我如何以易于阅读(供人类阅读)的格式显示JSON?我主要寻找缩进和空白,甚至是颜色/字体样式等。
当前回答
var jsonObj = {"streetLabel": "Avenue Anatole France", "city": "Paris 07", "postalCode": "75007", "countryCode": "FRA", "countryLabel": "France" };
document.getElementById("result-before").innerHTML = JSON.stringify(jsonObj);
如果以HTML显示,则应添加应答器<pre></pre>
document.getElementById("result-after").innerHTML = "<pre>"+JSON.stringify(jsonObj,undefined, 2) +"</pre>"
例子:
var jsonObj={“streetLabel”:“Avenue Anatole France”,“city”:“Paris 07”,“postalCode”:“75007”;document.getElementById(“result before”).innerHTML=JSON.stringfy(jsonObj);document.getElementById(“resultafter”).innerHTML=“<pre>”+JSON.stringify(jsonObj,未定义,2)+“</pre>”div{float:left;clear:both;margin:1em 0;}<div id=“result before”></div><div id=“result after”></div>
其他回答
对Ruby的其他漂亮打印机不满意,我自己编写了(NeatJSON),然后将其移植到JavaScript,包括一个免费的在线格式化程序。该代码在MIT许可证下是免费的(相当宽松)。
功能(全部可选):
设置线宽并换行,使对象和数组在合适时保持在同一行上,否则每行换行一个值。如果愿意,对对象关键点排序。对齐对象关键点(对齐冒号)。将浮点数格式化为特定的小数位数,而不打乱整数。“短”换行模式将左括号和右括号/大括号与值放在同一行,提供一些人更喜欢的格式。对数组和对象的间距、括号之间、冒号和逗号之前/之后进行精细控制。函数可用于web浏览器和Node.js。
我将在这里复制源代码,这样这不仅仅是一个库的链接,但我鼓励您转到GitHub项目页面,因为它将保持最新,而下面的代码不会。
(function(exports){
exports.neatJSON = neatJSON;
function neatJSON(value,opts){
opts = opts || {}
if (!('wrap' in opts)) opts.wrap = 80;
if (opts.wrap==true) opts.wrap = -1;
if (!('indent' in opts)) opts.indent = ' ';
if (!('arrayPadding' in opts)) opts.arrayPadding = ('padding' in opts) ? opts.padding : 0;
if (!('objectPadding' in opts)) opts.objectPadding = ('padding' in opts) ? opts.padding : 0;
if (!('afterComma' in opts)) opts.afterComma = ('aroundComma' in opts) ? opts.aroundComma : 0;
if (!('beforeComma' in opts)) opts.beforeComma = ('aroundComma' in opts) ? opts.aroundComma : 0;
if (!('afterColon' in opts)) opts.afterColon = ('aroundColon' in opts) ? opts.aroundColon : 0;
if (!('beforeColon' in opts)) opts.beforeColon = ('aroundColon' in opts) ? opts.aroundColon : 0;
var apad = repeat(' ',opts.arrayPadding),
opad = repeat(' ',opts.objectPadding),
comma = repeat(' ',opts.beforeComma)+','+repeat(' ',opts.afterComma),
colon = repeat(' ',opts.beforeColon)+':'+repeat(' ',opts.afterColon);
return build(value,'');
function build(o,indent){
if (o===null || o===undefined) return indent+'null';
else{
switch(o.constructor){
case Number:
var isFloat = (o === +o && o !== (o|0));
return indent + ((isFloat && ('decimals' in opts)) ? o.toFixed(opts.decimals) : (o+''));
case Array:
var pieces = o.map(function(v){ return build(v,'') });
var oneLine = indent+'['+apad+pieces.join(comma)+apad+']';
if (opts.wrap===false || oneLine.length<=opts.wrap) return oneLine;
if (opts.short){
var indent2 = indent+' '+apad;
pieces = o.map(function(v){ return build(v,indent2) });
pieces[0] = pieces[0].replace(indent2,indent+'['+apad);
pieces[pieces.length-1] = pieces[pieces.length-1]+apad+']';
return pieces.join(',\n');
}else{
var indent2 = indent+opts.indent;
return indent+'[\n'+o.map(function(v){ return build(v,indent2) }).join(',\n')+'\n'+indent+']';
}
case Object:
var keyvals=[],i=0;
for (var k in o) keyvals[i++] = [JSON.stringify(k), build(o[k],'')];
if (opts.sorted) keyvals = keyvals.sort(function(kv1,kv2){ kv1=kv1[0]; kv2=kv2[0]; return kv1<kv2?-1:kv1>kv2?1:0 });
