我如何打印(到控制台)的Id,标题,名称等,这个结构在Golang?

type Project struct {
    Id      int64   `json:"project_id"`
    Title   string  `json:"title"`
    Name    string  `json:"name"`
    Data    Data    `json:"data"`
    Commits Commits `json:"commits"`
}

当前回答

我想推荐Go -spew,根据他们的github“为Go数据结构实现了一个深度漂亮的打印机,以帮助调试”

go get -u github.com/davecgh/go-spew/spew

使用的例子:

package main

import (
    "github.com/davecgh/go-spew/spew"
)

type Project struct {
    Id      int64  `json:"project_id"`
    Title   string `json:"title"`
    Name    string `json:"name"`
    Data    string `json:"data"`
    Commits string `json:"commits"`
}

func main() {

    o := Project{Name: "hello", Title: "world"}
    spew.Dump(o)
}

输出:

(main.Project) {
 Id: (int64) 0,
 Title: (string) (len=5) "world",
 Name: (string) (len=5) "hello",
 Data: (string) "",
 Commits: (string) ""
}

其他回答

我建议你使用fmt。Printf("%#v\n", s),它将打印golang类型在同一时间

package main

import (
    "fmt"
    "testing"
)

type student struct {
    id   int32
    name string
}

type Project struct {
    Id      int64   `json:"project_id"`
    Title   string  `json:"title"`
    Name    string  `json:"name"`
}

func TestPrint(t *testing.T) {
    s := Project{1, "title","jack"}
    fmt.Printf("%+v\n", s)
    fmt.Printf("%#v\n", s)
}

结果:

{Id:1 Title:title Name:jack}
main.Project{Id:1, Title:"title", Name:"jack"}

还有go-render,它处理指针递归和字符串和int映射的大量键排序。

安装:

go get github.com/luci/go-render/render

例子:

type customType int
type testStruct struct {
        S string
        V *map[string]int
        I interface{}
}

a := testStruct{
        S: "hello",
        V: &map[string]int{"foo": 0, "bar": 1},
        I: customType(42),
}

fmt.Println("Render test:")
fmt.Printf("fmt.Printf:    %#v\n", a)))
fmt.Printf("render.Render: %s\n", Render(a))

打印:

fmt.Printf:    render.testStruct{S:"hello", V:(*map[string]int)(0x600dd065), I:42}
render.Render: render.testStruct{S:"hello", V:(*map[string]int){"bar":1, "foo":0}, I:render.customType(42)}

我推荐使用Pretty Printer Library。这样你可以很容易地打印任何结构体。

安装库 https://github.com/kr/pretty

or

go get github.com/kr/pretty

现在在代码中这样做

package main

import (
fmt
github.com/kr/pretty
)

func main(){

type Project struct {
    Id int64 `json:"project_id"`
    Title string `json:"title"`
    Name string `json:"name"`
    Data Data `json:"data"`
    Commits Commits `json:"commits"`
}

fmt.Printf("%# v", pretty.Formatter(Project)) //It will print all struct details

fmt.Printf("%# v", pretty.Formatter(Project.Id)) //It will print component one by one.

}

此外,您还可以通过这个库获取组件之间的差异等等。你也可以在这里查看图书馆文档。

    type Response struct {
        UserId int    `json:"userId"`
        Id     int    `json:"id"`
        Title  string `json:"title"`
        Body   string `json:"body"`
    }

    func PostsGet() gin.HandlerFunc {
        return func(c *gin.Context) {
            xs, err := http.Get("https://jsonplaceholder.typicode.com/posts")
            if err != nil {
                log.Println("The HTTP request failed with error: ", err)
            }
            data, _ := ioutil.ReadAll(xs`enter code here`.Body)


            // this will print the struct in console            
            fmt.Println(string(data))


            // this is to send as response for the API
            bytes := []byte(string(data))
            var res []Response
            json.Unmarshal(bytes, &res)

            c.JSON(http.StatusOK, res)
        }
    }

我建议使用json.Unmarshal() 我试着打印id,希望它有帮助:

var jsonString = `{"Id": 1, "Title": "the title", "Name": "the name","Data": "the data","Commits" : "the commits"}`
var jsonData = []byte(jsonString)

var data Project

var err = json.Unmarshal(jsonData, &data)
if err != nil {
    fmt.Println(err.Error())
    return
}

fmt.Println("Id :", data.Id)