我有一个带有一些GET参数的URL,如下所示:

www.test.com/t.html?a=1&b=3&c=m2-m3-m4-m5 

我需要得到c的全部值。我试图读取URL,但只得到m2。如何使用JavaScript执行此操作?


当前回答

我很早以前就发现了这一点,非常简单:

function getUrlVars() {
    var vars = {};
    var parts = window.location.href.replace(/[?&]+([^=&]+)=([^&]*)/gi,    
    function(m,key,value) {
      vars[key] = value;
    });
    return vars;
  }

然后这样称呼:

var fType = getUrlVars()["type"];

其他回答

我做了一个函数来实现这一点:

var getUrlParams = function (url) {
  var params = {};
  (url + '?').split('?')[1].split('&').forEach(function (pair) {
    pair = (pair + '=').split('=').map(decodeURIComponent);
    if (pair[0].length) {
      params[pair[0]] = pair[1];
    }
  });
  return params;
};

2017年5月26日更新,这里有一个ES7实现(使用babel预设阶段0、1、2或3运行):

const getUrlParams = url => `${url}?`.split('?')[1]
  .split('&').reduce((params, pair) =>
    ((key, val) => key ? {...params, [key]: val} : params)
    (...`${pair}=`.split('=').map(decodeURIComponent)), {});

一些测试:

console.log(getUrlParams('https://google.com/foo?a=1&b=2&c')); // Will log {a: '1', b: '2', c: ''}
console.log(getUrlParams('/foo?a=1&b=2&c')); // Will log {a: '1', b: '2', c: ''}
console.log(getUrlParams('?a=1&b=2&c')); // Will log {a: '1', b: '2', c: ''}
console.log(getUrlParams('https://google.com/')); // Will log {}
console.log(getUrlParams('a=1&b=2&c')); // Will log {}

2018年3月26日更新,这里是一个Typescript实现:

const getUrlParams = (search: string) => `${search}?`
  .split('?')[1]
  .split('&')
  .reduce(
    (params: object, pair: string) => {
      const [key, value] = `${pair}=`
        .split('=')
        .map(decodeURIComponent)

      return key.length > 0 ? { ...params, [key]: value } : params
    },
    {}
  )

2019年2月13日更新,这里是一个与TypeScript 3一起使用的更新的TypeScript实现。

interface IParams { [key: string]: string }

const paramReducer = (params: IParams, pair: string): IParams => {
  const [key, value] = `${pair}=`.split('=').map(decodeURIComponent)

  return key.length > 0 ? { ...params, [key]: value } : params
}

const getUrlParams = (search: string): IParams =>
  `${search}?`.split('?')[1].split('&').reduce<IParams>(paramReducer, {})

您可以添加一个输入框,然后要求用户将值复制到其中……这非常简单:

<h1>Hey User! Can you please copy the value out of the location bar where it says like, &m=2? Thanks! And then, if you could...paste it in the box below and click the Done button?</h1>
<input type='text' id='the-url-value' />
<input type='button' value='This is the Done button. Click here after you do all that other stuff I wrote.' />

<script>
//...read the value on click

好吧,但说真的。。。我发现了这段代码,它似乎很有用:

http://www.developerdrive.com/2013/08/turning-the-querystring-into-a-json-object-using-javascript/

function queryToJSON() {
    var pairs = location.search.slice(1).split('&');

    var result = {};
    pairs.forEach(function(pair) {
        pair = pair.split('=');
        result[pair[0]] = decodeURIComponent(pair[1] || '');
    });

    return JSON.parse(JSON.stringify(result));
}

var query = queryToJSON();

这里是一个递归解决方案,它没有正则表达式,并且具有最小的变异(只有params对象被变异,我认为这在JS中是不可避免的)。

太棒了,因为它:

是递归的处理多个同名参数处理格式错误的参数字符串(缺少值等)如果“=”在值中,则不中断执行URL解码最后,这太棒了,因为它……啊!!!

代码:

var get_params = function(search_string) {

  var parse = function(params, pairs) {
    var pair = pairs[0];
    var parts = pair.split('=');
    var key = decodeURIComponent(parts[0]);
    var value = decodeURIComponent(parts.slice(1).join('='));

    // Handle multiple parameters of the same name
    if (typeof params[key] === "undefined") {
      params[key] = value;
    } else {
      params[key] = [].concat(params[key], value);
    }

    return pairs.length == 1 ? params : parse(params, pairs.slice(1))
  }

  // Get rid of leading ?
  return search_string.length == 0 ? {} : parse({}, search_string.substr(1).split('&'));
}

var params = get_params(location.search);

// Finally, to get the param you want
params['c'];

对于像index.html这样的单参数值?msg=1使用以下代码,

$(window).load(function(){
    queryString();
});

function queryString()
{
    var queryString = window.location.search.substring(1);
    var varArray = queryString.split("="); //eg. index.html?msg=1

    var param1 = varArray[0];
    var param2 = varArray[1];

}

对于所有参数值,请使用以下代码:,

$(window).load(function(){
    queryString();
});

function queryString()
{
    var queryString = window.location.search;
    var varArray = queryString.split("&");
    for (var i=0;i<varArray.length;i++) {
      var param = varArray[i].split("=");
        //parameter-value pair
    }
} 

我的解决方案:

/**
 * get object with params from query of url
 */
const getParams = (url) => {
  const params = {};
  const parser = document.createElement('a');
  parser.href = url;
  const query = parser.search.substring(1);
  if (query !== '') {
    const vars = query.split('&');
    for (let i = 0; i < vars.length; i++) {
      const pair = vars[i].split('=');
      const key = decodeURIComponent(pair[0]).replace('[]', '');
      const value = decodeURIComponent(pair[1]);
      
      if (key in params) {
        if (Array.isArray(params[key])) {
          params[key].push(value);
        } else {
          params[key] = [params[key]];
          params[key].push(value);
        }
      } else params[key] = value;
    }
  }
  return params;
}