keyvals = keyvals.map(function(kv){ return kv.join(colon) }).join(comma);
var oneLine = indent+"{"+opad+keyvals+opad+"}";
if (opts.wrap===false || oneLine.length<opts.wrap) return oneLine;
if (opts.short){
var keyvals=[],i=0;
for (var k in o) keyvals[i++] = [indent+' '+opad+JSON.stringify(k),o[k]];
if (opts.sorted) keyvals = keyvals.sort(function(kv1,kv2){ kv1=kv1[0]; kv2=kv2[0]; return kv1<kv2?-1:kv1>kv2?1:0 });
keyvals[0][0] = keyvals[0][0].replace(indent+' ',indent+'{');
if (opts.aligned){
var longest = 0;
for (var i=keyvals.length;i--;) if (keyvals[i][0].length>longest) longest = keyvals[i][0].length;
var padding = repeat(' ',longest);
for (var i=keyvals.length;i--;) keyvals[i][0] = padRight(padding,keyvals[i][0]);
}
for (var i=keyvals.length;i--;){
var k=keyvals[i][0], v=keyvals[i][1];
var indent2 = repeat(' ',(k+colon).length);
var oneLine = k+colon+build(v,'');
keyvals[i] = (opts.wrap===false || oneLine.length<=opts.wrap || !v || typeof v!="object") ? oneLine : (k+colon+build(v,indent2).replace(/^\s+/,''));
}
return keyvals.join(',\n') + opad + '}';
}else{
var keyvals=[],i=0;
for (var k in o) keyvals[i++] = [indent+opts.indent+JSON.stringify(k),o[k]];
if (opts.sorted) keyvals = keyvals.sort(function(kv1,kv2){ kv1=kv1[0]; kv2=kv2[0]; return kv1<kv2?-1:kv1>kv2?1:0 });
if (opts.aligned){
var longest = 0;
for (var i=keyvals.length;i--;) if (keyvals[i][0].length>longest) longest = keyvals[i][0].length;
var padding = repeat(' ',longest);
for (var i=keyvals.length;i--;) keyvals[i][0] = padRight(padding,keyvals[i][0]);
}
var indent2 = indent+opts.indent;
for (var i=keyvals.length;i--;){
var k=keyvals[i][0], v=keyvals[i][1];
var oneLine = k+colon+build(v,'');
keyvals[i] = (opts.wrap===false || oneLine.length<=opts.wrap || !v || typeof v!="object") ? oneLine : (k+colon+build(v,indent2).replace(/^\s+/,''));
}
return indent+'{\n'+keyvals.join(',\n')+'\n'+indent+'}'
}
default:
return indent+JSON.stringify(o);
}
}
}
function repeat(str,times){ // http://stackoverflow.com/a/17800645/405017
var result = '';
while(true){
if (times & 1) result += str;
times >>= 1;
if (times) str += str;
else break;
}
return result;
}
function padRight(pad, str){
return (str + pad).substring(0, pad.length);
}
}
neatJSON.version = "0.5";
})(typeof exports === 'undefined' ? this : exports);
我今天遇到了@Pumbaa80的代码问题。我试图将JSON语法高亮显示应用于我在Mithril视图中呈现的数据,因此我需要为JSON.stringify输出中的所有内容创建DOM节点。
我还将非常长的正则表达式拆分为其组成部分。
render_json = (data) ->
# wraps JSON data in span elements so that syntax highlighting may be
# applied. Should be placed in a `whitespace: pre` context
if typeof(data) isnt 'string'
data = JSON.stringify(data, undefined, 2)
unicode = /"(\\u[a-zA-Z0-9]{4}|\\[^u]|[^\\"])*"(\s*:)?/
keyword = /\b(true|false|null)\b/
whitespace = /\s+/
punctuation = /[,.}{\[\]]/
number = /-?\d+(?:\.\d*)?(?:[eE][+\-]?\d+)?/
syntax = '(' + [unicode, keyword, whitespace,
punctuation, number].map((r) -> r.source).join('|') + ')'
parser = new RegExp(syntax, 'g')
nodes = data.match(parser) ? []
select_class = (node) ->
if punctuation.test(node)
return 'punctuation'
if /^\s+$/.test(node)
return 'whitespace'
if /^\"/.test(node)
if /:$/.test(node)
return 'key'
return 'string'
