我需要在Java中连接两个字符串数组。

void f(String[] first, String[] second) {
    String[] both = ???
}

哪种方法最简单?


当前回答

Object[] mixArray(String[] a, String[] b)
String[] s1 = a;
String[] s2 = b;
Object[] result;
List<String> input = new ArrayList<String>();
for (int i = 0; i < s1.length; i++)
{
    input.add(s1[i]);
}
for (int i = 0; i < s2.length; i++)
{
    input.add(s2[i]);
}
result = input.toArray();
return result;

其他回答

只是想添加,您也可以使用System.arraycopy:

import static java.lang.System.out;
import static java.lang.System.arraycopy;
import java.lang.reflect.Array;
class Playground {
    @SuppressWarnings("unchecked")
    public static <T>T[] combineArrays(T[] a1, T[] a2) {
        T[] result = (T[]) Array.newInstance(a1.getClass().getComponentType(), a1.length+a2.length);
        arraycopy(a1,0,result,0,a1.length);
        arraycopy(a2,0,result,a1.length,a2.length);
        return result;
    }
    public static void main(String[ ] args) {
        String monthsString = "JANFEBMARAPRMAYJUNJULAUGSEPOCTNOVDEC";
        String[] months = monthsString.split("(?<=\\G.{3})");
        String daysString = "SUNMONTUEWEDTHUFRISAT";
        String[] days = daysString.split("(?<=\\G.{3})");
        for (String m : months) {
            out.println(m);
        }
        out.println("===");
         for (String d : days) {
            out.println(d);
        }
        out.println("===");
        String[] results = combineArrays(months, days);
        for (String r : results) {
            out.println(r);
        }
        out.println("===");
    }
}

FunctionalJava库有一个数组包装器类,它为数组提供了方便的方法,如串联。

import static fj.data.Array.array;

…然后

Array<String> both = array(first).append(array(second));

要取回展开的数组,请调用

String[] s = both.array();

另一种思考问题的方式。要连接两个或多个数组,必须列出每个数组的所有元素,然后构建一个新数组。这听起来像是创建一个List<T>,然后调用它上的Array。其他一些答案使用ArrayList,这很好。但如何实现我们自己的呢?这并不难:

private static <T> T[] addAll(final T[] f, final T...o){
    return new AbstractList<T>(){

        @Override
        public T get(int i) {
            return i>=f.length ? o[i - f.length] : f[i];
        }

        @Override
        public int size() {
            return f.length + o.length;
        }

    }.toArray(f);
}

我相信上面的解决方案相当于使用System.arraycopy的解决方案。然而,我认为这个解决方案有其自身的优点。

这是字符串数组的转换函数:

public String[] mergeArrays(String[] mainArray, String[] addArray) {
    String[] finalArray = new String[mainArray.length + addArray.length];
    System.arraycopy(mainArray, 0, finalArray, 0, mainArray.length);
    System.arraycopy(addArray, 0, finalArray, mainArray.length, addArray.length);

    return finalArray;
}

这是可行的,但您需要插入自己的错误检查。

public class StringConcatenate {

    public static void main(String[] args){

        // Create two arrays to concatenate and one array to hold both
        String[] arr1 = new String[]{"s","t","r","i","n","g"};
        String[] arr2 = new String[]{"s","t","r","i","n","g"};
        String[] arrBoth = new String[arr1.length+arr2.length];

        // Copy elements from first array into first part of new array
        for(int i = 0; i < arr1.length; i++){
            arrBoth[i] = arr1[i];
        }

        // Copy elements from second array into last part of new array
        for(int j = arr1.length;j < arrBoth.length;j++){
            arrBoth[j] = arr2[j-arr1.length];
        }

        // Print result
        for(int k = 0; k < arrBoth.length; k++){
            System.out.print(arrBoth[k]);
        }

        // Additional line to make your terminal look better at completion!
        System.out.println();
    }
}

它可能不是最有效的,但除了Java自己的API之外,它不依赖其他任何东西。