我如何以易于阅读(供人类阅读)的格式显示JSON?我主要寻找缩进和空白,甚至是颜色/字体样式等。
当前回答
以下是如何在不使用本机函数的情况下打印。
function pretty(ob, lvl = 0) {
let temp = [];
if(typeof ob === "object"){
for(let x in ob) {
if(ob.hasOwnProperty(x)) {
temp.push( getTabs(lvl+1) + x + ":" + pretty(ob[x], lvl+1) );
}
}
return "{\n"+ temp.join(",\n") +"\n" + getTabs(lvl) + "}";
}
else {
return ob;
}
}
function getTabs(n) {
let c = 0, res = "";
while(c++ < n)
res+="\t";
return res;
}
let obj = {a: {b: 2}, x: {y: 3}};
console.log(pretty(obj));
/*
{
a: {
b: 2
},
x: {
y: 3
}
}
*/
其他回答
这是user123444555621的很棒的HTML,适合终端。易于调试节点脚本:
function prettyJ(json) {
if (typeof json !== 'string') {
json = JSON.stringify(json, undefined, 2);
}
return json.replace(/("(\\u[a-zA-Z0-9]{4}|\\[^u]|[^\\"])*"(\s*:)?|\b(true|false|null)\b|-?\d+(?:\.\d*)?(?:[eE][+\-]?\d+)?)/g,
function (match) {
let cls = "\x1b[36m";
if (/^"/.test(match)) {
if (/:$/.test(match)) {
cls = "\x1b[34m";
} else {
cls = "\x1b[32m";
}
} else if (/true|false/.test(match)) {
cls = "\x1b[35m";
} else if (/null/.test(match)) {
cls = "\x1b[31m";
}
return cls + match + "\x1b[0m";
}
);
}
用法:
// thing = any json OR string of json
prettyJ(thing);
以下是如何在不使用本机函数的情况下打印。
function pretty(ob, lvl = 0) {
let temp = [];
if(typeof ob === "object"){
for(let x in ob) {
if(ob.hasOwnProperty(x)) {
temp.push( getTabs(lvl+1) + x + ":" + pretty(ob[x], lvl+1) );
}
}
return "{\n"+ temp.join(",\n") +"\n" + getTabs(lvl) + "}";
}
else {
return ob;
}
}
function getTabs(n) {
let c = 0, res = "";
while(c++ < n)
res+="\t";
return res;
}
let obj = {a: {b: 2}, x: {y: 3}};
console.log(pretty(obj));
/*
{
a: {
b: 2
},
x: {
y: 3
}
}
*/
要使用Bootstrap在HTML中突出显示和美化它,请执行以下操作:
function prettifyJson(json, prettify) {
if (typeof json !== 'string') {
if (prettify) {
json = JSON.stringify(json, undefined, 4);
} else {
json = JSON.stringify(json);
}
}
return json.replace(/("(\\u[a-zA-Z0-9]{4}|\\[^u]|[^\\"])*"(\s*:)?|\b(true|false|null)\b|-?\d+(?:\.\d*)?(?:[eE][+\-]?\d+)?)/g,
function(match) {
let cls = "<span>";
if (/^"/.test(match)) {
if (/:$/.test(match)) {
cls = "<span class='text-danger'>";
} else {
cls = "<span>";
}
} else if (/true|false/.test(match)) {
cls = "<span class='text-primary'>";
} else if (/null/.test(match)) {
cls = "<span class='text-info'>";
}
return cls + match + "</span>";
}
);
}
更好的方法。
用Javascript美化JSON数组
JSON.stringify(jsonobj,null,'\t')
我想在这里展示我的jsonAnalyze方法,它只打印了JSON结构,但在某些情况下,打印整个JSON会更有用。
假设您有这样一个复杂的JSON:
let theJson = {
'username': 'elen',
'email': 'elen@test.com',
'state': 'married',
'profiles': [
{'name': 'elenLove', 'job': 'actor' },
{'name': 'elenDoe', 'job': 'spy'}
],
'hobbies': ['run', 'movies'],
'status': {
'home': {
'ownsHome': true,
'addresses': [
{'town': 'Mexico', 'address': '123 mexicoStr'},
{'town': 'Atlanta', 'address': '4B atlanta 45-48'},
]
},
'car': {
'ownsCar': true,
'cars': [
{'brand': 'Nissan', 'plate': 'TOKY-114', 'prevOwnersIDs': ['4532354531', '3454655344', '5566753422']},
{'brand': 'Benz', 'plate': 'ELEN-1225', 'prevOwnersIDs': ['4531124531', '97864655344', '887666753422']}
]
}
},
'active': true,
'employed': false,
};
然后该方法将返回如下结构:
username
email
state
profiles[]
profiles[].name
profiles[].job
hobbies[]
status{}
status{}.home{}
status{}.home{}.ownsHome
status{}.home{}.addresses[]
status{}.home{}.addresses[].town
status{}.home{}.addresses[].address
status{}.car{}
status{}.car{}.ownsCar
status{}.car{}.cars[]
status{}.car{}.cars[].brand
status{}.car{}.cars[].plate
status{}.car{}.cars[].prevOwnersIDs[]
active
employed
这是jsonAnalysis()代码:
function jsonAnalyze(obj) {
let arr = [];
analyzeJson(obj, null, arr);
return logBeautifiedDotNotation(arr);
function analyzeJson(obj, parentStr, outArr) {
let opt;
if (!outArr) {
return "no output array given"
}
for (let prop in obj) {
opt = parentStr ? parentStr + '.' + prop : prop;
if (Array.isArray(obj[prop]) && obj[prop] !== null) {
let arr = obj[prop];
if ((Array.isArray(arr[0]) || typeof arr[0] == "object") && arr[0] != null) {
outArr.push(opt + '[]');
analyzeJson(arr[0], opt + '[]', outArr);
} else {
outArr.push(opt + '[]');
}
} else if (typeof obj[prop] == "object" && obj[prop] !== null) {
outArr.push(opt + '{}');
analyzeJson(obj[prop], opt + '{}', outArr);
} else {
if (obj.hasOwnProperty(prop) && typeof obj[prop] != 'function') {
outArr.push(opt);
}
}
}
}
function logBeautifiedDotNotation(arr) {
retStr = '';
arr.map(function (item) {
let dotsAmount = item.split(".").length - 1;
let dotsString = Array(dotsAmount + 1).join(' ');
retStr += dotsString + item + '\n';
console.log(dotsString + item)
});
return retStr;
}
}
jsonAnalyze(theJson);