if /true|false/.test(node)
return 'boolean'
if /null/.test(node)
return 'null'
return 'number'
return nodes.map (node) ->
cls = select_class(node)
return Mithril('span', {class: cls}, node)
此处为Github上的上下文代码
这是user123444555621的很棒的HTML,适合终端。易于调试节点脚本:
function prettyJ(json) {
if (typeof json !== 'string') {
json = JSON.stringify(json, undefined, 2);
}
return json.replace(/("(\\u[a-zA-Z0-9]{4}|\\[^u]|[^\\"])*"(\s*:)?|\b(true|false|null)\b|-?\d+(?:\.\d*)?(?:[eE][+\-]?\d+)?)/g,
function (match) {
let cls = "\x1b[36m";
if (/^"/.test(match)) {
if (/:$/.test(match)) {
cls = "\x1b[34m";
} else {
cls = "\x1b[32m";
}
} else if (/true|false/.test(match)) {
cls = "\x1b[35m";
} else if (/null/.test(match)) {
cls = "\x1b[31m";
}
return cls + match + "\x1b[0m";
}
);
}
用法:
// thing = any json OR string of json
prettyJ(thing);
我想在这里展示我的jsonAnalyze方法,它只打印了JSON结构,但在某些情况下,打印整个JSON会更有用。
假设您有这样一个复杂的JSON:
let theJson = {
'username': 'elen',
'email': 'elen@test.com',
'state': 'married',
'profiles': [
{'name': 'elenLove', 'job': 'actor' },
{'name': 'elenDoe', 'job': 'spy'}
],
'hobbies': ['run', 'movies'],
'status': {
'home': {
'ownsHome': true,
'addresses': [
{'town': 'Mexico', 'address': '123 mexicoStr'},
{'town': 'Atlanta', 'address': '4B atlanta 45-48'},
]
},
'car': {
'ownsCar': true,
'cars': [
{'brand': 'Nissan', 'plate': 'TOKY-114', 'prevOwnersIDs': ['4532354531', '3454655344', '5566753422']},
{'brand': 'Benz', 'plate': 'ELEN-1225', 'prevOwnersIDs': ['4531124531', '97864655344', '887666753422']}
]
}
},
'active': true,
'employed': false,
};
然后该方法将返回如下结构:
username
email
state
profiles[]
profiles[].name
profiles[].job
hobbies[]
status{}
status{}.home{}
status{}.home{}.ownsHome
status{}.home{}.addresses[]
status{}.home{}.addresses[].town
status{}.home{}.addresses[].address
status{}.car{}
status{}.car{}.ownsCar
status{}.car{}.cars[]
status{}.car{}.cars[].brand
status{}.car{}.cars[].plate
status{}.car{}.cars[].prevOwnersIDs[]
active
employed
这是jsonAnalysis()代码:
function jsonAnalyze(obj) {
let arr = [];
analyzeJson(obj, null, arr);
return logBeautifiedDotNotation(arr);
function analyzeJson(obj, parentStr, outArr) {
let opt;
if (!outArr) {
return "no output array given"
}
for (let prop in obj) {
opt = parentStr ? parentStr + '.' + prop : prop;
if (Array.isArray(obj[prop]) && obj[prop] !== null) {
let arr = obj[prop];
if ((Array.isArray(arr[0]) || typeof arr[0] == "object") && arr[0] != null) {
outArr.push(opt + '[]');
analyzeJson(arr[0], opt + '[]', outArr);
} else {
outArr.push(opt + '[]');
}
} else if (typeof obj[prop] == "object" && obj[prop] !== null) {
outArr.push(opt + '{}');
analyzeJson(obj[prop], opt + '{}', outArr);
} else {
if (obj.hasOwnProperty(prop) && typeof obj[prop] != 'function') {
outArr.push(opt);
}
}
}
}
function logBeautifiedDotNotation(arr) {
retStr = '';
arr.map(function (item) {
let dotsAmount = item.split(".").length - 1;
let dotsString = Array(dotsAmount + 1).join(' ');
retStr += dotsString + item + '\n';
console.log(dotsString + item)
});
return retStr;
}
}
jsonAnalyze(theJson);
1行代码(无颜色)中的快速易读JSON输出:
document.documentElement.innerHTML='<pre>'+JSON.stringify(obj, null, 2)+'</pre>';
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