.url.attr('query')         // --> path: "/correct/"
    $.url.attr('message')   // --> query: "done"
    $.url.attr('year')      // --> query: "1990"
});
</script>

以下是我所做的：

var uriParams = getSearchParameters();
alert(uriParams.c);


// background functions:

// Get object/associative array of URL parameters
function getSearchParameters () {
  var prmstr = window.location.search.substr(1);
  return prmstr !== null && prmstr !== "" ? transformToAssocArray(prmstr) : {};
}

// convert parameters from url-style string to associative array
function transformToAssocArray (prmstr) {
  var params = {},
      prmarr = prmstr.split("&");

  for (var i = 0; i < prmarr.length; i++) {
    var tmparr = prmarr[i].split("=");
    params[tmparr[0]] = tmparr[1];
  }
  return params;
}

// http:localhost:8080/path?param_1=a&param_2=b
var getParamsMap = function () {
    var params = window.location.search.split("&");
    var paramsMap = {};
    params.forEach(function (p) {
        var v = p.split("=");
        paramsMap[v[0]]=decodeURIComponent(v[1]);
    });
    return paramsMap;
};

// -----------------------

console.log(getParamsMap()["param_1"]);  // should log "a"