这是一个更灵活的算法舍入到N位有效数字

Swift 3解决方案

extension Double {
// Rounds the double to 'places' significant digits
  func roundTo(places:Int) -> Double {
    guard self != 0.0 else {
        return 0
    }
    let divisor = pow(10.0, Double(places) - ceil(log10(fabs(self))))
    return (self * divisor).rounded() / divisor
  }
}


// Double(0.123456789).roundTo(places: 2) = 0.12
// Double(1.23456789).roundTo(places: 2) = 1.2
// Double(1234.56789).roundTo(places: 2) = 1200

基于Yogi的回答，这里有一个Swift函数来完成这项工作:

func roundToPlaces(value:Double, places:Int) -> Double {
    let divisor = pow(10.0, Double(places))
    return round(value * divisor) / divisor
}

这是一个完整的代码

Swift 3.0/4.0/5.0, Xcode 9.0 GM/9.2及以上

let doubleValue : Double = 123.32565254455
self.lblValue.text = String(format:"%.f", doubleValue)
print(self.lblValue.text)

输出- 123

let doubleValue : Double = 123.32565254455
self.lblValue_1.text = String(format:"%.1f", doubleValue)
print(self.lblValue_1.text)

输出- 123.3

let doubleValue : Double = 123.32565254455
self.lblValue_2.text = String(format:"%.2f", doubleValue)
print(self.lblValue_2.text)

输出- 123.33

let doubleValue : Double = 123.32565254455
self.lblValue_3.text = String(format:"%.3f", doubleValue)
print(self.lblValue_3.text)

输出- 123.326

Swift 4, Xcode 10

yourLabel.text =  String(format:"%.2f", yourDecimalValue)

:

Using String(format:): Typecast Double to String with %.3f format specifier and then back to Double Double(String(format: "%.3f", 10.123546789))! Or extend Double to handle N-Decimal places: extension Double { func rounded(toDecimalPlaces n: Int) -> Double { return Double(String(format: "%.\(n)f", self))! } } By calculation multiply with 10^3, round it and then divide by 10^3... (1000 * 10.123546789).rounded()/1000 Or extend Double to handle N-Decimal places: extension Double { func rounded(toDecimalPlaces n: Int) -> Double { let multiplier = pow(10, Double(n)) return (multiplier * self).rounded()/multiplier } }

一个方便的方法是使用Double类型的扩展

extension Double {
    var roundTo2f: Double {return Double(round(100 *self)/100)  }
    var roundTo3f: Double {return Double(round(1000*self)/1000) }
}

用法:

let regularPie:  Double = 3.14159
var smallerPie:  Double = regularPie.roundTo3f  // results 3.142
var smallestPie: Double = regularPie.roundTo2f  // results 3.14