isJsonString('{ "Id": 1, "Name": "Coke" }')

应该是正确的

isJsonString('foo')
isJsonString('<div>foo</div>')

应该为假。

我正在寻找一种不使用try/catch的解决方案,因为我将调试器设置为“在所有错误上中断”,这导致它在无效的JSON字符串上中断。


当前回答

对于喜欢. net惯例中的“try”函数,它返回一个布尔值并处理一个包含结果的byref参数。如果不需要out参数,可以省略它,只使用返回值。

StringTests.js

  var obj1 = {};
  var bool1 = '{"h":"happy"}'.tryParse(obj1); // false
  var obj2 = {};
  var bool2 = '2114509 GOODLUCKBUDDY 315852'.tryParse(obj2);  // false

  var obj3 = {};
  if('{"house_number":"1","road":"Mauchly","city":"Irvine","county":"Orange County","state":"California","postcode":"92618","country":"United States of America","country_code":"us"}'.tryParse(obj3))
    console.log(obj3);

StringUtils.js

String.prototype.tryParse = function(jsonObject) {
  jsonObject = jsonObject || {};
  try {
    if(!/^[\[{]/.test(this) || !/[}\]]$/.test(this)) // begin / end with [] or {}
      return false; // avoid error handling for strings that obviously aren't json
    var json = JSON.parse(this);
    if(typeof json === 'object'){
      jsonObject.merge(json);
      return true;
    }
  } catch (e) {
    return false;
  }
}

ObjectUtils.js

Object.defineProperty(Object.prototype, 'merge', {
  value: function(mergeObj){
    for (var propertyName in mergeObj) {
      if (mergeObj.hasOwnProperty(propertyName)) {
        this[propertyName] = mergeObj[propertyName];
      }      
    }
    return this;
  },
  enumerable: false, // this is actually the default
});

其他回答

function get_json(txt)
{  var data

   try     {  data = eval('('+txt+')'); }
   catch(e){  data = false;             }

   return data;
}

如果有错误,返回false。

如果没有错误,则返回json数据

如果你有疑问,值是或不是json

  function isStringified(jsonValue) { // use this function to check
   try {
    console.log("need to parse");
    return JSON.parse(jsonValue);
   } catch (err) {
    console.log("not need to parse");

     return jsonValue; 
    }
  }

然后

  const json = isStringified(stringValue);

  if (typeof json == "object") {
      console.log("string is a valid json")
    }else{
      console.log("string is not a valid json")
    }

下面是我的工作代码:

function IsJsonString(str) {
  try {
    var json = JSON.parse(str);
    return (typeof json === 'object');
  } catch (e) {
    return false;
  }
}

下面是typescript版本:

JSONTryParse(input: any) {
    try {
        //check if the string exists
        if (input) {
            var o = JSON.parse(input);

            //validate the result too
            if (o && o.constructor === Object) {
                return o;
            }
        }
    }
    catch (e: any) {
    }

    return false;
};

对于喜欢. net惯例中的“try”函数,它返回一个布尔值并处理一个包含结果的byref参数。如果不需要out参数,可以省略它,只使用返回值。

StringTests.js

  var obj1 = {};
  var bool1 = '{"h":"happy"}'.tryParse(obj1); // false
  var obj2 = {};
  var bool2 = '2114509 GOODLUCKBUDDY 315852'.tryParse(obj2);  // false

  var obj3 = {};
  if('{"house_number":"1","road":"Mauchly","city":"Irvine","county":"Orange County","state":"California","postcode":"92618","country":"United States of America","country_code":"us"}'.tryParse(obj3))
    console.log(obj3);

StringUtils.js

String.prototype.tryParse = function(jsonObject) {
  jsonObject = jsonObject || {};
  try {
    if(!/^[\[{]/.test(this) || !/[}\]]$/.test(this)) // begin / end with [] or {}
      return false; // avoid error handling for strings that obviously aren't json
    var json = JSON.parse(this);
    if(typeof json === 'object'){
      jsonObject.merge(json);
      return true;
    }
  } catch (e) {
    return false;
  }
}

ObjectUtils.js

Object.defineProperty(Object.prototype, 'merge', {
  value: function(mergeObj){
    for (var propertyName in mergeObj) {
      if (mergeObj.hasOwnProperty(propertyName)) {
        this[propertyName] = mergeObj[propertyName];
      }      
    }
    return this;
  },
  enumerable: false, // this is actually the default
});